Switching Orders of Differentiation and Integration in case of Function of 2 Variables
$begingroup$
I encountered the following equation in my calculus lecture notes:
$$
frac{d}{dx}int_0^xf(x,y)dy = f(x,x)+int_0^xfrac{partial f}{partial x}(x,y)dy
$$
Could you show me how to prove the above equality?
multivariable-calculus
$endgroup$
add a comment |
$begingroup$
I encountered the following equation in my calculus lecture notes:
$$
frac{d}{dx}int_0^xf(x,y)dy = f(x,x)+int_0^xfrac{partial f}{partial x}(x,y)dy
$$
Could you show me how to prove the above equality?
multivariable-calculus
$endgroup$
add a comment |
$begingroup$
I encountered the following equation in my calculus lecture notes:
$$
frac{d}{dx}int_0^xf(x,y)dy = f(x,x)+int_0^xfrac{partial f}{partial x}(x,y)dy
$$
Could you show me how to prove the above equality?
multivariable-calculus
$endgroup$
I encountered the following equation in my calculus lecture notes:
$$
frac{d}{dx}int_0^xf(x,y)dy = f(x,x)+int_0^xfrac{partial f}{partial x}(x,y)dy
$$
Could you show me how to prove the above equality?
multivariable-calculus
multivariable-calculus
asked Jan 25 at 17:39
A Slow LearnerA Slow Learner
453213
453213
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
This is a particular version of what is known as the Leibniz Integral Rule. The wikipedia link provides a nice proof of the general case(s), and it is not too hard to see how this particular form follows
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3087389%2fswitching-orders-of-differentiation-and-integration-in-case-of-function-of-2-var%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is a particular version of what is known as the Leibniz Integral Rule. The wikipedia link provides a nice proof of the general case(s), and it is not too hard to see how this particular form follows
$endgroup$
add a comment |
$begingroup$
This is a particular version of what is known as the Leibniz Integral Rule. The wikipedia link provides a nice proof of the general case(s), and it is not too hard to see how this particular form follows
$endgroup$
add a comment |
$begingroup$
This is a particular version of what is known as the Leibniz Integral Rule. The wikipedia link provides a nice proof of the general case(s), and it is not too hard to see how this particular form follows
$endgroup$
This is a particular version of what is known as the Leibniz Integral Rule. The wikipedia link provides a nice proof of the general case(s), and it is not too hard to see how this particular form follows
answered Jan 25 at 18:53
Marat AlievMarat Aliev
1312
1312
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3087389%2fswitching-orders-of-differentiation-and-integration-in-case-of-function-of-2-var%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
