Mixing
Affine rectification via vanishing line
$begingroup$
I'm trying to understand how to rectify an image given some lines that should actually be parallel in the final image. For example:
from the book Multiple View Geometry.
I know that the idea is to form a transformation such that the identified lines map to the line at inifinty in the resultin image, but I don't understand how this can work.
The idea would be to use:
$$
H = H_{A}
begin{bmatrix}
1 & 0 & 0 \
0 & 1 & 0 \
l_1 & l_2 & l_3
end{bmatrix}
$$
where the image line at inifinity is $mathbf{l} = (l_1, l_2, l_3)^{T}, l_3 neq 0$ and $H_A$ is an affine transformation.
What would the matrix A be and how does this help the rectification?
I'm confused on how this works. Thanks for any help.
transformation projective-geometry computer-vision
asked Jan 29 at 15:51
ErgoErgo
137213
$endgroup$
add a comment |
$begingroup$
I'm trying to understand how to rectify an image given some lines that should actually be parallel in the final image. For example:
from the book Multiple View Geometry.
I know that the idea is to form a transformation such that the identified lines map to the line at inifinty in the resultin image, but I don't understand how this can work.
The idea would be to use:
$$
H = H_{A}
begin{bmatrix}
1 & 0 & 0 \
0 & 1 & 0 \
l_1 & l_2 & l_3
end{bmatrix}
$$
where the image line at inifinity is $mathbf{l} = (l_1, l_2, l_3)^{T}, l_3 neq 0$ and $H_A$ is an affine transformation.
What would the matrix A be and how does this help the rectification?
I'm confused on how this works. Thanks for any help.
transformation projective-geometry computer-vision
asked Jan 29 at 15:51
ErgoErgo
137213
$endgroup$
add a comment |
$begingroup$
I'm trying to understand how to rectify an image given some lines that should actually be parallel in the final image. For example:
from the book Multiple View Geometry.
I know that the idea is to form a transformation such that the identified lines map to the line at inifinty in the resultin image, but I don't understand how this can work.
The idea would be to use:
$$
H = H_{A}
begin{bmatrix}
1 & 0 & 0 \
0 & 1 & 0 \
l_1 & l_2 & l_3
end{bmatrix}
$$
where the image line at inifinity is $mathbf{l} = (l_1, l_2, l_3)^{T}, l_3 neq 0$ and $H_A$ is an affine transformation.
What would the matrix A be and how does this help the rectification?
I'm confused on how this works. Thanks for any help.
transformation projective-geometry computer-vision
asked Jan 29 at 15:51
ErgoErgo
137213
$endgroup$
I'm trying to understand how to rectify an image given some lines that should actually be parallel in the final image. For example:
from the book Multiple View Geometry.
I know that the idea is to form a transformation such that the identified lines map to the line at inifinty in the resultin image, but I don't understand how this can work.
The idea would be to use:
$$
H = H_{A}
begin{bmatrix}
1 & 0 & 0 \
0 & 1 & 0 \
l_1 & l_2 & l_3
end{bmatrix}
$$
where the image line at inifinity is $mathbf{l} = (l_1, l_2, l_3)^{T}, l_3 neq 0$ and $H_A$ is an affine transformation.
What would the matrix A be and how does this help the rectification?
I'm confused on how this works. Thanks for any help.
transformation projective-geometry computer-vision
transformation projective-geometry computer-vision
asked Jan 29 at 15:51
ErgoErgo
137213
asked Jan 29 at 15:51
ErgoErgo
137213
asked Jan 29 at 15:51
ErgoErgo
137213
asked Jan 29 at 15:51
ErgoErgo
137213
asked Jan 29 at 15:51
ErgoErgo
137213
137213
add a comment |
add a comment |
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