Mixing
Cypress how to continue to call back end API until getting the expected result or timeout
0
I need to create a test case which needs to call a "get" API method to get some information, but the back end server some time need time to process, so I need to create a loop to continue to call the "get" API method until getting the expected result or timeout.
the pseudo code looks like following
string responseMessage;
for(i=0, i<10, i++) {
responseMessage = callGetApi();
if (responseMessage == "success") {
exit loop;
}else {
wait 1 seccond;
}
}
but I don't know how to create that kind of code in Cypress, please help!
javascript cypress
asked Jan 2 at 22:01
Yu JiaYu Jia
868
add a comment |
0
I need to create a test case which needs to call a "get" API method to get some information, but the back end server some time need time to process, so I need to create a loop to continue to call the "get" API method until getting the expected result or timeout.
the pseudo code looks like following
string responseMessage;
for(i=0, i<10, i++) {
responseMessage = callGetApi();
if (responseMessage == "success") {
exit loop;
}else {
wait 1 seccond;
}
}
but I don't know how to create that kind of code in Cypress, please help!
javascript cypress
asked Jan 2 at 22:01
Yu JiaYu Jia
868
add a comment |
0
0
0
I need to create a test case which needs to call a "get" API method to get some information, but the back end server some time need time to process, so I need to create a loop to continue to call the "get" API method until getting the expected result or timeout.
the pseudo code looks like following
string responseMessage;
for(i=0, i<10, i++) {
responseMessage = callGetApi();
if (responseMessage == "success") {
exit loop;
}else {
wait 1 seccond;
}
}
but I don't know how to create that kind of code in Cypress, please help!
javascript cypress
asked Jan 2 at 22:01
Yu JiaYu Jia
868
I need to create a test case which needs to call a "get" API method to get some information, but the back end server some time need time to process, so I need to create a loop to continue to call the "get" API method until getting the expected result or timeout.
the pseudo code looks like following
string responseMessage;
for(i=0, i<10, i++) {
responseMessage = callGetApi();
if (responseMessage == "success") {
exit loop;
}else {
wait 1 seccond;
}
}
but I don't know how to create that kind of code in Cypress, please help!
javascript cypress
javascript cypress
asked Jan 2 at 22:01
Yu JiaYu Jia
868
asked Jan 2 at 22:01
Yu JiaYu Jia
868
edited Jan 2 at 23:18
Yu Jia
asked Jan 2 at 22:01
Yu JiaYu Jia
868
asked Jan 2 at 22:01
Yu JiaYu Jia
868
asked Jan 2 at 22:01
Yu JiaYu Jia
868
868
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
Use async/await:
it('Test loop', async function() {
for(let i=0; i<10; i++) {
await Cypress.Promise(resolve => {
cy.request(your_url).should(response => {
expect(response.status).to.eq(200);
resolve();
});
}
}
});
edited Jan 3 at 19:17
Brendan
984616
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Use async/await:
it('Test loop', async function() {
for(let i=0; i<10; i++) {
await Cypress.Promise(resolve => {
cy.request(your_url).should(response => {
expect(response.status).to.eq(200);
resolve();
});
}
}
});
edited Jan 3 at 19:17
Brendan
984616
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
add a comment |
0
Use async/await:
it('Test loop', async function() {
for(let i=0; i<10; i++) {
await Cypress.Promise(resolve => {
cy.request(your_url).should(response => {
expect(response.status).to.eq(200);
resolve();
});
}
}
});
edited Jan 3 at 19:17
Brendan
984616
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
add a comment |
0
0
0
Use async/await:
it('Test loop', async function() {
for(let i=0; i<10; i++) {
await Cypress.Promise(resolve => {
cy.request(your_url).should(response => {
expect(response.status).to.eq(200);
resolve();
});
}
}
});
edited Jan 3 at 19:17
Brendan
984616
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
Use async/await:
it('Test loop', async function() {
for(let i=0; i<10; i++) {
await Cypress.Promise(resolve => {
cy.request(your_url).should(response => {
expect(response.status).to.eq(200);
resolve();
});
}
}
});
edited Jan 3 at 19:17
Brendan
984616
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
edited Jan 3 at 19:17
Brendan
984616
edited Jan 3 at 19:17
Brendan
984616
edited Jan 3 at 19:17
Brendan
984616
984616
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
answered Jan 3 at 17:33
Julia PassynkovaJulia Passynkova
8,94021824
8,94021824
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
add a comment |
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
Thanks for your answer, one problem after I use your code in my test, the test is to continue running not stop even the response status is 200, and I added code "console.log(i);" to show the iteration. the console show stop at second iteration.
– Yu Jia
Jan 4 at 1:21
add a comment |
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