Mixing
General Solution of partial differential equation
$begingroup$
Consider the equation $u_x+u_y =sqrt{u}$. Derive the general solution $u(x, y) = (x+f(x−y))^2/4$.
Observe that the trivial solution $u(x, y) = 0 $ is not covered by the general solution.
I was able to get to the solution given in the question, but I am not sure why the given trivial solution is not covered by the solution given
pde
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
$endgroup$
add a comment |
$begingroup$
Consider the equation $u_x+u_y =sqrt{u}$. Derive the general solution $u(x, y) = (x+f(x−y))^2/4$.
Observe that the trivial solution $u(x, y) = 0 $ is not covered by the general solution.
I was able to get to the solution given in the question, but I am not sure why the given trivial solution is not covered by the solution given
pde
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
$endgroup$
add a comment |
$begingroup$
Consider the equation $u_x+u_y =sqrt{u}$. Derive the general solution $u(x, y) = (x+f(x−y))^2/4$.
Observe that the trivial solution $u(x, y) = 0 $ is not covered by the general solution.
I was able to get to the solution given in the question, but I am not sure why the given trivial solution is not covered by the solution given
pde
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
$endgroup$
Consider the equation $u_x+u_y =sqrt{u}$. Derive the general solution $u(x, y) = (x+f(x−y))^2/4$.
Observe that the trivial solution $u(x, y) = 0 $ is not covered by the general solution.
I was able to get to the solution given in the question, but I am not sure why the given trivial solution is not covered by the solution given
pde
pde
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
asked Jan 30 at 20:01
Vinit SainiVinit Saini
11
11
add a comment |
add a comment |
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