Help to understand on atcoder Math problem statement
$begingroup$
I stumble on this question (https://atcoder.jp/contests/abc116/tasks/abc116_c) and I cannot for my life understand what the problem ask me to solve
So I understand these part:
we have N flowers
each flowers start at 0 heights
we have sequences of heights that map to each flowers.
I know there could be some sort of addition in here because on the third sample, I can see 96+50+75 = 221.
What I didn't understand
what is the relation of these "l" and "r" to the problem? I know r should be equal to the number of flower but in the first output, "r" can be 3.
I just cannot understand the problem, even after looking up the answer, I still don't know why the answer like that.
problem-solving
$endgroup$
add a comment |
$begingroup$
I stumble on this question (https://atcoder.jp/contests/abc116/tasks/abc116_c) and I cannot for my life understand what the problem ask me to solve
So I understand these part:
we have N flowers
each flowers start at 0 heights
we have sequences of heights that map to each flowers.
I know there could be some sort of addition in here because on the third sample, I can see 96+50+75 = 221.
What I didn't understand
what is the relation of these "l" and "r" to the problem? I know r should be equal to the number of flower but in the first output, "r" can be 3.
I just cannot understand the problem, even after looking up the answer, I still don't know why the answer like that.
problem-solving
$endgroup$
add a comment |
$begingroup$
I stumble on this question (https://atcoder.jp/contests/abc116/tasks/abc116_c) and I cannot for my life understand what the problem ask me to solve
So I understand these part:
we have N flowers
each flowers start at 0 heights
we have sequences of heights that map to each flowers.
I know there could be some sort of addition in here because on the third sample, I can see 96+50+75 = 221.
What I didn't understand
what is the relation of these "l" and "r" to the problem? I know r should be equal to the number of flower but in the first output, "r" can be 3.
I just cannot understand the problem, even after looking up the answer, I still don't know why the answer like that.
problem-solving
$endgroup$
I stumble on this question (https://atcoder.jp/contests/abc116/tasks/abc116_c) and I cannot for my life understand what the problem ask me to solve
So I understand these part:
we have N flowers
each flowers start at 0 heights
we have sequences of heights that map to each flowers.
I know there could be some sort of addition in here because on the third sample, I can see 96+50+75 = 221.
What I didn't understand
what is the relation of these "l" and "r" to the problem? I know r should be equal to the number of flower but in the first output, "r" can be 3.
I just cannot understand the problem, even after looking up the answer, I still don't know why the answer like that.
problem-solving
problem-solving
asked Jan 30 at 13:47
SactioSactio
1
1
add a comment |
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1 Answer
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$begingroup$
The $l$ and $r$ are indices. The input $(1,3)$ indicates that flowers number $1,2,3$ should be increased by $1$. If I instead input $(5,19)$, then flowers $5$ to $19$ are increased by $1$. So $r$ is not the number of flowers. Instead, if there are $n$ flowers, then we have to have $1 leq l leq r leq n$.
$endgroup$
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
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$begingroup$
The $l$ and $r$ are indices. The input $(1,3)$ indicates that flowers number $1,2,3$ should be increased by $1$. If I instead input $(5,19)$, then flowers $5$ to $19$ are increased by $1$. So $r$ is not the number of flowers. Instead, if there are $n$ flowers, then we have to have $1 leq l leq r leq n$.
$endgroup$
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
add a comment |
$begingroup$
The $l$ and $r$ are indices. The input $(1,3)$ indicates that flowers number $1,2,3$ should be increased by $1$. If I instead input $(5,19)$, then flowers $5$ to $19$ are increased by $1$. So $r$ is not the number of flowers. Instead, if there are $n$ flowers, then we have to have $1 leq l leq r leq n$.
$endgroup$
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
add a comment |
$begingroup$
The $l$ and $r$ are indices. The input $(1,3)$ indicates that flowers number $1,2,3$ should be increased by $1$. If I instead input $(5,19)$, then flowers $5$ to $19$ are increased by $1$. So $r$ is not the number of flowers. Instead, if there are $n$ flowers, then we have to have $1 leq l leq r leq n$.
$endgroup$
The $l$ and $r$ are indices. The input $(1,3)$ indicates that flowers number $1,2,3$ should be increased by $1$. If I instead input $(5,19)$, then flowers $5$ to $19$ are increased by $1$. So $r$ is not the number of flowers. Instead, if there are $n$ flowers, then we have to have $1 leq l leq r leq n$.
answered Jan 30 at 13:57
JohannaJohanna
4,74541640
4,74541640
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
add a comment |
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
$begingroup$
Thanks, I think I start to see it. So for sample first input output, they do - (1,3) so it will be "1 1 1 0" - then they do (2,4) to make it "1 2 2 1". and for the second input (1,5) then (1,1) twice then (3,4) then (4,4) assuming l and r can be less than or equal. The description of (l,r) in the problem might need little more explanation
$endgroup$
– Sactio
Jan 30 at 15:19
add a comment |
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