Matching the page number in link

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0

I keep trying to match the page number, but all I'm getting is undefined. What am I doing wrong?

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

javascript match

share|improve this question

asked Jan 3 at 4:27

frostyfrosty

85331639

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If you're trying to get parameter values from a URL, rather than writing an individual RegEx for each and every expected parameter, consider using something like searchParams instead.
  
  – Tyler Roper
  Jan 3 at 4:35
  
  
  

  
  
  
  

add a comment | 

0

I keep trying to match the page number, but all I'm getting is undefined. What am I doing wrong?

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

javascript match

share|improve this question

asked Jan 3 at 4:27

frostyfrosty

85331639

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If you're trying to get parameter values from a URL, rather than writing an individual RegEx for each and every expected parameter, consider using something like searchParams instead.
  
  – Tyler Roper
  Jan 3 at 4:35
  
  
  

  
  
  
  

add a comment | 

0

0

0

I keep trying to match the page number, but all I'm getting is undefined. What am I doing wrong?

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

javascript match

share|improve this question

asked Jan 3 at 4:27

frostyfrosty

85331639

I keep trying to match the page number, but all I'm getting is undefined. What am I doing wrong?

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

javascript match

javascript match

share|improve this question

asked Jan 3 at 4:27

frostyfrosty

85331639

share|improve this question

asked Jan 3 at 4:27

frostyfrosty

85331639

share|improve this question

share|improve this question

asked Jan 3 at 4:27

frostyfrosty

85331639

asked Jan 3 at 4:27

frostyfrosty

85331639

asked Jan 3 at 4:27

frostyfrosty

85331639

85331639

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If you're trying to get parameter values from a URL, rather than writing an individual RegEx for each and every expected parameter, consider using something like searchParams instead.
  
  – Tyler Roper
  Jan 3 at 4:35
  
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If you're trying to get parameter values from a URL, rather than writing an individual RegEx for each and every expected parameter, consider using something like searchParams instead.
  
  – Tyler Roper
  Jan 3 at 4:35
  
  
  

  
  
  
  

If you're trying to get parameter values from a URL, rather than writing an individual RegEx for each and every expected parameter, consider using something like searchParams instead.

– Tyler Roper
Jan 3 at 4:35

If you're trying to get parameter values from a URL, rather than writing an individual RegEx for each and every expected parameter, consider using something like searchParams instead.

– Tyler Roper
Jan 3 at 4:35

add a comment | 

3 Answers
3

active

oldest

votes

1

The problem is that you're using the /g flag, which will return an array of all matches to that regular expression in the string (disregarding capture groups - they aren't visible in the output with /g) - for example, if the input was page_number=1,page_number=2 it would result in page_number=2.

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

To use the capturing group of the only match, just remove the global flag:

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

share|improve this answer

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.
  
  – Ben Beck
  Jan 3 at 4:40
  

  
  
  
  

add a comment | 

0

A regex is likely overkill here. Why not just use split() like this:

var whatPage = currentLink.split('=')[1];

However, if a regex is necessary, you could utilize:

var whatPage =  currentLink.match(/page_number=([1-9]+)/);

console.log(whatPage[1]);

Note, I added the + symbol in the case that your page number isn't strictly within the range of 1-9.

share|improve this answer

edited Jan 3 at 4:41

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because there's actually a lot more stuff in the link than the example I'm posting here.
  
  – frosty
  Jan 3 at 4:32
  

  
  
  
  

add a comment | 

0

Try this way

var currentLink = "page_number=1";

var whatPage = currentLink.match(/[1-9]+/);  

 console.log(whatPage[0]);

share|improve this answer

answered Jan 3 at 4:46

EthanEthan

91

add a comment | 

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

active

oldest

votes

active

oldest

votes

1

The problem is that you're using the /g flag, which will return an array of all matches to that regular expression in the string (disregarding capture groups - they aren't visible in the output with /g) - for example, if the input was page_number=1,page_number=2 it would result in page_number=2.

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

To use the capturing group of the only match, just remove the global flag:

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

share|improve this answer

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.
  
  – Ben Beck
  Jan 3 at 4:40
  

  
  
  
  

add a comment | 

1

The problem is that you're using the /g flag, which will return an array of all matches to that regular expression in the string (disregarding capture groups - they aren't visible in the output with /g) - for example, if the input was page_number=1,page_number=2 it would result in page_number=2.

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

To use the capturing group of the only match, just remove the global flag:

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

share|improve this answer

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.
  
  – Ben Beck
  Jan 3 at 4:40
  

  
  
  
  

add a comment | 

1

1

1

The problem is that you're using the /g flag, which will return an array of all matches to that regular expression in the string (disregarding capture groups - they aren't visible in the output with /g) - for example, if the input was page_number=1,page_number=2 it would result in page_number=2.

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

To use the capturing group of the only match, just remove the global flag:

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

share|improve this answer

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

The problem is that you're using the /g flag, which will return an array of all matches to that regular expression in the string (disregarding capture groups - they aren't visible in the output with /g) - for example, if the input was page_number=1,page_number=2 it would result in page_number=2.

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

To use the capturing group of the only match, just remove the global flag:

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

var currentLink = "page_number=1,page_number=2";

var whatPage = currentLink.match(/page_number=([1-9])/g);

console.log(whatPage[1]);

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

var currentLink = "page_number=1";

var whatPage = currentLink.match(/page_number=([1-9])/);

console.log(whatPage[1]);

share|improve this answer

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

share|improve this answer

share|improve this answer

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

answered Jan 3 at 4:35

CertainPerformanceCertainPerformance

97.8k165887

97.8k165887

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.
  
  – Ben Beck
  Jan 3 at 4:40
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.
  
  – Ben Beck
  Jan 3 at 4:40
  

  
  
  
  

It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.

– Ben Beck
Jan 3 at 4:40

It's worth noting that unless you know the page number is strictly 1-9, then you may want to append the + symbol to the end of your regex (i.e. currentLink.match(/page_number=([1-9]+)/); to cover any number of digits.

– Ben Beck
Jan 3 at 4:40

add a comment | 

0

A regex is likely overkill here. Why not just use split() like this:

var whatPage = currentLink.split('=')[1];

However, if a regex is necessary, you could utilize:

var whatPage =  currentLink.match(/page_number=([1-9]+)/);

console.log(whatPage[1]);

Note, I added the + symbol in the case that your page number isn't strictly within the range of 1-9.

share|improve this answer

edited Jan 3 at 4:41

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because there's actually a lot more stuff in the link than the example I'm posting here.
  
  – frosty
  Jan 3 at 4:32
  

  
  
  
  

add a comment | 

0

A regex is likely overkill here. Why not just use split() like this:

var whatPage = currentLink.split('=')[1];

However, if a regex is necessary, you could utilize:

var whatPage =  currentLink.match(/page_number=([1-9]+)/);

console.log(whatPage[1]);

Note, I added the + symbol in the case that your page number isn't strictly within the range of 1-9.

share|improve this answer

edited Jan 3 at 4:41

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because there's actually a lot more stuff in the link than the example I'm posting here.
  
  – frosty
  Jan 3 at 4:32
  

  
  
  
  

add a comment | 

0

0

0

A regex is likely overkill here. Why not just use split() like this:

var whatPage = currentLink.split('=')[1];

However, if a regex is necessary, you could utilize:

var whatPage =  currentLink.match(/page_number=([1-9]+)/);

console.log(whatPage[1]);

Note, I added the + symbol in the case that your page number isn't strictly within the range of 1-9.

share|improve this answer

edited Jan 3 at 4:41

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

A regex is likely overkill here. Why not just use split() like this:

var whatPage = currentLink.split('=')[1];

However, if a regex is necessary, you could utilize:

var whatPage =  currentLink.match(/page_number=([1-9]+)/);

console.log(whatPage[1]);

Note, I added the + symbol in the case that your page number isn't strictly within the range of 1-9.

share|improve this answer

edited Jan 3 at 4:41

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

share|improve this answer

share|improve this answer

edited Jan 3 at 4:41

edited Jan 3 at 4:41

edited Jan 3 at 4:41

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

answered Jan 3 at 4:30

Ben BeckBen Beck

1,9731616

1,9731616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because there's actually a lot more stuff in the link than the example I'm posting here.
  
  – frosty
  Jan 3 at 4:32
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Because there's actually a lot more stuff in the link than the example I'm posting here.
  
  – frosty
  Jan 3 at 4:32
  

  
  
  
  

Because there's actually a lot more stuff in the link than the example I'm posting here.

– frosty
Jan 3 at 4:32

Because there's actually a lot more stuff in the link than the example I'm posting here.

– frosty
Jan 3 at 4:32

add a comment | 

0

Try this way

var currentLink = "page_number=1";

var whatPage = currentLink.match(/[1-9]+/);  

 console.log(whatPage[0]);

share|improve this answer

answered Jan 3 at 4:46

EthanEthan

91

add a comment | 

0

Try this way

var currentLink = "page_number=1";

var whatPage = currentLink.match(/[1-9]+/);  

 console.log(whatPage[0]);

share|improve this answer

answered Jan 3 at 4:46

EthanEthan

91

add a comment | 

0

0

0

Try this way

var currentLink = "page_number=1";

var whatPage = currentLink.match(/[1-9]+/);  

 console.log(whatPage[0]);

share|improve this answer

answered Jan 3 at 4:46

EthanEthan

91

Try this way

var currentLink = "page_number=1";

var whatPage = currentLink.match(/[1-9]+/);  

 console.log(whatPage[0]);

share|improve this answer

answered Jan 3 at 4:46

EthanEthan

91

share|improve this answer

share|improve this answer

answered Jan 3 at 4:46

EthanEthan

91

answered Jan 3 at 4:46

EthanEthan

91

answered Jan 3 at 4:46

EthanEthan

91

91

add a comment | 

add a comment | 

Thanks for contributing an answer to Stack Overflow!

• Please be sure to answer the question. Provide details and share your research!

But avoid …

• Asking for help, clarification, or responding to other answers.


• Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

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• Please be sure to answer the question. Provide details and share your research!

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