Price of a n toss coin game












1












$begingroup$


I was thinking of a game where a player pays one dollar to toss a coin. If the result is a head they get their 1 dollar bet plus an additional 1 dollar. If the outcome is a tails they lose their 1 dollar bet and get nothing.



If n = 1 the fair price will be 0.5 dollars to play. But what happens if we want to make it n tosses? It becomes complicated because at each iterative step the player has to decide whether the current pay off is greater or less then the expected outcome of tossing another coin.



I simulated this once and got a fair price to be 0.76 dollars for n = 20 but I just cannot recall what my logic was.



Any suggestions will be appreciated.



The players pay off is the number of heads in n tosses.










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$endgroup$












  • $begingroup$
    define "fair price" in "fair price will be 0.5"
    $endgroup$
    – Roam
    Feb 15 '14 at 7:36










  • $begingroup$
    if you were going to sell this opportunity to a unlimited number of punters if you charge 50c for each person to play in the long run you will break even ie. you would expect not to make money and not to lose money
    $endgroup$
    – Seeking Alpha
    Feb 15 '14 at 7:38












  • $begingroup$
    @SeekingAlpha How did you get 50c? If $n=1$, you lose one dollar with probability $frac{1}{2}$ and win one dollar with probability $frac{1}{2}$.
    $endgroup$
    – JiK
    Feb 15 '14 at 8:48










  • $begingroup$
    @JiK, $frac 12 cdot 1+frac 12cdot0=$1=50 c$.
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:52










  • $begingroup$
    What do you earn after two tosses? Does one earn $1$ per head or only when all tosses are head?
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:54
















1












$begingroup$


I was thinking of a game where a player pays one dollar to toss a coin. If the result is a head they get their 1 dollar bet plus an additional 1 dollar. If the outcome is a tails they lose their 1 dollar bet and get nothing.



If n = 1 the fair price will be 0.5 dollars to play. But what happens if we want to make it n tosses? It becomes complicated because at each iterative step the player has to decide whether the current pay off is greater or less then the expected outcome of tossing another coin.



I simulated this once and got a fair price to be 0.76 dollars for n = 20 but I just cannot recall what my logic was.



Any suggestions will be appreciated.



The players pay off is the number of heads in n tosses.










share|cite|improve this question









$endgroup$












  • $begingroup$
    define "fair price" in "fair price will be 0.5"
    $endgroup$
    – Roam
    Feb 15 '14 at 7:36










  • $begingroup$
    if you were going to sell this opportunity to a unlimited number of punters if you charge 50c for each person to play in the long run you will break even ie. you would expect not to make money and not to lose money
    $endgroup$
    – Seeking Alpha
    Feb 15 '14 at 7:38












  • $begingroup$
    @SeekingAlpha How did you get 50c? If $n=1$, you lose one dollar with probability $frac{1}{2}$ and win one dollar with probability $frac{1}{2}$.
    $endgroup$
    – JiK
    Feb 15 '14 at 8:48










  • $begingroup$
    @JiK, $frac 12 cdot 1+frac 12cdot0=$1=50 c$.
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:52










  • $begingroup$
    What do you earn after two tosses? Does one earn $1$ per head or only when all tosses are head?
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:54














1












1








1





$begingroup$


I was thinking of a game where a player pays one dollar to toss a coin. If the result is a head they get their 1 dollar bet plus an additional 1 dollar. If the outcome is a tails they lose their 1 dollar bet and get nothing.



If n = 1 the fair price will be 0.5 dollars to play. But what happens if we want to make it n tosses? It becomes complicated because at each iterative step the player has to decide whether the current pay off is greater or less then the expected outcome of tossing another coin.



I simulated this once and got a fair price to be 0.76 dollars for n = 20 but I just cannot recall what my logic was.



Any suggestions will be appreciated.



The players pay off is the number of heads in n tosses.










share|cite|improve this question









$endgroup$




I was thinking of a game where a player pays one dollar to toss a coin. If the result is a head they get their 1 dollar bet plus an additional 1 dollar. If the outcome is a tails they lose their 1 dollar bet and get nothing.



If n = 1 the fair price will be 0.5 dollars to play. But what happens if we want to make it n tosses? It becomes complicated because at each iterative step the player has to decide whether the current pay off is greater or less then the expected outcome of tossing another coin.



I simulated this once and got a fair price to be 0.76 dollars for n = 20 but I just cannot recall what my logic was.



Any suggestions will be appreciated.



The players pay off is the number of heads in n tosses.







probability statistics






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Feb 15 '14 at 7:27









Seeking AlphaSeeking Alpha

25228




25228












  • $begingroup$
    define "fair price" in "fair price will be 0.5"
    $endgroup$
    – Roam
    Feb 15 '14 at 7:36










  • $begingroup$
    if you were going to sell this opportunity to a unlimited number of punters if you charge 50c for each person to play in the long run you will break even ie. you would expect not to make money and not to lose money
    $endgroup$
    – Seeking Alpha
    Feb 15 '14 at 7:38












  • $begingroup$
    @SeekingAlpha How did you get 50c? If $n=1$, you lose one dollar with probability $frac{1}{2}$ and win one dollar with probability $frac{1}{2}$.
    $endgroup$
    – JiK
    Feb 15 '14 at 8:48










  • $begingroup$
    @JiK, $frac 12 cdot 1+frac 12cdot0=$1=50 c$.
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:52










  • $begingroup$
    What do you earn after two tosses? Does one earn $1$ per head or only when all tosses are head?
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:54


















  • $begingroup$
    define "fair price" in "fair price will be 0.5"
    $endgroup$
    – Roam
    Feb 15 '14 at 7:36










  • $begingroup$
    if you were going to sell this opportunity to a unlimited number of punters if you charge 50c for each person to play in the long run you will break even ie. you would expect not to make money and not to lose money
    $endgroup$
    – Seeking Alpha
    Feb 15 '14 at 7:38












  • $begingroup$
    @SeekingAlpha How did you get 50c? If $n=1$, you lose one dollar with probability $frac{1}{2}$ and win one dollar with probability $frac{1}{2}$.
    $endgroup$
    – JiK
    Feb 15 '14 at 8:48










  • $begingroup$
    @JiK, $frac 12 cdot 1+frac 12cdot0=$1=50 c$.
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:52










  • $begingroup$
    What do you earn after two tosses? Does one earn $1$ per head or only when all tosses are head?
    $endgroup$
    – Ragnar
    Feb 15 '14 at 8:54
















$begingroup$
define "fair price" in "fair price will be 0.5"
$endgroup$
– Roam
Feb 15 '14 at 7:36




$begingroup$
define "fair price" in "fair price will be 0.5"
$endgroup$
– Roam
Feb 15 '14 at 7:36












$begingroup$
if you were going to sell this opportunity to a unlimited number of punters if you charge 50c for each person to play in the long run you will break even ie. you would expect not to make money and not to lose money
$endgroup$
– Seeking Alpha
Feb 15 '14 at 7:38






$begingroup$
if you were going to sell this opportunity to a unlimited number of punters if you charge 50c for each person to play in the long run you will break even ie. you would expect not to make money and not to lose money
$endgroup$
– Seeking Alpha
Feb 15 '14 at 7:38














$begingroup$
@SeekingAlpha How did you get 50c? If $n=1$, you lose one dollar with probability $frac{1}{2}$ and win one dollar with probability $frac{1}{2}$.
$endgroup$
– JiK
Feb 15 '14 at 8:48




$begingroup$
@SeekingAlpha How did you get 50c? If $n=1$, you lose one dollar with probability $frac{1}{2}$ and win one dollar with probability $frac{1}{2}$.
$endgroup$
– JiK
Feb 15 '14 at 8:48












$begingroup$
@JiK, $frac 12 cdot 1+frac 12cdot0=$1=50 c$.
$endgroup$
– Ragnar
Feb 15 '14 at 8:52




$begingroup$
@JiK, $frac 12 cdot 1+frac 12cdot0=$1=50 c$.
$endgroup$
– Ragnar
Feb 15 '14 at 8:52












$begingroup$
What do you earn after two tosses? Does one earn $1$ per head or only when all tosses are head?
$endgroup$
– Ragnar
Feb 15 '14 at 8:54




$begingroup$
What do you earn after two tosses? Does one earn $1$ per head or only when all tosses are head?
$endgroup$
– Ragnar
Feb 15 '14 at 8:54










1 Answer
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$begingroup$

The fair price for $n$ tosses is $n$ dollars.



JiK has shown for a single toss the fair price is one dollar. For $n$ tosses if the player pays a dollar for each toss then the expected profit is $$E[mathrm{gain}]= {left( { n over 2} right)} (+1) + {left( { n over 2} right) } (-1)= 0,$$ where ${n over 2}$ is the expected number of heads and the expected number of tails. So the fair price is $n.$



Intuitively, this makes sense. All tosses are independent, so if the fair price for a single toss is one dollar, then the fair price for $n$ tosses should be $n$ dollars.






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    $begingroup$

    The fair price for $n$ tosses is $n$ dollars.



    JiK has shown for a single toss the fair price is one dollar. For $n$ tosses if the player pays a dollar for each toss then the expected profit is $$E[mathrm{gain}]= {left( { n over 2} right)} (+1) + {left( { n over 2} right) } (-1)= 0,$$ where ${n over 2}$ is the expected number of heads and the expected number of tails. So the fair price is $n.$



    Intuitively, this makes sense. All tosses are independent, so if the fair price for a single toss is one dollar, then the fair price for $n$ tosses should be $n$ dollars.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      The fair price for $n$ tosses is $n$ dollars.



      JiK has shown for a single toss the fair price is one dollar. For $n$ tosses if the player pays a dollar for each toss then the expected profit is $$E[mathrm{gain}]= {left( { n over 2} right)} (+1) + {left( { n over 2} right) } (-1)= 0,$$ where ${n over 2}$ is the expected number of heads and the expected number of tails. So the fair price is $n.$



      Intuitively, this makes sense. All tosses are independent, so if the fair price for a single toss is one dollar, then the fair price for $n$ tosses should be $n$ dollars.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        The fair price for $n$ tosses is $n$ dollars.



        JiK has shown for a single toss the fair price is one dollar. For $n$ tosses if the player pays a dollar for each toss then the expected profit is $$E[mathrm{gain}]= {left( { n over 2} right)} (+1) + {left( { n over 2} right) } (-1)= 0,$$ where ${n over 2}$ is the expected number of heads and the expected number of tails. So the fair price is $n.$



        Intuitively, this makes sense. All tosses are independent, so if the fair price for a single toss is one dollar, then the fair price for $n$ tosses should be $n$ dollars.






        share|cite|improve this answer









        $endgroup$



        The fair price for $n$ tosses is $n$ dollars.



        JiK has shown for a single toss the fair price is one dollar. For $n$ tosses if the player pays a dollar for each toss then the expected profit is $$E[mathrm{gain}]= {left( { n over 2} right)} (+1) + {left( { n over 2} right) } (-1)= 0,$$ where ${n over 2}$ is the expected number of heads and the expected number of tails. So the fair price is $n.$



        Intuitively, this makes sense. All tosses are independent, so if the fair price for a single toss is one dollar, then the fair price for $n$ tosses should be $n$ dollars.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Feb 16 '14 at 3:09









        soakleysoakley

        1,42621114




        1,42621114






























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