Mixing
spark 2.3.1 insertinto remove value of fields and change it to null
I just upgrade my spark cluster from 2.2.1 to 2.3.1 in order to enjoy the feature of overwrite specific partitions. see link.
But ....
From some reason when I am testing it I get a very strange behavior see code:
import org.apache.spark.SparkConf
import org.apache.spark.sql.{SaveMode, SparkSession}
case class MyRow(partitionField: Int, someId: Int, someText: String)
object ExampleForStack2 extends App{
val sparkConf = new SparkConf()
sparkConf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
sparkConf.setMaster(s"local[2]")
val spark = SparkSession.builder().config(sparkConf).getOrCreate()
val list1 = List(
MyRow(1, 1, "someText")
,MyRow(2, 2, "someText2")
)
val list2 = List(
MyRow(1, 1, "someText modified")
,MyRow(3, 3, "someText3")
)
val df = spark.createDataFrame(list1)
val df2 = spark.createDataFrame(list2)
df2.show(false)
df.write.partitionBy("partitionField").option("path","/tmp/tables/").saveAsTable("my_table")
df2.write.mode(SaveMode.Overwrite).insertInto("my_table")
spark.sql("select * from my_table").show(false)
}
And output:
+--------------+------+-----------------+
|partitionField|someId|someText |
+--------------+------+-----------------+
|1 |1 |someText modified|
|3 |3 |someText3 |
+--------------+------+-----------------+
+------+---------+--------------+
|someId|someText |partitionField|
+------+---------+--------------+
|2 |someText2|2 |
|1 |someText |1 |
|3 |3 |null |
|1 |1 |null |
+------+---------+--------------+
Why I get those nulls ?
It seems that fields were moved ? but why?
Thanks
scala apache-spark
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
add a comment |
I just upgrade my spark cluster from 2.2.1 to 2.3.1 in order to enjoy the feature of overwrite specific partitions. see link.
But ....
From some reason when I am testing it I get a very strange behavior see code:
import org.apache.spark.SparkConf
import org.apache.spark.sql.{SaveMode, SparkSession}
case class MyRow(partitionField: Int, someId: Int, someText: String)
object ExampleForStack2 extends App{
val sparkConf = new SparkConf()
sparkConf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
sparkConf.setMaster(s"local[2]")
val spark = SparkSession.builder().config(sparkConf).getOrCreate()
val list1 = List(
MyRow(1, 1, "someText")
,MyRow(2, 2, "someText2")
)
val list2 = List(
MyRow(1, 1, "someText modified")
,MyRow(3, 3, "someText3")
)
val df = spark.createDataFrame(list1)
val df2 = spark.createDataFrame(list2)
df2.show(false)
df.write.partitionBy("partitionField").option("path","/tmp/tables/").saveAsTable("my_table")
df2.write.mode(SaveMode.Overwrite).insertInto("my_table")
spark.sql("select * from my_table").show(false)
}
And output:
+--------------+------+-----------------+
|partitionField|someId|someText |
+--------------+------+-----------------+
|1 |1 |someText modified|
|3 |3 |someText3 |
+--------------+------+-----------------+
+------+---------+--------------+
|someId|someText |partitionField|
+------+---------+--------------+
|2 |someText2|2 |
|1 |someText |1 |
|3 |3 |null |
|1 |1 |null |
+------+---------+--------------+
Why I get those nulls ?
It seems that fields were moved ? but why?
Thanks
scala apache-spark
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
add a comment |
I just upgrade my spark cluster from 2.2.1 to 2.3.1 in order to enjoy the feature of overwrite specific partitions. see link.
But ....
From some reason when I am testing it I get a very strange behavior see code:
import org.apache.spark.SparkConf
import org.apache.spark.sql.{SaveMode, SparkSession}
case class MyRow(partitionField: Int, someId: Int, someText: String)
object ExampleForStack2 extends App{
val sparkConf = new SparkConf()
sparkConf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
sparkConf.setMaster(s"local[2]")
val spark = SparkSession.builder().config(sparkConf).getOrCreate()
val list1 = List(
MyRow(1, 1, "someText")
,MyRow(2, 2, "someText2")
)
val list2 = List(
MyRow(1, 1, "someText modified")
,MyRow(3, 3, "someText3")
)
val df = spark.createDataFrame(list1)
val df2 = spark.createDataFrame(list2)
df2.show(false)
df.write.partitionBy("partitionField").option("path","/tmp/tables/").saveAsTable("my_table")
df2.write.mode(SaveMode.Overwrite).insertInto("my_table")
spark.sql("select * from my_table").show(false)
}
And output:
+--------------+------+-----------------+
|partitionField|someId|someText |
+--------------+------+-----------------+
|1 |1 |someText modified|
|3 |3 |someText3 |
+--------------+------+-----------------+
+------+---------+--------------+
|someId|someText |partitionField|
+------+---------+--------------+
|2 |someText2|2 |
|1 |someText |1 |
|3 |3 |null |
|1 |1 |null |
+------+---------+--------------+
Why I get those nulls ?
It seems that fields were moved ? but why?
Thanks
scala apache-spark
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
I just upgrade my spark cluster from 2.2.1 to 2.3.1 in order to enjoy the feature of overwrite specific partitions. see link.
But ....
From some reason when I am testing it I get a very strange behavior see code:
import org.apache.spark.SparkConf
import org.apache.spark.sql.{SaveMode, SparkSession}
case class MyRow(partitionField: Int, someId: Int, someText: String)
object ExampleForStack2 extends App{
val sparkConf = new SparkConf()
sparkConf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
sparkConf.setMaster(s"local[2]")
val spark = SparkSession.builder().config(sparkConf).getOrCreate()
val list1 = List(
MyRow(1, 1, "someText")
,MyRow(2, 2, "someText2")
)
val list2 = List(
MyRow(1, 1, "someText modified")
,MyRow(3, 3, "someText3")
)
val df = spark.createDataFrame(list1)
val df2 = spark.createDataFrame(list2)
df2.show(false)
df.write.partitionBy("partitionField").option("path","/tmp/tables/").saveAsTable("my_table")
df2.write.mode(SaveMode.Overwrite).insertInto("my_table")
spark.sql("select * from my_table").show(false)
}
And output:
+--------------+------+-----------------+
|partitionField|someId|someText |
+--------------+------+-----------------+
|1 |1 |someText modified|
|3 |3 |someText3 |
+--------------+------+-----------------+
+------+---------+--------------+
|someId|someText |partitionField|
+------+---------+--------------+
|2 |someText2|2 |
|1 |someText |1 |
|3 |3 |null |
|1 |1 |null |
+------+---------+--------------+
Why I get those nulls ?
It seems that fields were moved ? but why?
Thanks
scala apache-spark
scala apache-spark
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
asked Jan 2 at 21:32
Ehud LevEhud Lev
8381017
8381017
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Ok found it, insert into is based on fields position. see documentation
Unlike saveAsTable, insertInto ignores the column names and just uses position-based resolution. For example:
scala> Seq((1, 2)).toDF("i", "j").write.mode("overwrite").saveAsTable("t1")
scala> Seq((3, 4)).toDF("j", "i").write.insertInto("t1")
scala> Seq((5, 6)).toDF("a", "b").write.insertInto("t1")
scala> sql("select * from t1").show
+---+---+
| i| j|
+---+---+
| 5| 6|
| 3| 4|
| 1| 2|
+---+---+
Because it inserts data to an existing table, format or options will
be ignored.
Moreover I am using dynamic partition which should appear as the last field. So the solution is to move the dynamic partitions to the end of the dataframe, which means in my case:
df2.select("someId", "someText","partitionField").write.mode(SaveMode.Overwrite).insertInto("my_table")
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Ok found it, insert into is based on fields position. see documentation
Unlike saveAsTable, insertInto ignores the column names and just uses position-based resolution. For example:
scala> Seq((1, 2)).toDF("i", "j").write.mode("overwrite").saveAsTable("t1")
scala> Seq((3, 4)).toDF("j", "i").write.insertInto("t1")
scala> Seq((5, 6)).toDF("a", "b").write.insertInto("t1")
scala> sql("select * from t1").show
+---+---+
| i| j|
+---+---+
| 5| 6|
| 3| 4|
| 1| 2|
+---+---+
Because it inserts data to an existing table, format or options will
be ignored.
Moreover I am using dynamic partition which should appear as the last field. So the solution is to move the dynamic partitions to the end of the dataframe, which means in my case:
df2.select("someId", "someText","partitionField").write.mode(SaveMode.Overwrite).insertInto("my_table")
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
add a comment |
Ok found it, insert into is based on fields position. see documentation
Unlike saveAsTable, insertInto ignores the column names and just uses position-based resolution. For example:
scala> Seq((1, 2)).toDF("i", "j").write.mode("overwrite").saveAsTable("t1")
scala> Seq((3, 4)).toDF("j", "i").write.insertInto("t1")
scala> Seq((5, 6)).toDF("a", "b").write.insertInto("t1")
scala> sql("select * from t1").show
+---+---+
| i| j|
+---+---+
| 5| 6|
| 3| 4|
| 1| 2|
+---+---+
Because it inserts data to an existing table, format or options will
be ignored.
Moreover I am using dynamic partition which should appear as the last field. So the solution is to move the dynamic partitions to the end of the dataframe, which means in my case:
df2.select("someId", "someText","partitionField").write.mode(SaveMode.Overwrite).insertInto("my_table")
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
add a comment |
Ok found it, insert into is based on fields position. see documentation
Unlike saveAsTable, insertInto ignores the column names and just uses position-based resolution. For example:
scala> Seq((1, 2)).toDF("i", "j").write.mode("overwrite").saveAsTable("t1")
scala> Seq((3, 4)).toDF("j", "i").write.insertInto("t1")
scala> Seq((5, 6)).toDF("a", "b").write.insertInto("t1")
scala> sql("select * from t1").show
+---+---+
| i| j|
+---+---+
| 5| 6|
| 3| 4|
| 1| 2|
+---+---+
Because it inserts data to an existing table, format or options will
be ignored.
Moreover I am using dynamic partition which should appear as the last field. So the solution is to move the dynamic partitions to the end of the dataframe, which means in my case:
df2.select("someId", "someText","partitionField").write.mode(SaveMode.Overwrite).insertInto("my_table")
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
Ok found it, insert into is based on fields position. see documentation
Unlike saveAsTable, insertInto ignores the column names and just uses position-based resolution. For example:
scala> Seq((1, 2)).toDF("i", "j").write.mode("overwrite").saveAsTable("t1")
scala> Seq((3, 4)).toDF("j", "i").write.insertInto("t1")
scala> Seq((5, 6)).toDF("a", "b").write.insertInto("t1")
scala> sql("select * from t1").show
+---+---+
| i| j|
+---+---+
| 5| 6|
| 3| 4|
| 1| 2|
+---+---+
Because it inserts data to an existing table, format or options will
be ignored.
Moreover I am using dynamic partition which should appear as the last field. So the solution is to move the dynamic partitions to the end of the dataframe, which means in my case:
df2.select("someId", "someText","partitionField").write.mode(SaveMode.Overwrite).insertInto("my_table")
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
answered Jan 2 at 21:51
Ehud LevEhud Lev
8381017
8381017
add a comment |
add a comment |
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