Closure of the graphic of the vector of the players' payoff functions












0














Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.



Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?










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  • It's the graph, not graphic. And yes.
    – Michael Greinecker
    Nov 20 '18 at 7:22










  • I'm sorry because of that. Can you give me a hint?
    – Diego Cornejo Koc
    Nov 20 '18 at 13:14










  • This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
    – Michael Greinecker
    Nov 20 '18 at 13:39










  • But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
    – Diego Cornejo Koc
    Nov 20 '18 at 13:50










  • $X$ is compact as the Cartesian product of compact spaces.
    – Michael Greinecker
    Nov 20 '18 at 14:06
















0














Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.



Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?










share|cite|improve this question






















  • It's the graph, not graphic. And yes.
    – Michael Greinecker
    Nov 20 '18 at 7:22










  • I'm sorry because of that. Can you give me a hint?
    – Diego Cornejo Koc
    Nov 20 '18 at 13:14










  • This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
    – Michael Greinecker
    Nov 20 '18 at 13:39










  • But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
    – Diego Cornejo Koc
    Nov 20 '18 at 13:50










  • $X$ is compact as the Cartesian product of compact spaces.
    – Michael Greinecker
    Nov 20 '18 at 14:06














0












0








0







Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.



Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?










share|cite|improve this question













Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.



Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?







game-theory






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share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 20 '18 at 6:54









Diego Cornejo Koc

63




63












  • It's the graph, not graphic. And yes.
    – Michael Greinecker
    Nov 20 '18 at 7:22










  • I'm sorry because of that. Can you give me a hint?
    – Diego Cornejo Koc
    Nov 20 '18 at 13:14










  • This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
    – Michael Greinecker
    Nov 20 '18 at 13:39










  • But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
    – Diego Cornejo Koc
    Nov 20 '18 at 13:50










  • $X$ is compact as the Cartesian product of compact spaces.
    – Michael Greinecker
    Nov 20 '18 at 14:06


















  • It's the graph, not graphic. And yes.
    – Michael Greinecker
    Nov 20 '18 at 7:22










  • I'm sorry because of that. Can you give me a hint?
    – Diego Cornejo Koc
    Nov 20 '18 at 13:14










  • This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
    – Michael Greinecker
    Nov 20 '18 at 13:39










  • But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
    – Diego Cornejo Koc
    Nov 20 '18 at 13:50










  • $X$ is compact as the Cartesian product of compact spaces.
    – Michael Greinecker
    Nov 20 '18 at 14:06
















It's the graph, not graphic. And yes.
– Michael Greinecker
Nov 20 '18 at 7:22




It's the graph, not graphic. And yes.
– Michael Greinecker
Nov 20 '18 at 7:22












I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14




I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14












This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker
Nov 20 '18 at 13:39




This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker
Nov 20 '18 at 13:39












But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50




But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50












$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker
Nov 20 '18 at 14:06




$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker
Nov 20 '18 at 14:06















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