Closure of the graphic of the vector of the players' payoff functions
Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.
Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?
game-theory
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Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.
Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?
game-theory
It's the graph, not graphic. And yes.
– Michael Greinecker♦
Nov 20 '18 at 7:22
I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14
This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker♦
Nov 20 '18 at 13:39
But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50
$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker♦
Nov 20 '18 at 14:06
|
show 4 more comments
Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.
Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?
game-theory
Let $X_i$ be a compact subset of a topological vector space (not necessarily Hausdorff) , $i=1,ldots,N$,
$ u_i: Xrightarrow mathbb{R}$ the payoff functions and $u$ the vector of the players' payoff functions.
Is true that the closure of the graphic of $u$ is a subset of $Xtimes mathbb{R}^N$?
game-theory
game-theory
asked Nov 20 '18 at 6:54
Diego Cornejo Koc
63
63
It's the graph, not graphic. And yes.
– Michael Greinecker♦
Nov 20 '18 at 7:22
I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14
This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker♦
Nov 20 '18 at 13:39
But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50
$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker♦
Nov 20 '18 at 14:06
|
show 4 more comments
It's the graph, not graphic. And yes.
– Michael Greinecker♦
Nov 20 '18 at 7:22
I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14
This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker♦
Nov 20 '18 at 13:39
But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50
$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker♦
Nov 20 '18 at 14:06
It's the graph, not graphic. And yes.
– Michael Greinecker♦
Nov 20 '18 at 7:22
It's the graph, not graphic. And yes.
– Michael Greinecker♦
Nov 20 '18 at 7:22
I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14
I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14
This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker♦
Nov 20 '18 at 13:39
This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker♦
Nov 20 '18 at 13:39
But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50
But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50
$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker♦
Nov 20 '18 at 14:06
$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker♦
Nov 20 '18 at 14:06
|
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It's the graph, not graphic. And yes.
– Michael Greinecker♦
Nov 20 '18 at 7:22
I'm sorry because of that. Can you give me a hint?
– Diego Cornejo Koc
Nov 20 '18 at 13:14
This is pretty much a direct consequence of the definition of the graph of a function, see en.wikipedia.org/wiki/Graph_of_a_function
– Michael Greinecker♦
Nov 20 '18 at 13:39
But $overline{Gr(u)} subseteq overline{Xtimes mathbb{R}^N} = overline{X}times mathbb{R}^N$ and $X$ is not necessarily closed.
– Diego Cornejo Koc
Nov 20 '18 at 13:50
$X$ is compact as the Cartesian product of compact spaces.
– Michael Greinecker♦
Nov 20 '18 at 14:06