How to execute Shell Script from Flask App [duplicate]

-1

This question already has an answer here:

Store output of subprocess.Popen call in a string

9 answers

I've created and deployed a Flask App with Apache2 server WSGI in which now would like to run a .sh script from the App. However, from calling from python code, it doesn't execute.

Here is the test.sh:

#!/bin/bash

echo "hi from shell script"

Here is my python flask app code index.py (runs when App is opened) but nothing is printed or executed:

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

To check that there is not errors in my code, I've check flask error logs, and no errors. Also, I created a script called test_shell_script.py with same python code as above (but not flask app code) and it runs great like this:

# test_shell_script.py

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

And then run it with python:
python3 /var/www/FlaskApp/FlaskApp/test_shell_script.py

hi from shell script

I did change the permissions as well:

-rwxr-xr-x 1 root root 364 Nov 19 17:48 ../scripts/test.sh

What am I missing here which is not allowing my Flask app to run shell commands from the python code?

edited Nov 19 '18 at 19:19

asked Nov 19 '18 at 18:57

jKraut

57731019

marked as duplicate by davidism flask
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Nov 20 '18 at 1:05

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

What kind of error do you get? This looks similar: stackoverflow.com/questions/4256107/…, can you try the subprocess.Popen suggestion?
– Seraf
Nov 19 '18 at 19:04

Receive no error. I've tried subprocess.Popen and even os.system
– jKraut
Nov 19 '18 at 19:09

You gave permission to root for the file run_sql.sh but the file name you are trying to run is test.sh
– Seraf
Nov 19 '18 at 19:15

@Seraf - sorry that was a typo, fixed it now
– jKraut
Nov 19 '18 at 19:19

Weird, the user that runs the Flask app is root? (Probably yes but still asking)
– Seraf
Nov 19 '18 at 19:25

|
show 2 more comments

-1

This question already has an answer here:

Store output of subprocess.Popen call in a string

9 answers

I've created and deployed a Flask App with Apache2 server WSGI in which now would like to run a .sh script from the App. However, from calling from python code, it doesn't execute.

Here is the test.sh:

#!/bin/bash

echo "hi from shell script"

Here is my python flask app code index.py (runs when App is opened) but nothing is printed or executed:

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

# test_shell_script.py

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

And then run it with python:
python3 /var/www/FlaskApp/FlaskApp/test_shell_script.py

hi from shell script

I did change the permissions as well:

-rwxr-xr-x 1 root root 364 Nov 19 17:48 ../scripts/test.sh

What am I missing here which is not allowing my Flask app to run shell commands from the python code?

edited Nov 19 '18 at 19:19

asked Nov 19 '18 at 18:57

jKraut

57731019

marked as duplicate by davidism flask
Users with the flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

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Nov 20 '18 at 1:05

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

What kind of error do you get? This looks similar: stackoverflow.com/questions/4256107/…, can you try the subprocess.Popen suggestion?
– Seraf
Nov 19 '18 at 19:04

Receive no error. I've tried subprocess.Popen and even os.system
– jKraut
Nov 19 '18 at 19:09

You gave permission to root for the file run_sql.sh but the file name you are trying to run is test.sh
– Seraf
Nov 19 '18 at 19:15

@Seraf - sorry that was a typo, fixed it now
– jKraut
Nov 19 '18 at 19:19

Weird, the user that runs the Flask app is root? (Probably yes but still asking)
– Seraf
Nov 19 '18 at 19:25

|
show 2 more comments

-1

This question already has an answer here:

Store output of subprocess.Popen call in a string

9 answers

I've created and deployed a Flask App with Apache2 server WSGI in which now would like to run a .sh script from the App. However, from calling from python code, it doesn't execute.

Here is the test.sh:

#!/bin/bash

echo "hi from shell script"

Here is my python flask app code index.py (runs when App is opened) but nothing is printed or executed:

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

# test_shell_script.py

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

And then run it with python:
python3 /var/www/FlaskApp/FlaskApp/test_shell_script.py

hi from shell script

I did change the permissions as well:

-rwxr-xr-x 1 root root 364 Nov 19 17:48 ../scripts/test.sh

What am I missing here which is not allowing my Flask app to run shell commands from the python code?

edited Nov 19 '18 at 19:19

asked Nov 19 '18 at 18:57

jKraut

57731019

This question already has an answer here:

Store output of subprocess.Popen call in a string

9 answers

I've created and deployed a Flask App with Apache2 server WSGI in which now would like to run a .sh script from the App. However, from calling from python code, it doesn't execute.

Here is the test.sh:

#!/bin/bash

echo "hi from shell script"

Here is my python flask app code index.py (runs when App is opened) but nothing is printed or executed:

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

# test_shell_script.py

import subprocess

subprocess.call('/var/www/FlaskApp/FlaskApp/scripts/test.sh')

And then run it with python:
python3 /var/www/FlaskApp/FlaskApp/test_shell_script.py

hi from shell script

I did change the permissions as well:

-rwxr-xr-x 1 root root 364 Nov 19 17:48 ../scripts/test.sh

What am I missing here which is not allowing my Flask app to run shell commands from the python code?

This question already has an answer here:

Store output of subprocess.Popen call in a string

9 answers

python bash shell flask

edited Nov 19 '18 at 19:19

asked Nov 19 '18 at 18:57

jKraut

57731019

edited Nov 19 '18 at 19:19

asked Nov 19 '18 at 18:57

jKraut

57731019

edited Nov 19 '18 at 19:19

asked Nov 19 '18 at 18:57

jKraut

57731019

asked Nov 19 '18 at 18:57

jKraut

57731019

asked Nov 19 '18 at 18:57

jKraut

57731019

marked as duplicate by davidism flask
Users with the flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

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Nov 20 '18 at 1:05

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by davidism flask
Users with the flask badge can single-handedly close flask questions as duplicates and reopen them as needed.

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Nov 20 '18 at 1:05

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

What kind of error do you get? This looks similar: stackoverflow.com/questions/4256107/…, can you try the subprocess.Popen suggestion?
– Seraf
Nov 19 '18 at 19:04

Receive no error. I've tried subprocess.Popen and even os.system
– jKraut
Nov 19 '18 at 19:09

You gave permission to root for the file run_sql.sh but the file name you are trying to run is test.sh
– Seraf
Nov 19 '18 at 19:15

@Seraf - sorry that was a typo, fixed it now
– jKraut
Nov 19 '18 at 19:19

Weird, the user that runs the Flask app is root? (Probably yes but still asking)
– Seraf
Nov 19 '18 at 19:25

|
show 2 more comments

What kind of error do you get? This looks similar: stackoverflow.com/questions/4256107/…, can you try the subprocess.Popen suggestion?
– Seraf
Nov 19 '18 at 19:04

Receive no error. I've tried subprocess.Popen and even os.system
– jKraut
Nov 19 '18 at 19:09

You gave permission to root for the file run_sql.sh but the file name you are trying to run is test.sh
– Seraf
Nov 19 '18 at 19:15

@Seraf - sorry that was a typo, fixed it now
– jKraut
Nov 19 '18 at 19:19

Weird, the user that runs the Flask app is root? (Probably yes but still asking)
– Seraf
Nov 19 '18 at 19:25

What kind of error do you get? This looks similar: stackoverflow.com/questions/4256107/…, can you try the subprocess.Popen suggestion?
– Seraf
Nov 19 '18 at 19:04

Receive no error. I've tried subprocess.Popen and even os.system
– jKraut
Nov 19 '18 at 19:09

You gave permission to root for the file run_sql.sh but the file name you are trying to run is test.sh
– Seraf
Nov 19 '18 at 19:15

@Seraf - sorry that was a typo, fixed it now
– jKraut
Nov 19 '18 at 19:19

Weird, the user that runs the Flask app is root? (Probably yes but still asking)
– Seraf
Nov 19 '18 at 19:25

|
show 2 more comments

1 Answer
1

active

oldest

votes

To show command output inside Python, there are two popular methods:

check_output(): It runs command with arguments and return its output. (official documentation)

subprocess.communicate(): Interact with process: Send data to stdin. Read data from stdout and stderr, until end-of-file is reached. (official documentation)

I could view the shell file output using these both methods using Python 3.5 in an Ubuntu machine.

app.py:

import subprocess

from subprocess import Popen, PIPE

from subprocess import check_output

from flask import Flask



def get_shell_script_output_using_communicate():

    session = subprocess.Popen(['./some.sh'], stdout=PIPE, stderr=PIPE)

    stdout, stderr = session.communicate()

    if stderr:

        raise Exception("Error "+str(stderr))

    return stdout.decode('utf-8')



def get_shell_script_output_using_check_output():

    stdout = check_output(['./some.sh']).decode('utf-8')

    return stdout



app = Flask(__name__)



@app.route('/',methods=['GET',])

def home():

    return '<pre>'+get_shell_script_output_using_check_output()+'</pre>'



app.run(debug=True)

some.sh:

#!/bin/bash

echo "hi from shell script"

echo "hello from shell script"

Output screenshot:

enter image description here

answered Nov 19 '18 at 19:55

arsho

3,28911531

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

To show command output inside Python, there are two popular methods:

check_output(): It runs command with arguments and return its output. (official documentation)

subprocess.communicate(): Interact with process: Send data to stdin. Read data from stdout and stderr, until end-of-file is reached. (official documentation)

I could view the shell file output using these both methods using Python 3.5 in an Ubuntu machine.

app.py:

import subprocess

from subprocess import Popen, PIPE

from subprocess import check_output

from flask import Flask



def get_shell_script_output_using_communicate():

    session = subprocess.Popen(['./some.sh'], stdout=PIPE, stderr=PIPE)

    stdout, stderr = session.communicate()

    if stderr:

        raise Exception("Error "+str(stderr))

    return stdout.decode('utf-8')



def get_shell_script_output_using_check_output():

    stdout = check_output(['./some.sh']).decode('utf-8')

    return stdout



app = Flask(__name__)



@app.route('/',methods=['GET',])

def home():

    return '<pre>'+get_shell_script_output_using_check_output()+'</pre>'



app.run(debug=True)

some.sh:

#!/bin/bash

echo "hi from shell script"

echo "hello from shell script"

Output screenshot:

enter image description here

answered Nov 19 '18 at 19:55

arsho

3,28911531

add a comment |

To show command output inside Python, there are two popular methods:

check_output(): It runs command with arguments and return its output. (official documentation)

subprocess.communicate(): Interact with process: Send data to stdin. Read data from stdout and stderr, until end-of-file is reached. (official documentation)

I could view the shell file output using these both methods using Python 3.5 in an Ubuntu machine.

app.py:

import subprocess

from subprocess import Popen, PIPE

from subprocess import check_output

from flask import Flask



def get_shell_script_output_using_communicate():

    session = subprocess.Popen(['./some.sh'], stdout=PIPE, stderr=PIPE)

    stdout, stderr = session.communicate()

    if stderr:

        raise Exception("Error "+str(stderr))

    return stdout.decode('utf-8')



def get_shell_script_output_using_check_output():

    stdout = check_output(['./some.sh']).decode('utf-8')

    return stdout



app = Flask(__name__)



@app.route('/',methods=['GET',])

def home():

    return '<pre>'+get_shell_script_output_using_check_output()+'</pre>'



app.run(debug=True)

some.sh:

#!/bin/bash

echo "hi from shell script"

echo "hello from shell script"

Output screenshot:

enter image description here

answered Nov 19 '18 at 19:55

arsho

3,28911531

add a comment |

To show command output inside Python, there are two popular methods:

check_output(): It runs command with arguments and return its output. (official documentation)

subprocess.communicate(): Interact with process: Send data to stdin. Read data from stdout and stderr, until end-of-file is reached. (official documentation)

I could view the shell file output using these both methods using Python 3.5 in an Ubuntu machine.

app.py:

import subprocess

from subprocess import Popen, PIPE

from subprocess import check_output

from flask import Flask



def get_shell_script_output_using_communicate():

    session = subprocess.Popen(['./some.sh'], stdout=PIPE, stderr=PIPE)

    stdout, stderr = session.communicate()

    if stderr:

        raise Exception("Error "+str(stderr))

    return stdout.decode('utf-8')



def get_shell_script_output_using_check_output():

    stdout = check_output(['./some.sh']).decode('utf-8')

    return stdout



app = Flask(__name__)



@app.route('/',methods=['GET',])

def home():

    return '<pre>'+get_shell_script_output_using_check_output()+'</pre>'



app.run(debug=True)

some.sh:

#!/bin/bash

echo "hi from shell script"

echo "hello from shell script"

Output screenshot:

enter image description here

answered Nov 19 '18 at 19:55

arsho

3,28911531

To show command output inside Python, there are two popular methods:

check_output(): It runs command with arguments and return its output. (official documentation)

subprocess.communicate(): Interact with process: Send data to stdin. Read data from stdout and stderr, until end-of-file is reached. (official documentation)

I could view the shell file output using these both methods using Python 3.5 in an Ubuntu machine.

app.py:

import subprocess

from subprocess import Popen, PIPE

from subprocess import check_output

from flask import Flask



def get_shell_script_output_using_communicate():

    session = subprocess.Popen(['./some.sh'], stdout=PIPE, stderr=PIPE)

    stdout, stderr = session.communicate()

    if stderr:

        raise Exception("Error "+str(stderr))

    return stdout.decode('utf-8')



def get_shell_script_output_using_check_output():

    stdout = check_output(['./some.sh']).decode('utf-8')

    return stdout



app = Flask(__name__)



@app.route('/',methods=['GET',])

def home():

    return '<pre>'+get_shell_script_output_using_check_output()+'</pre>'



app.run(debug=True)

some.sh:

#!/bin/bash

echo "hi from shell script"

echo "hello from shell script"

Output screenshot:

enter image description here

answered Nov 19 '18 at 19:55

arsho

3,28911531

answered Nov 19 '18 at 19:55

arsho

3,28911531

answered Nov 19 '18 at 19:55

arsho

3,28911531

answered Nov 19 '18 at 19:55

arsho

3,28911531

add a comment |

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