Create Multiple 2x2 Tables
I need to create multiple 2x2 tables across many variables.
sample data:
Month <- c("Jan", "Feb", "March", "April")
Quiz1 <- c("90", "80", "100", "70")
Quiz2 <- c("100", "70", "50", "20")
Quiz3 <- c("60", "35", "26", "80")
df <- data.frame(Month, Quiz1, Quiz2, Quiz3)
What I would like to do is get a 2x2 of each of each quiz by month and then save it in a csv so that I can create bar graphs - pie charts, etc in excel and they need to be distributed with non R users. It can be the same CSV or multiple ones, that does not matter. This is how I have been doing it (there are close to 20 quizes) but I know there has got to be a more efficient way.
Quiz1 <- table(df$Month, df$Quiz1)
Quiz2 <- table(df$Month, df$Quiz2)
Quiz3 <- table(df$Month, df$Quiz3)
write.csv(Quiz1, "filepath...")
write.csv(Quiz2, "filepath...")
write.csv(Quiz3, "filepath...")
I found this answer: loop for tabulation of variables in data frame and it would work great except it is just for frequency tables and I'm not sure how to adapt it for this scenario and I don't have enough points to leave a comment.
Thank you in advance for any help!
r
add a comment |
I need to create multiple 2x2 tables across many variables.
sample data:
Month <- c("Jan", "Feb", "March", "April")
Quiz1 <- c("90", "80", "100", "70")
Quiz2 <- c("100", "70", "50", "20")
Quiz3 <- c("60", "35", "26", "80")
df <- data.frame(Month, Quiz1, Quiz2, Quiz3)
What I would like to do is get a 2x2 of each of each quiz by month and then save it in a csv so that I can create bar graphs - pie charts, etc in excel and they need to be distributed with non R users. It can be the same CSV or multiple ones, that does not matter. This is how I have been doing it (there are close to 20 quizes) but I know there has got to be a more efficient way.
Quiz1 <- table(df$Month, df$Quiz1)
Quiz2 <- table(df$Month, df$Quiz2)
Quiz3 <- table(df$Month, df$Quiz3)
write.csv(Quiz1, "filepath...")
write.csv(Quiz2, "filepath...")
write.csv(Quiz3, "filepath...")
I found this answer: loop for tabulation of variables in data frame and it would work great except it is just for frequency tables and I'm not sure how to adapt it for this scenario and I don't have enough points to leave a comment.
Thank you in advance for any help!
r
add a comment |
I need to create multiple 2x2 tables across many variables.
sample data:
Month <- c("Jan", "Feb", "March", "April")
Quiz1 <- c("90", "80", "100", "70")
Quiz2 <- c("100", "70", "50", "20")
Quiz3 <- c("60", "35", "26", "80")
df <- data.frame(Month, Quiz1, Quiz2, Quiz3)
What I would like to do is get a 2x2 of each of each quiz by month and then save it in a csv so that I can create bar graphs - pie charts, etc in excel and they need to be distributed with non R users. It can be the same CSV or multiple ones, that does not matter. This is how I have been doing it (there are close to 20 quizes) but I know there has got to be a more efficient way.
Quiz1 <- table(df$Month, df$Quiz1)
Quiz2 <- table(df$Month, df$Quiz2)
Quiz3 <- table(df$Month, df$Quiz3)
write.csv(Quiz1, "filepath...")
write.csv(Quiz2, "filepath...")
write.csv(Quiz3, "filepath...")
I found this answer: loop for tabulation of variables in data frame and it would work great except it is just for frequency tables and I'm not sure how to adapt it for this scenario and I don't have enough points to leave a comment.
Thank you in advance for any help!
r
I need to create multiple 2x2 tables across many variables.
sample data:
Month <- c("Jan", "Feb", "March", "April")
Quiz1 <- c("90", "80", "100", "70")
Quiz2 <- c("100", "70", "50", "20")
Quiz3 <- c("60", "35", "26", "80")
df <- data.frame(Month, Quiz1, Quiz2, Quiz3)
What I would like to do is get a 2x2 of each of each quiz by month and then save it in a csv so that I can create bar graphs - pie charts, etc in excel and they need to be distributed with non R users. It can be the same CSV or multiple ones, that does not matter. This is how I have been doing it (there are close to 20 quizes) but I know there has got to be a more efficient way.
Quiz1 <- table(df$Month, df$Quiz1)
Quiz2 <- table(df$Month, df$Quiz2)
Quiz3 <- table(df$Month, df$Quiz3)
write.csv(Quiz1, "filepath...")
write.csv(Quiz2, "filepath...")
write.csv(Quiz3, "filepath...")
I found this answer: loop for tabulation of variables in data frame and it would work great except it is just for frequency tables and I'm not sure how to adapt it for this scenario and I don't have enough points to leave a comment.
Thank you in advance for any help!
r
r
asked Nov 19 '18 at 19:11
user7777508user7777508
5617
5617
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
We can use lapply
to loop through the columns except the 'Month' column, then get the table
of the 'Month' with the looped column. The output will be a list
of tables
lst <- lapply(df[-1], function(x) table(df$Month, x))
names(lst) <- paste0("Quiz", seq_along(lst))
Instead of creating several global variables, a single list
would serve the purpose. After the transformations, then use write.csv
to write into different files
lapply(names(lst), function(x) write.csv(lst[[x]], file = paste0(x, ".csv"))
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
@user7777508 If you have adata.frame
, it should work fine as the columns have equal length
– akrun
Nov 19 '18 at 19:28
1
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
We can use lapply
to loop through the columns except the 'Month' column, then get the table
of the 'Month' with the looped column. The output will be a list
of tables
lst <- lapply(df[-1], function(x) table(df$Month, x))
names(lst) <- paste0("Quiz", seq_along(lst))
Instead of creating several global variables, a single list
would serve the purpose. After the transformations, then use write.csv
to write into different files
lapply(names(lst), function(x) write.csv(lst[[x]], file = paste0(x, ".csv"))
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
@user7777508 If you have adata.frame
, it should work fine as the columns have equal length
– akrun
Nov 19 '18 at 19:28
1
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
add a comment |
We can use lapply
to loop through the columns except the 'Month' column, then get the table
of the 'Month' with the looped column. The output will be a list
of tables
lst <- lapply(df[-1], function(x) table(df$Month, x))
names(lst) <- paste0("Quiz", seq_along(lst))
Instead of creating several global variables, a single list
would serve the purpose. After the transformations, then use write.csv
to write into different files
lapply(names(lst), function(x) write.csv(lst[[x]], file = paste0(x, ".csv"))
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
@user7777508 If you have adata.frame
, it should work fine as the columns have equal length
– akrun
Nov 19 '18 at 19:28
1
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
add a comment |
We can use lapply
to loop through the columns except the 'Month' column, then get the table
of the 'Month' with the looped column. The output will be a list
of tables
lst <- lapply(df[-1], function(x) table(df$Month, x))
names(lst) <- paste0("Quiz", seq_along(lst))
Instead of creating several global variables, a single list
would serve the purpose. After the transformations, then use write.csv
to write into different files
lapply(names(lst), function(x) write.csv(lst[[x]], file = paste0(x, ".csv"))
We can use lapply
to loop through the columns except the 'Month' column, then get the table
of the 'Month' with the looped column. The output will be a list
of tables
lst <- lapply(df[-1], function(x) table(df$Month, x))
names(lst) <- paste0("Quiz", seq_along(lst))
Instead of creating several global variables, a single list
would serve the purpose. After the transformations, then use write.csv
to write into different files
lapply(names(lst), function(x) write.csv(lst[[x]], file = paste0(x, ".csv"))
edited Nov 19 '18 at 19:21
answered Nov 19 '18 at 19:12
akrunakrun
399k13187262
399k13187262
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
@user7777508 If you have adata.frame
, it should work fine as the columns have equal length
– akrun
Nov 19 '18 at 19:28
1
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
add a comment |
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
@user7777508 If you have adata.frame
, it should work fine as the columns have equal length
– akrun
Nov 19 '18 at 19:28
1
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
This works on the example data I have posted above but when I try to run this on the larger dataset with all of the quizes I am getting this error: "error in table(df$Month, x): all arguments must have the same length"
– user7777508
Nov 19 '18 at 19:27
@user7777508 If you have a
data.frame
, it should work fine as the columns have equal length– akrun
Nov 19 '18 at 19:28
@user7777508 If you have a
data.frame
, it should work fine as the columns have equal length– akrun
Nov 19 '18 at 19:28
1
1
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
Great that worked perfectly! Thanks for your help.
– user7777508
Nov 19 '18 at 19:54
add a comment |
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