How to insert a string every n words?

I need help with text. I got a code which for example finds if the line has even number of words, then it finds every 2nd word in a text file. The problem is i don't know how to append a string to that every 2nd word and print it out.

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Collections;

using System.IO;



namespace sd

{

class Program

{

    const string CFd = "..\..\A.txt";

    const string CFr = "..\..\Rezults.txt";



    static void Main(string args)

    {





        Apdoroti(CFd, CFr);

        Console.WriteLine();



        }

    static void Apdoroti(string fd, string fr)

    {

        string lines = File.ReadAllLines(fd, Encoding.GetEncoding(1257));

        using (var far = File.CreateText(fr))

        {

                StringBuilder news = new StringBuilder();

                VD(CFd,news);

                far.WriteLine(news);



        }

    }





    static void VD(string fv, StringBuilder news)

    {

        using (StreamReader reader = new StreamReader(fv,

        Encoding.GetEncoding(1257)))

        {

            string lines = File.ReadAllLines(fv, Encoding.GetEncoding(1257));

            int nrl;

            int prad = 1;

            foreach (string line in lines)

            {

                nrl = line.Trim().Split(' ').Count();

                string parts = line.Split(' ');

                if (nrl % 2 == 0)

                {

                    Console.WriteLine(nrl);

                    for (int i = 0; i < nrl; i += 2)

                    {

                        int ind = line.IndexOf(parts[i]);

                        nauja.Append(parts[i]);

                        Console.WriteLine(" {0} ", news);

                    }



                }

            }

        }

    }



}

}

For example if i got a text like:
"Monster in the Jungle Once upon a time a wise lion lived in jungle.
He was always respected for his intelligence and kindness."

Then it should print out:
"Monster in abb the Jungle abb Once upon abb a time abb a wise abb lion lived abb in jungle.
He was always respected for his intelligence and kindness."

edited Nov 19 '18 at 19:17

asked Nov 19 '18 at 18:34

Scr1pt25

304

It is so hard to follow your existing code. What does VD() mean? What does fv mean? You really need to work on your naming
– maccettura
Nov 19 '18 at 18:41

ill give my full code
– Scr1pt25
Nov 19 '18 at 18:46

I think you mean even number of words.
– paparazzo
Nov 19 '18 at 19:07

add a comment |

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Collections;

using System.IO;



namespace sd

{

class Program

{

    const string CFd = "..\..\A.txt";

    const string CFr = "..\..\Rezults.txt";



    static void Main(string args)

    {





        Apdoroti(CFd, CFr);

        Console.WriteLine();



        }

    static void Apdoroti(string fd, string fr)

    {

        string lines = File.ReadAllLines(fd, Encoding.GetEncoding(1257));

        using (var far = File.CreateText(fr))

        {

                StringBuilder news = new StringBuilder();

                VD(CFd,news);

                far.WriteLine(news);



        }

    }





    static void VD(string fv, StringBuilder news)

    {

        using (StreamReader reader = new StreamReader(fv,

        Encoding.GetEncoding(1257)))

        {

            string lines = File.ReadAllLines(fv, Encoding.GetEncoding(1257));

            int nrl;

            int prad = 1;

            foreach (string line in lines)

            {

                nrl = line.Trim().Split(' ').Count();

                string parts = line.Split(' ');

                if (nrl % 2 == 0)

                {

                    Console.WriteLine(nrl);

                    for (int i = 0; i < nrl; i += 2)

                    {

                        int ind = line.IndexOf(parts[i]);

                        nauja.Append(parts[i]);

                        Console.WriteLine(" {0} ", news);

                    }



                }

            }

        }

    }



}

}

For example if i got a text like:
"Monster in the Jungle Once upon a time a wise lion lived in jungle.
He was always respected for his intelligence and kindness."

Then it should print out:
"Monster in abb the Jungle abb Once upon abb a time abb a wise abb lion lived abb in jungle.
He was always respected for his intelligence and kindness."

edited Nov 19 '18 at 19:17

asked Nov 19 '18 at 18:34

Scr1pt25

304

It is so hard to follow your existing code. What does VD() mean? What does fv mean? You really need to work on your naming
– maccettura
Nov 19 '18 at 18:41

ill give my full code
– Scr1pt25
Nov 19 '18 at 18:46

I think you mean even number of words.
– paparazzo
Nov 19 '18 at 19:07

add a comment |

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Collections;

using System.IO;



namespace sd

{

class Program

{

    const string CFd = "..\..\A.txt";

    const string CFr = "..\..\Rezults.txt";



    static void Main(string args)

    {





        Apdoroti(CFd, CFr);

        Console.WriteLine();



        }

    static void Apdoroti(string fd, string fr)

    {

        string lines = File.ReadAllLines(fd, Encoding.GetEncoding(1257));

        using (var far = File.CreateText(fr))

        {

                StringBuilder news = new StringBuilder();

                VD(CFd,news);

                far.WriteLine(news);



        }

    }





    static void VD(string fv, StringBuilder news)

    {

        using (StreamReader reader = new StreamReader(fv,

        Encoding.GetEncoding(1257)))

        {

            string lines = File.ReadAllLines(fv, Encoding.GetEncoding(1257));

            int nrl;

            int prad = 1;

            foreach (string line in lines)

            {

                nrl = line.Trim().Split(' ').Count();

                string parts = line.Split(' ');

                if (nrl % 2 == 0)

                {

                    Console.WriteLine(nrl);

                    for (int i = 0; i < nrl; i += 2)

                    {

                        int ind = line.IndexOf(parts[i]);

                        nauja.Append(parts[i]);

                        Console.WriteLine(" {0} ", news);

                    }



                }

            }

        }

    }



}

}

For example if i got a text like:
"Monster in the Jungle Once upon a time a wise lion lived in jungle.
He was always respected for his intelligence and kindness."

Then it should print out:
"Monster in abb the Jungle abb Once upon abb a time abb a wise abb lion lived abb in jungle.
He was always respected for his intelligence and kindness."

edited Nov 19 '18 at 19:17

asked Nov 19 '18 at 18:34

Scr1pt25

304

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Collections;

using System.IO;



namespace sd

{

class Program

{

    const string CFd = "..\..\A.txt";

    const string CFr = "..\..\Rezults.txt";



    static void Main(string args)

    {





        Apdoroti(CFd, CFr);

        Console.WriteLine();



        }

    static void Apdoroti(string fd, string fr)

    {

        string lines = File.ReadAllLines(fd, Encoding.GetEncoding(1257));

        using (var far = File.CreateText(fr))

        {

                StringBuilder news = new StringBuilder();

                VD(CFd,news);

                far.WriteLine(news);



        }

    }





    static void VD(string fv, StringBuilder news)

    {

        using (StreamReader reader = new StreamReader(fv,

        Encoding.GetEncoding(1257)))

        {

            string lines = File.ReadAllLines(fv, Encoding.GetEncoding(1257));

            int nrl;

            int prad = 1;

            foreach (string line in lines)

            {

                nrl = line.Trim().Split(' ').Count();

                string parts = line.Split(' ');

                if (nrl % 2 == 0)

                {

                    Console.WriteLine(nrl);

                    for (int i = 0; i < nrl; i += 2)

                    {

                        int ind = line.IndexOf(parts[i]);

                        nauja.Append(parts[i]);

                        Console.WriteLine(" {0} ", news);

                    }



                }

            }

        }

    }



}

}

For example if i got a text like:
"Monster in the Jungle Once upon a time a wise lion lived in jungle.
He was always respected for his intelligence and kindness."

Then it should print out:
"Monster in abb the Jungle abb Once upon abb a time abb a wise abb lion lived abb in jungle.
He was always respected for his intelligence and kindness."

edited Nov 19 '18 at 19:17

asked Nov 19 '18 at 18:34

Scr1pt25

304

edited Nov 19 '18 at 19:17

asked Nov 19 '18 at 18:34

Scr1pt25

304

edited Nov 19 '18 at 19:17

asked Nov 19 '18 at 18:34

Scr1pt25

304

asked Nov 19 '18 at 18:34

Scr1pt25

304

asked Nov 19 '18 at 18:34

Scr1pt25

304

It is so hard to follow your existing code. What does VD() mean? What does fv mean? You really need to work on your naming
– maccettura
Nov 19 '18 at 18:41

ill give my full code
– Scr1pt25
Nov 19 '18 at 18:46

I think you mean even number of words.
– paparazzo
Nov 19 '18 at 19:07

add a comment |

It is so hard to follow your existing code. What does VD() mean? What does fv mean? You really need to work on your naming
– maccettura
Nov 19 '18 at 18:41

ill give my full code
– Scr1pt25
Nov 19 '18 at 18:46

I think you mean even number of words.
– paparazzo
Nov 19 '18 at 19:07

It is so hard to follow your existing code. What does VD() mean? What does fv mean? You really need to work on your naming
– maccettura
Nov 19 '18 at 18:41

ill give my full code
– Scr1pt25
Nov 19 '18 at 18:46

I think you mean even number of words.
– paparazzo
Nov 19 '18 at 19:07

add a comment |

2 Answers
2

active

oldest

votes

You can do it with a regex replace, like this regex:

@"w+sw+s"

It maches a Word, a Space, a Word and a Space.

Now replace it with:

"$&abb "

How to use:

using System.Text.RegularExpressions;



string text =  "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

Regex regex = new Regex(@"w+sw+s");

string output = regex.Replace(text, "$&abb ");

Now you will get the desired output.

Edit:

To Work with any number of Words, you can use:

@"(w+s){3}"

where the quantifier (here 3) can be set to whatever you want.

Edit2:

If you don't want to replace numbers:

@"([a-zA-Z]+s){2}"

edited Nov 20 '18 at 2:56

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

Thank you a lot, but what if there are numbers in the text, how can you make it so that it would skip them?
– Scr1pt25
Nov 19 '18 at 19:17

add a comment |

You can use linq, first parse the line on spaces to get a list of words (you are doing) and then for every odd element add the text required, finally convert the array back into a string.

    string test = "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

    var words = test.Split(' ');

    var wordArray = words.Select((w, i) => 

        (i % 2 != 0) ? (w+ " asd ")   : (w + " ")

    ).ToArray();



    var res = string.Join("", wordArray);

Also this can be easily changed to insert after every n words by changing the mod function. Do remember that array index will start at 0 though.

answered Nov 20 '18 at 3:56

peeyush singh

352210

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You can do it with a regex replace, like this regex:

@"w+sw+s"

It maches a Word, a Space, a Word and a Space.

Now replace it with:

"$&abb "

How to use:

using System.Text.RegularExpressions;



string text =  "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

Regex regex = new Regex(@"w+sw+s");

string output = regex.Replace(text, "$&abb ");

Now you will get the desired output.

Edit:

To Work with any number of Words, you can use:

@"(w+s){3}"

where the quantifier (here 3) can be set to whatever you want.

Edit2:

If you don't want to replace numbers:

@"([a-zA-Z]+s){2}"

edited Nov 20 '18 at 2:56

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

Thank you a lot, but what if there are numbers in the text, how can you make it so that it would skip them?
– Scr1pt25
Nov 19 '18 at 19:17

add a comment |

You can do it with a regex replace, like this regex:

@"w+sw+s"

It maches a Word, a Space, a Word and a Space.

Now replace it with:

"$&abb "

How to use:

using System.Text.RegularExpressions;



string text =  "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

Regex regex = new Regex(@"w+sw+s");

string output = regex.Replace(text, "$&abb ");

Now you will get the desired output.

Edit:

To Work with any number of Words, you can use:

@"(w+s){3}"

where the quantifier (here 3) can be set to whatever you want.

Edit2:

If you don't want to replace numbers:

@"([a-zA-Z]+s){2}"

edited Nov 20 '18 at 2:56

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

Thank you a lot, but what if there are numbers in the text, how can you make it so that it would skip them?
– Scr1pt25
Nov 19 '18 at 19:17

add a comment |

You can do it with a regex replace, like this regex:

@"w+sw+s"

It maches a Word, a Space, a Word and a Space.

Now replace it with:

"$&abb "

How to use:

using System.Text.RegularExpressions;



string text =  "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

Regex regex = new Regex(@"w+sw+s");

string output = regex.Replace(text, "$&abb ");

Now you will get the desired output.

Edit:

To Work with any number of Words, you can use:

@"(w+s){3}"

where the quantifier (here 3) can be set to whatever you want.

Edit2:

If you don't want to replace numbers:

@"([a-zA-Z]+s){2}"

edited Nov 20 '18 at 2:56

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

You can do it with a regex replace, like this regex:

@"w+sw+s"

It maches a Word, a Space, a Word and a Space.

Now replace it with:

"$&abb "

How to use:

using System.Text.RegularExpressions;



string text =  "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

Regex regex = new Regex(@"w+sw+s");

string output = regex.Replace(text, "$&abb ");

Now you will get the desired output.

Edit:

To Work with any number of Words, you can use:

@"(w+s){3}"

where the quantifier (here 3) can be set to whatever you want.

Edit2:

If you don't want to replace numbers:

@"([a-zA-Z]+s){2}"

edited Nov 20 '18 at 2:56

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

edited Nov 20 '18 at 2:56

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

answered Nov 19 '18 at 18:49

Poul Bak

5,44331232

Thank you a lot, but what if there are numbers in the text, how can you make it so that it would skip them?
– Scr1pt25
Nov 19 '18 at 19:17

add a comment |

Thank you a lot, but what if there are numbers in the text, how can you make it so that it would skip them?
– Scr1pt25
Nov 19 '18 at 19:17

Thank you a lot, but what if there are numbers in the text, how can you make it so that it would skip them?
– Scr1pt25
Nov 19 '18 at 19:17

add a comment |

You can use linq, first parse the line on spaces to get a list of words (you are doing) and then for every odd element add the text required, finally convert the array back into a string.

    string test = "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

    var words = test.Split(' ');

    var wordArray = words.Select((w, i) => 

        (i % 2 != 0) ? (w+ " asd ")   : (w + " ")

    ).ToArray();



    var res = string.Join("", wordArray);

Also this can be easily changed to insert after every n words by changing the mod function. Do remember that array index will start at 0 though.

answered Nov 20 '18 at 3:56

peeyush singh

352210

add a comment |

You can use linq, first parse the line on spaces to get a list of words (you are doing) and then for every odd element add the text required, finally convert the array back into a string.

    string test = "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

    var words = test.Split(' ');

    var wordArray = words.Select((w, i) => 

        (i % 2 != 0) ? (w+ " asd ")   : (w + " ")

    ).ToArray();



    var res = string.Join("", wordArray);

Also this can be easily changed to insert after every n words by changing the mod function. Do remember that array index will start at 0 though.

answered Nov 20 '18 at 3:56

peeyush singh

352210

add a comment |

You can use linq, first parse the line on spaces to get a list of words (you are doing) and then for every odd element add the text required, finally convert the array back into a string.

    string test = "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

    var words = test.Split(' ');

    var wordArray = words.Select((w, i) => 

        (i % 2 != 0) ? (w+ " asd ")   : (w + " ")

    ).ToArray();



    var res = string.Join("", wordArray);

Also this can be easily changed to insert after every n words by changing the mod function. Do remember that array index will start at 0 though.

answered Nov 20 '18 at 3:56

peeyush singh

352210

You can use linq, first parse the line on spaces to get a list of words (you are doing) and then for every odd element add the text required, finally convert the array back into a string.

    string test = "Monster in the Jungle Once upon a time a wise lion lived in jungle. He was always respected for his intelligence and kindness.";

    var words = test.Split(' ');

    var wordArray = words.Select((w, i) => 

        (i % 2 != 0) ? (w+ " asd ")   : (w + " ")

    ).ToArray();



    var res = string.Join("", wordArray);

Also this can be easily changed to insert after every n words by changing the mod function. Do remember that array index will start at 0 though.

answered Nov 20 '18 at 3:56

peeyush singh

352210

answered Nov 20 '18 at 3:56

peeyush singh

352210

answered Nov 20 '18 at 3:56

peeyush singh

352210

answered Nov 20 '18 at 3:56

peeyush singh

352210

add a comment |

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