Mixing
How to keep the state of relay
$begingroup$
In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:
How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?
relay schematics
asked Jan 7 at 12:47
newbienewbie
449
$endgroup$
add a comment |
$begingroup$
In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:
How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?
relay schematics
asked Jan 7 at 12:47
newbienewbie
449
$endgroup$
1
$begingroup$
It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
$endgroup$
– Harry Svensson
Jan 7 at 13:19
1
$begingroup$
Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
$endgroup$
– mike65535
Jan 7 at 13:24
$begingroup$
thanks @HarrySvensson found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
$begingroup$
thanks @mike65535 found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
add a comment |
$begingroup$
In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:
How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?
relay schematics
asked Jan 7 at 12:47
newbienewbie
449
$endgroup$
In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:
How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?
relay schematics
relay schematics
asked Jan 7 at 12:47
newbienewbie
449
asked Jan 7 at 12:47
newbienewbie
449
edited Jan 7 at 13:14
newbie
asked Jan 7 at 12:47
newbienewbie
449
asked Jan 7 at 12:47
newbienewbie
449
asked Jan 7 at 12:47
newbienewbie
449
449
1
$begingroup$
It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
$endgroup$
– Harry Svensson
Jan 7 at 13:19
1
$begingroup$
Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
$endgroup$
– mike65535
Jan 7 at 13:24
$begingroup$
thanks @HarrySvensson found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
$begingroup$
thanks @mike65535 found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
add a comment |
1
$begingroup$
It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
$endgroup$
– Harry Svensson
Jan 7 at 13:19
1
$begingroup$
Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
$endgroup$
– mike65535
Jan 7 at 13:24
$begingroup$
thanks @HarrySvensson found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
$begingroup$
thanks @mike65535 found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
1
1
$begingroup$
It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
$endgroup$
– Harry Svensson
Jan 7 at 13:19
$begingroup$
It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
$endgroup$
– Harry Svensson
Jan 7 at 13:19
1
1
$begingroup$
Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
$endgroup$
– mike65535
Jan 7 at 13:24
$begingroup$
Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
$endgroup$
– mike65535
Jan 7 at 13:24
$begingroup$
thanks @HarrySvensson found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
$begingroup$
thanks @HarrySvensson found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
$begingroup$
thanks @mike65535 found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
$begingroup$
thanks @mike65535 found the solution.
$endgroup$
– newbie
Jan 7 at 15:16
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).
Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.
To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:
simulate this circuit – Schematic created using CircuitLab
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
$endgroup$
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
1
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
|
show 4 more comments
$begingroup$
You can add some positive feedback, with a N.C. pushbutton in series.
For example, a diode from the op-amp output to non-inverting input. With said switch in series.
Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.
Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
$endgroup$
$begingroup$
i'm new to electronics, can you please explain with schematic?
$endgroup$
– newbie
Jan 7 at 15:41
2
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:09
add a comment |
$begingroup$
If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.
https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460
there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.
answered Jan 7 at 14:16
KorayKoray
865
$endgroup$
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).
Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.
To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:
simulate this circuit – Schematic created using CircuitLab
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
$endgroup$
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
1
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
|
show 4 more comments
$begingroup$
You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).
Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.
To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:
simulate this circuit – Schematic created using CircuitLab
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
$endgroup$
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
1
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
|
show 4 more comments
$begingroup$
You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).
Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.
To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:
simulate this circuit – Schematic created using CircuitLab
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
$endgroup$
You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).
Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.
To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:
simulate this circuit – Schematic created using CircuitLab
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
answered Jan 7 at 13:24
BimpelrekkieBimpelrekkie
48.2k240107
48.2k240107
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
1
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
|
show 4 more comments
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
1
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
$endgroup$
– Dorian
Jan 7 at 14:10
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
Oh, already sugested by Sphero
$endgroup$
– Dorian
Jan 7 at 14:12
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
$endgroup$
– Bimpelrekkie
Jan 7 at 14:15
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
$begingroup$
When you push the switch the relay will be off no matter the input.
$endgroup$
– Dorian
Jan 7 at 14:20
1
1
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
$begingroup$
@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:06
|
show 4 more comments
$begingroup$
You can add some positive feedback, with a N.C. pushbutton in series.
For example, a diode from the op-amp output to non-inverting input. With said switch in series.
Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.
Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
$endgroup$
$begingroup$
i'm new to electronics, can you please explain with schematic?
$endgroup$
– newbie
Jan 7 at 15:41
2
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:09
add a comment |
$begingroup$
You can add some positive feedback, with a N.C. pushbutton in series.
For example, a diode from the op-amp output to non-inverting input. With said switch in series.
Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.
Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
$endgroup$
$begingroup$
i'm new to electronics, can you please explain with schematic?
$endgroup$
– newbie
Jan 7 at 15:41
2
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:09
add a comment |
$begingroup$
You can add some positive feedback, with a N.C. pushbutton in series.
For example, a diode from the op-amp output to non-inverting input. With said switch in series.
Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.
Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
$endgroup$
You can add some positive feedback, with a N.C. pushbutton in series.
For example, a diode from the op-amp output to non-inverting input. With said switch in series.
Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.
Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
edited Jan 7 at 15:58
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
answered Jan 7 at 13:25
Spehro PefhanySpehro Pefhany
206k5156412
206k5156412
$begingroup$
i'm new to electronics, can you please explain with schematic?
$endgroup$
– newbie
Jan 7 at 15:41
2
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:09
add a comment |
$begingroup$
i'm new to electronics, can you please explain with schematic?
$endgroup$
– newbie
Jan 7 at 15:41
2
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
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– Bimpelrekkie
Jan 7 at 16:09
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i'm new to electronics, can you please explain with schematic?
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– newbie
Jan 7 at 15:41
$begingroup$
i'm new to electronics, can you please explain with schematic?
$endgroup$
– newbie
Jan 7 at 15:41
2
2
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:09
$begingroup$
Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
$endgroup$
– Bimpelrekkie
Jan 7 at 16:09
add a comment |
$begingroup$
If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.
https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460
there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.
answered Jan 7 at 14:16
KorayKoray
865
$endgroup$
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
add a comment |
$begingroup$
If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.
https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460
there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.
answered Jan 7 at 14:16
KorayKoray
865
$endgroup$
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
add a comment |
$begingroup$
If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.
https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460
there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.
answered Jan 7 at 14:16
KorayKoray
865
$endgroup$
If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.
https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460
there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.
answered Jan 7 at 14:16
KorayKoray
865
answered Jan 7 at 14:16
KorayKoray
865
answered Jan 7 at 14:16
KorayKoray
865
answered Jan 7 at 14:16
KorayKoray
865
865
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
add a comment |
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
$begingroup$
Sometimes called a "bistable (or bi-stable) relay".
$endgroup$
– Stobor
Jan 8 at 1:15
add a comment |
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1
$begingroup$
It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
$endgroup$
– Harry Svensson
Jan 7 at 13:19
1
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Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
$endgroup$
– mike65535
Jan 7 at 13:24
$begingroup$
thanks @HarrySvensson found the solution.
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– newbie
Jan 7 at 15:16
$begingroup$
thanks @mike65535 found the solution.
$endgroup$
– newbie
Jan 7 at 15:16