Probability that random hyperplane separates two random points












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I don't have a good intuition for the following problem:



Given three random (unit) vectors $a, b, n in mathbb{R}^d$, chosen u.a.r. as points on a unit sphere, with $n$ being the normal vector of a hyperplane $h_n$.



As the dimension $d$ increased, does the probability of $h_n$ separating $a$ from $b$ increase, decrease or stays the same?










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    1














    I don't have a good intuition for the following problem:



    Given three random (unit) vectors $a, b, n in mathbb{R}^d$, chosen u.a.r. as points on a unit sphere, with $n$ being the normal vector of a hyperplane $h_n$.



    As the dimension $d$ increased, does the probability of $h_n$ separating $a$ from $b$ increase, decrease or stays the same?










    share|cite|improve this question

























      1












      1








      1







      I don't have a good intuition for the following problem:



      Given three random (unit) vectors $a, b, n in mathbb{R}^d$, chosen u.a.r. as points on a unit sphere, with $n$ being the normal vector of a hyperplane $h_n$.



      As the dimension $d$ increased, does the probability of $h_n$ separating $a$ from $b$ increase, decrease or stays the same?










      share|cite|improve this question













      I don't have a good intuition for the following problem:



      Given three random (unit) vectors $a, b, n in mathbb{R}^d$, chosen u.a.r. as points on a unit sphere, with $n$ being the normal vector of a hyperplane $h_n$.



      As the dimension $d$ increased, does the probability of $h_n$ separating $a$ from $b$ increase, decrease or stays the same?







      geometry random-variables






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      asked Nov 22 '18 at 0:30









      stefanstefan

      4201418




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          It stays the same. Choose first the hyperplane $H$ randomly. The probability of $ain H$ or $bin H$ is $0$. The hyperplane separates the sphere in two hemisphers so in particular the probability of $a$ being in one of them is $1/2$ and the same is true for $b$. So essentially we have two independent bernoulli random variables.






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            It stays the same. Choose first the hyperplane $H$ randomly. The probability of $ain H$ or $bin H$ is $0$. The hyperplane separates the sphere in two hemisphers so in particular the probability of $a$ being in one of them is $1/2$ and the same is true for $b$. So essentially we have two independent bernoulli random variables.






            share|cite|improve this answer




























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              It stays the same. Choose first the hyperplane $H$ randomly. The probability of $ain H$ or $bin H$ is $0$. The hyperplane separates the sphere in two hemisphers so in particular the probability of $a$ being in one of them is $1/2$ and the same is true for $b$. So essentially we have two independent bernoulli random variables.






              share|cite|improve this answer


























                2












                2








                2






                It stays the same. Choose first the hyperplane $H$ randomly. The probability of $ain H$ or $bin H$ is $0$. The hyperplane separates the sphere in two hemisphers so in particular the probability of $a$ being in one of them is $1/2$ and the same is true for $b$. So essentially we have two independent bernoulli random variables.






                share|cite|improve this answer














                It stays the same. Choose first the hyperplane $H$ randomly. The probability of $ain H$ or $bin H$ is $0$. The hyperplane separates the sphere in two hemisphers so in particular the probability of $a$ being in one of them is $1/2$ and the same is true for $b$. So essentially we have two independent bernoulli random variables.







                share|cite|improve this answer














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                share|cite|improve this answer








                edited Nov 25 '18 at 16:42

























                answered Nov 22 '18 at 0:47









                Dante GrevinoDante Grevino

                94319




                94319






























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