Mixing
Probabily: Permutation of words in a sample with replacement
Form the six letters $A, B, C, D, E, F$ three letters are chosen at random with replacement. What is the probability that either the word BAD or CAD can be formed from the chosen letters.
a) $1/216$
b) $3/216$
c) $6/216$
d) $12/216$
My approach:
Possible outcomes $= 6 times 6 times 6 = 216$.
Favourable Outcome $ = 2 times 3! = 12.$
Hence Probability $= 12/216$. I am getting d). So where am I making a mistake?
Reference: CSIR NET DEC 2015 Paper A Q.No. 50
Edit: As it turns out I was checking the wrong answer key. My solution is right.
probability
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
asked Nov 20 '18 at 3:57
henceproved
1358
|
show 2 more comments
Form the six letters $A, B, C, D, E, F$ three letters are chosen at random with replacement. What is the probability that either the word BAD or CAD can be formed from the chosen letters.
a) $1/216$
b) $3/216$
c) $6/216$
d) $12/216$
My approach:
Possible outcomes $= 6 times 6 times 6 = 216$.
Favourable Outcome $ = 2 times 3! = 12.$
Hence Probability $= 12/216$. I am getting d). So where am I making a mistake?
Reference: CSIR NET DEC 2015 Paper A Q.No. 50
Edit: As it turns out I was checking the wrong answer key. My solution is right.
probability
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
asked Nov 20 '18 at 3:57
henceproved
1358
1
Looks right ... are you sure the correct answer is c?
– Bram28
Nov 20 '18 at 4:07
@Bram28 Yes, you can check for yourself, CSIR NET DEC 2015 Part A Question 50.
– henceproved
Nov 20 '18 at 4:09
Well, I still say it is d!
– Bram28
Nov 20 '18 at 4:14
@BRam28 Sorry for the confusion, I rechecked it, as it turns out I was checking the wrong answer key. Mine (as well as yours) solution is right.
– henceproved
Nov 21 '18 at 2:52
Aha! I figured :) Thanks for letting me know.
– Bram28
Nov 21 '18 at 3:39
|
show 2 more comments
Form the six letters $A, B, C, D, E, F$ three letters are chosen at random with replacement. What is the probability that either the word BAD or CAD can be formed from the chosen letters.
a) $1/216$
b) $3/216$
c) $6/216$
d) $12/216$
My approach:
Possible outcomes $= 6 times 6 times 6 = 216$.
Favourable Outcome $ = 2 times 3! = 12.$
Hence Probability $= 12/216$. I am getting d). So where am I making a mistake?
Reference: CSIR NET DEC 2015 Paper A Q.No. 50
Edit: As it turns out I was checking the wrong answer key. My solution is right.
probability
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
asked Nov 20 '18 at 3:57
henceproved
1358
Form the six letters $A, B, C, D, E, F$ three letters are chosen at random with replacement. What is the probability that either the word BAD or CAD can be formed from the chosen letters.
a) $1/216$
b) $3/216$
c) $6/216$
d) $12/216$
My approach:
Possible outcomes $= 6 times 6 times 6 = 216$.
Favourable Outcome $ = 2 times 3! = 12.$
Hence Probability $= 12/216$. I am getting d). So where am I making a mistake?
Reference: CSIR NET DEC 2015 Paper A Q.No. 50
Edit: As it turns out I was checking the wrong answer key. My solution is right.
probability
probability
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
asked Nov 20 '18 at 3:57
henceproved
1358
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
asked Nov 20 '18 at 3:57
henceproved
1358
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
edited Nov 21 '18 at 15:46
N. F. Taussig
43.5k93355
43.5k93355
asked Nov 20 '18 at 3:57
henceproved
1358
asked Nov 20 '18 at 3:57
henceproved
1358
asked Nov 20 '18 at 3:57
henceproved
1358
1358
1
Looks right ... are you sure the correct answer is c?
– Bram28
Nov 20 '18 at 4:07
@Bram28 Yes, you can check for yourself, CSIR NET DEC 2015 Part A Question 50.
– henceproved
Nov 20 '18 at 4:09
Well, I still say it is d!
– Bram28
Nov 20 '18 at 4:14
@BRam28 Sorry for the confusion, I rechecked it, as it turns out I was checking the wrong answer key. Mine (as well as yours) solution is right.
– henceproved
Nov 21 '18 at 2:52
Aha! I figured :) Thanks for letting me know.
– Bram28
Nov 21 '18 at 3:39
|
show 2 more comments
1
Looks right ... are you sure the correct answer is c?
– Bram28
Nov 20 '18 at 4:07
@Bram28 Yes, you can check for yourself, CSIR NET DEC 2015 Part A Question 50.
– henceproved
Nov 20 '18 at 4:09
Well, I still say it is d!
– Bram28
Nov 20 '18 at 4:14
@BRam28 Sorry for the confusion, I rechecked it, as it turns out I was checking the wrong answer key. Mine (as well as yours) solution is right.
– henceproved
Nov 21 '18 at 2:52
Aha! I figured :) Thanks for letting me know.
– Bram28
Nov 21 '18 at 3:39
1
1
Looks right ... are you sure the correct answer is c?
– Bram28
Nov 20 '18 at 4:07
Looks right ... are you sure the correct answer is c?
– Bram28
Nov 20 '18 at 4:07
@Bram28 Yes, you can check for yourself, CSIR NET DEC 2015 Part A Question 50.
– henceproved
Nov 20 '18 at 4:09
@Bram28 Yes, you can check for yourself, CSIR NET DEC 2015 Part A Question 50.
– henceproved
Nov 20 '18 at 4:09
Well, I still say it is d!
– Bram28
Nov 20 '18 at 4:14
Well, I still say it is d!
– Bram28
Nov 20 '18 at 4:14
@BRam28 Sorry for the confusion, I rechecked it, as it turns out I was checking the wrong answer key. Mine (as well as yours) solution is right.
– henceproved
Nov 21 '18 at 2:52
@BRam28 Sorry for the confusion, I rechecked it, as it turns out I was checking the wrong answer key. Mine (as well as yours) solution is right.
– henceproved
Nov 21 '18 at 2:52
Aha! I figured :) Thanks for letting me know.
– Bram28
Nov 21 '18 at 3:39
Aha! I figured :) Thanks for letting me know.
– Bram28
Nov 21 '18 at 3:39
|
show 2 more comments
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1
Looks right ... are you sure the correct answer is c?
– Bram28
Nov 20 '18 at 4:07
@Bram28 Yes, you can check for yourself, CSIR NET DEC 2015 Part A Question 50.
– henceproved
Nov 20 '18 at 4:09
Well, I still say it is d!
– Bram28
Nov 20 '18 at 4:14
@BRam28 Sorry for the confusion, I rechecked it, as it turns out I was checking the wrong answer key. Mine (as well as yours) solution is right.
– henceproved
Nov 21 '18 at 2:52
Aha! I figured :) Thanks for letting me know.
– Bram28
Nov 21 '18 at 3:39