Mixing
rxjava - how to take alternating emissions from two observables
I have two observables and i would like to take from each one until there is nothing left from both. is there any operator to do this ? let me show you an example of what i have tried and what i want to accomplish:
Observable<String> observable = Observable.just("hello","are", "doing");
Observable<String> observable2 = Observable.just("how","you","today");
i would like to "reduce" this such that the final emissions would be"
Hello how are you doing today
here i have tried using scan but it works more like accumulation and i get the following results:
Observable.merge(observable, observable2).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String wordAccum1, String word2) {
return wordAccum1 + " " + word2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String sentence) throws Exception {
Log.v("consumerResult",sentence+"");
}
});
log output shows:
consumerResult: hello are doing how you today
how can i take from each one consecutively ?
rx-java2
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
add a comment |
I have two observables and i would like to take from each one until there is nothing left from both. is there any operator to do this ? let me show you an example of what i have tried and what i want to accomplish:
Observable<String> observable = Observable.just("hello","are", "doing");
Observable<String> observable2 = Observable.just("how","you","today");
i would like to "reduce" this such that the final emissions would be"
Hello how are you doing today
here i have tried using scan but it works more like accumulation and i get the following results:
Observable.merge(observable, observable2).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String wordAccum1, String word2) {
return wordAccum1 + " " + word2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String sentence) throws Exception {
Log.v("consumerResult",sentence+"");
}
});
log output shows:
consumerResult: hello are doing how you today
how can i take from each one consecutively ?
rx-java2
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
add a comment |
I have two observables and i would like to take from each one until there is nothing left from both. is there any operator to do this ? let me show you an example of what i have tried and what i want to accomplish:
Observable<String> observable = Observable.just("hello","are", "doing");
Observable<String> observable2 = Observable.just("how","you","today");
i would like to "reduce" this such that the final emissions would be"
Hello how are you doing today
here i have tried using scan but it works more like accumulation and i get the following results:
Observable.merge(observable, observable2).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String wordAccum1, String word2) {
return wordAccum1 + " " + word2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String sentence) throws Exception {
Log.v("consumerResult",sentence+"");
}
});
log output shows:
consumerResult: hello are doing how you today
how can i take from each one consecutively ?
rx-java2
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
I have two observables and i would like to take from each one until there is nothing left from both. is there any operator to do this ? let me show you an example of what i have tried and what i want to accomplish:
Observable<String> observable = Observable.just("hello","are", "doing");
Observable<String> observable2 = Observable.just("how","you","today");
i would like to "reduce" this such that the final emissions would be"
Hello how are you doing today
here i have tried using scan but it works more like accumulation and i get the following results:
Observable.merge(observable, observable2).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String wordAccum1, String word2) {
return wordAccum1 + " " + word2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String sentence) throws Exception {
Log.v("consumerResult",sentence+"");
}
});
log output shows:
consumerResult: hello are doing how you today
how can i take from each one consecutively ?
rx-java2
rx-java2
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
edited Nov 19 '18 at 15:30
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
asked Nov 19 '18 at 12:20
j2emanue
21.6k24139249
21.6k24139249
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Try this
Observable<String> observable = Observable.just("hello", "are", "doing");
Observable<String> observable2 = Observable.just("how", "you", "today");
observable.zipWith(observable2, new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+" "+s2;
}
}).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+ " " + s2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
System.out.println(s); // this will emit with "hello how are you doing today"
}
});
If you are using Java 8, you can reduce the same code using lambda, as follows
observable.zipWith(observable2, (s, s2) -> s + " " + s2)
.reduce((s, s2) -> s +" "+ s2).subscribe(System.out::println);
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
1
The key iszipWith. You don't needscan+lastElement,reducesuffices.
– akarnokd
Nov 19 '18 at 14:10
@akarnokd updated the answer withreduce
– Sarath Kn
Nov 19 '18 at 14:15
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this
Observable<String> observable = Observable.just("hello", "are", "doing");
Observable<String> observable2 = Observable.just("how", "you", "today");
observable.zipWith(observable2, new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+" "+s2;
}
}).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+ " " + s2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
System.out.println(s); // this will emit with "hello how are you doing today"
}
});
If you are using Java 8, you can reduce the same code using lambda, as follows
observable.zipWith(observable2, (s, s2) -> s + " " + s2)
.reduce((s, s2) -> s +" "+ s2).subscribe(System.out::println);
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
1
The key iszipWith. You don't needscan+lastElement,reducesuffices.
– akarnokd
Nov 19 '18 at 14:10
@akarnokd updated the answer withreduce
– Sarath Kn
Nov 19 '18 at 14:15
add a comment |
Try this
Observable<String> observable = Observable.just("hello", "are", "doing");
Observable<String> observable2 = Observable.just("how", "you", "today");
observable.zipWith(observable2, new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+" "+s2;
}
}).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+ " " + s2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
System.out.println(s); // this will emit with "hello how are you doing today"
}
});
If you are using Java 8, you can reduce the same code using lambda, as follows
observable.zipWith(observable2, (s, s2) -> s + " " + s2)
.reduce((s, s2) -> s +" "+ s2).subscribe(System.out::println);
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
1
The key iszipWith. You don't needscan+lastElement,reducesuffices.
– akarnokd
Nov 19 '18 at 14:10
@akarnokd updated the answer withreduce
– Sarath Kn
Nov 19 '18 at 14:15
add a comment |
Try this
Observable<String> observable = Observable.just("hello", "are", "doing");
Observable<String> observable2 = Observable.just("how", "you", "today");
observable.zipWith(observable2, new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+" "+s2;
}
}).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+ " " + s2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
System.out.println(s); // this will emit with "hello how are you doing today"
}
});
If you are using Java 8, you can reduce the same code using lambda, as follows
observable.zipWith(observable2, (s, s2) -> s + " " + s2)
.reduce((s, s2) -> s +" "+ s2).subscribe(System.out::println);
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
Try this
Observable<String> observable = Observable.just("hello", "are", "doing");
Observable<String> observable2 = Observable.just("how", "you", "today");
observable.zipWith(observable2, new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+" "+s2;
}
}).reduce(new BiFunction<String, String, String>() {
@Override
public String apply(String s, String s2) throws Exception {
return s+ " " + s2;
}
}).subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
System.out.println(s); // this will emit with "hello how are you doing today"
}
});
If you are using Java 8, you can reduce the same code using lambda, as follows
observable.zipWith(observable2, (s, s2) -> s + " " + s2)
.reduce((s, s2) -> s +" "+ s2).subscribe(System.out::println);
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
edited Nov 19 '18 at 14:20
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
answered Nov 19 '18 at 14:09
Sarath Kn
1,599919
1,599919
1
The key iszipWith. You don't needscan+lastElement,reducesuffices.
– akarnokd
Nov 19 '18 at 14:10
@akarnokd updated the answer withreduce
– Sarath Kn
Nov 19 '18 at 14:15
add a comment |
1
The key iszipWith. You don't needscan+lastElement,reducesuffices.
– akarnokd
Nov 19 '18 at 14:10
@akarnokd updated the answer withreduce
– Sarath Kn
Nov 19 '18 at 14:15
1
1
The key is
zipWith. You don't need scan+lastElement, reduce suffices.– akarnokd
Nov 19 '18 at 14:10
The key is
zipWith. You don't need scan+lastElement, reduce suffices.– akarnokd
Nov 19 '18 at 14:10
@akarnokd updated the answer with
reduce– Sarath Kn
Nov 19 '18 at 14:15
@akarnokd updated the answer with
reduce– Sarath Kn
Nov 19 '18 at 14:15
add a comment |
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