Mixing
SQL Use ID to count dates but only can count each once
1
TABLE 1
ID DATE
1 . 1/1/2018
2 . 1/2/2018
2 . 1/2/2018
3 . 1/3/2018
4 . 1/2/2018
So I need to get a count of each date but there are cases where the same ID has the same date. I need to only count that one once.
For example my expected output is
1/1/2018 . 1
1/2/2018 . 2
1/3/2018 . 1
But the output i'm getting is
1/1/2018 . 1
1/2/2018 . 3
1/3/2018 . 1
sql
sql-server edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
add a comment |
1
TABLE 1
ID DATE
1 . 1/1/2018
2 . 1/2/2018
2 . 1/2/2018
3 . 1/3/2018
4 . 1/2/2018
So I need to get a count of each date but there are cases where the same ID has the same date. I need to only count that one once.
For example my expected output is
1/1/2018 . 1
1/2/2018 . 2
1/3/2018 . 1
But the output i'm getting is
1/1/2018 . 1
1/2/2018 . 3
1/3/2018 . 1
sql
sql-server edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
You should post your query in question as well in order to rectify issue.
– Yogesh Sharma
Nov 19 '18 at 17:38
So the row4 . 1/2/2018does not count in your expected output?
– forpas
Nov 19 '18 at 18:02
It does count in my output but I don't want it to count one of the dates with the id of 2.
– Brandon Brown
Nov 19 '18 at 18:05
So there is an extra row1/2/2018 . 1in your expected output?
– forpas
Nov 19 '18 at 18:07
yes an extra one is being counted. Yogesh solved it. Thank you.
– Brandon Brown
Nov 19 '18 at 18:10
add a comment |
1
1
1
TABLE 1
ID DATE
1 . 1/1/2018
2 . 1/2/2018
2 . 1/2/2018
3 . 1/3/2018
4 . 1/2/2018
So I need to get a count of each date but there are cases where the same ID has the same date. I need to only count that one once.
For example my expected output is
1/1/2018 . 1
1/2/2018 . 2
1/3/2018 . 1
But the output i'm getting is
1/1/2018 . 1
1/2/2018 . 3
1/3/2018 . 1
sql
sql-server edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
TABLE 1
ID DATE
1 . 1/1/2018
2 . 1/2/2018
2 . 1/2/2018
3 . 1/3/2018
4 . 1/2/2018
So I need to get a count of each date but there are cases where the same ID has the same date. I need to only count that one once.
For example my expected output is
1/1/2018 . 1
1/2/2018 . 2
1/3/2018 . 1
But the output i'm getting is
1/1/2018 . 1
1/2/2018 . 3
1/3/2018 . 1
sql
sql-server sql
sql-server edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
edited Nov 19 '18 at 17:39
Yogesh Sharma
28.3k51335
28.3k51335
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
asked Nov 19 '18 at 17:33
Brandon BrownBrandon Brown
144
144
You should post your query in question as well in order to rectify issue.
– Yogesh Sharma
Nov 19 '18 at 17:38
So the row4 . 1/2/2018does not count in your expected output?
– forpas
Nov 19 '18 at 18:02
It does count in my output but I don't want it to count one of the dates with the id of 2.
– Brandon Brown
Nov 19 '18 at 18:05
So there is an extra row1/2/2018 . 1in your expected output?
– forpas
Nov 19 '18 at 18:07
yes an extra one is being counted. Yogesh solved it. Thank you.
– Brandon Brown
Nov 19 '18 at 18:10
add a comment |
You should post your query in question as well in order to rectify issue.
– Yogesh Sharma
Nov 19 '18 at 17:38
So the row4 . 1/2/2018does not count in your expected output?
– forpas
Nov 19 '18 at 18:02
It does count in my output but I don't want it to count one of the dates with the id of 2.
– Brandon Brown
Nov 19 '18 at 18:05
So there is an extra row1/2/2018 . 1in your expected output?
– forpas
Nov 19 '18 at 18:07
yes an extra one is being counted. Yogesh solved it. Thank you.
– Brandon Brown
Nov 19 '18 at 18:10
You should post your query in question as well in order to rectify issue.
– Yogesh Sharma
Nov 19 '18 at 17:38
You should post your query in question as well in order to rectify issue.
– Yogesh Sharma
Nov 19 '18 at 17:38
So the row
4 . 1/2/2018 does not count in your expected output?– forpas
Nov 19 '18 at 18:02
So the row
4 . 1/2/2018 does not count in your expected output?– forpas
Nov 19 '18 at 18:02
It does count in my output but I don't want it to count one of the dates with the id of 2.
– Brandon Brown
Nov 19 '18 at 18:05
It does count in my output but I don't want it to count one of the dates with the id of 2.
– Brandon Brown
Nov 19 '18 at 18:05
So there is an extra row
1/2/2018 . 1 in your expected output?– forpas
Nov 19 '18 at 18:07
So there is an extra row
1/2/2018 . 1 in your expected output?– forpas
Nov 19 '18 at 18:07
yes an extra one is being counted. Yogesh solved it. Thank you.
– Brandon Brown
Nov 19 '18 at 18:10
yes an extra one is being counted. Yogesh solved it. Thank you.
– Brandon Brown
Nov 19 '18 at 18:10
add a comment |
3 Answers
3
active
oldest
votes
3
You need DISTINCT inside COUNT() to considered same id as once :
SELECT DATE, COUNT(DISTINCT ID)
FROM table1 t
GROUP BY DATE;
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
add a comment |
0
You need to GROUP by ID and DATE:
SELECT ID, DATE, COUNT(DATE) AS COUNTER
FROM table1
GROUP BY ID, DATE
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
add a comment |
0
You could use a subquery where you concatenate the key and the date using distinct.
SELECT DATE, COUNT(DATE) FROM table1
where DATE + ID =
(select DATE + ID from table1)
group by DATE
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You need DISTINCT inside COUNT() to considered same id as once :
SELECT DATE, COUNT(DISTINCT ID)
FROM table1 t
GROUP BY DATE;
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
add a comment |
3
You need DISTINCT inside COUNT() to considered same id as once :
SELECT DATE, COUNT(DISTINCT ID)
FROM table1 t
GROUP BY DATE;
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
add a comment |
3
3
3
You need DISTINCT inside COUNT() to considered same id as once :
SELECT DATE, COUNT(DISTINCT ID)
FROM table1 t
GROUP BY DATE;
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
You need DISTINCT inside COUNT() to considered same id as once :
SELECT DATE, COUNT(DISTINCT ID)
FROM table1 t
GROUP BY DATE;
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
answered Nov 19 '18 at 17:35
Yogesh SharmaYogesh Sharma
28.3k51335
28.3k51335
add a comment |
add a comment |
0
You need to GROUP by ID and DATE:
SELECT ID, DATE, COUNT(DATE) AS COUNTER
FROM table1
GROUP BY ID, DATE
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
add a comment |
0
You need to GROUP by ID and DATE:
SELECT ID, DATE, COUNT(DATE) AS COUNTER
FROM table1
GROUP BY ID, DATE
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
add a comment |
0
0
0
You need to GROUP by ID and DATE:
SELECT ID, DATE, COUNT(DATE) AS COUNTER
FROM table1
GROUP BY ID, DATE
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
You need to GROUP by ID and DATE:
SELECT ID, DATE, COUNT(DATE) AS COUNTER
FROM table1
GROUP BY ID, DATE
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
answered Nov 19 '18 at 18:28
forpasforpas
9,3091421
9,3091421
add a comment |
add a comment |
0
You could use a subquery where you concatenate the key and the date using distinct.
SELECT DATE, COUNT(DATE) FROM table1
where DATE + ID =
(select DATE + ID from table1)
group by DATE
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
add a comment |
0
You could use a subquery where you concatenate the key and the date using distinct.
SELECT DATE, COUNT(DATE) FROM table1
where DATE + ID =
(select DATE + ID from table1)
group by DATE
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
add a comment |
0
0
0
You could use a subquery where you concatenate the key and the date using distinct.
SELECT DATE, COUNT(DATE) FROM table1
where DATE + ID =
(select DATE + ID from table1)
group by DATE
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
You could use a subquery where you concatenate the key and the date using distinct.
SELECT DATE, COUNT(DATE) FROM table1
where DATE + ID =
(select DATE + ID from table1)
group by DATE
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
answered Nov 19 '18 at 18:56
KarlomanioKarlomanio
27528
27528
add a comment |
add a comment |
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You should post your query in question as well in order to rectify issue.
– Yogesh Sharma
Nov 19 '18 at 17:38
So the row
4 . 1/2/2018does not count in your expected output?– forpas
Nov 19 '18 at 18:02
It does count in my output but I don't want it to count one of the dates with the id of 2.
– Brandon Brown
Nov 19 '18 at 18:05
So there is an extra row
1/2/2018 . 1in your expected output?– forpas
Nov 19 '18 at 18:07
yes an extra one is being counted. Yogesh solved it. Thank you.
– Brandon Brown
Nov 19 '18 at 18:10