Vectorize only some arguments in function when calculating on Pandas dataframe












0















I have written a function that is meant to calculate a new dataframe column based on two other columns, as a few points of data from another dataframe. I want to apply this function in a vectorized way to the main dataframe, such that the 2 column inputs are calculated in such a way. At the same time, I want the third argument to be a constant dataframe that is used for a separate interpolation calculation (i.e not vectorized). How can this be accomplished?



Main function (as an example):



def calc_fitted_values(L, option, df_ref):
'''
This calculates an outputval for each combination of L and option, based
on intermediate calculations involving fitted values from df_ref.
- L is some column in my main dataframe
- option is a second column in the main dataframe
- df_ref is a separate data frame used in the pre-calculations here
'''
df_ref_option = df_ref[df_ref['option']==option] # take slice of df_ref based on option
x = df_ref_option['x'].values # get data columns to be used for polyfit
y = df_ref_option['y'].values
C = np.polyfit(np.log(x), np.log(y), 1); # use polyfit to get log fit of the reference data
a = np.exp(C[1]);
b = C[0];
outputval = a*(L**b)
return outputval


Usage wanted from function:



df['outputval']] = calc_fitted_values(df['L'], df['option'], df_ref)


In this example, L and option will be array values obtained from my main data frame columns (df), but df_ref is unrelated in in terms of shape and size.



How can I best write a function for this type of situation?



Thanks.



EDIT: My current "solution" is to use lambda...



f = lambda L, option : calc_fitted_values(L, option, df_ref)
df['outputval'] = np.vectorize(f)(df['L'].values, df['option'].values)


But this appears to be very slow. Might be due to the calculation each time through with df_ref, so would it be better to have a function that returns a lambda-defined function? Not sure of the best approach to this.










share|improve this question

























  • one possible solution: torch.nn.CrossEntropyLoss discuss.pytorch.org/t/…

    – teng
    Nov 19 '18 at 21:57











  • If you use np.vectorize (for convenience, not speed), try the exclude parameter. And don't neglect the otypes parameter.

    – hpaulj
    Nov 19 '18 at 22:32











  • the parameter option is not used ...

    – B. M.
    Nov 20 '18 at 11:59











  • @B.M. sorry, fixed it

    – teepee
    Nov 20 '18 at 16:48
















0















I have written a function that is meant to calculate a new dataframe column based on two other columns, as a few points of data from another dataframe. I want to apply this function in a vectorized way to the main dataframe, such that the 2 column inputs are calculated in such a way. At the same time, I want the third argument to be a constant dataframe that is used for a separate interpolation calculation (i.e not vectorized). How can this be accomplished?



Main function (as an example):



def calc_fitted_values(L, option, df_ref):
'''
This calculates an outputval for each combination of L and option, based
on intermediate calculations involving fitted values from df_ref.
- L is some column in my main dataframe
- option is a second column in the main dataframe
- df_ref is a separate data frame used in the pre-calculations here
'''
df_ref_option = df_ref[df_ref['option']==option] # take slice of df_ref based on option
x = df_ref_option['x'].values # get data columns to be used for polyfit
y = df_ref_option['y'].values
C = np.polyfit(np.log(x), np.log(y), 1); # use polyfit to get log fit of the reference data
a = np.exp(C[1]);
b = C[0];
outputval = a*(L**b)
return outputval


Usage wanted from function:



df['outputval']] = calc_fitted_values(df['L'], df['option'], df_ref)


In this example, L and option will be array values obtained from my main data frame columns (df), but df_ref is unrelated in in terms of shape and size.



How can I best write a function for this type of situation?



Thanks.



EDIT: My current "solution" is to use lambda...



f = lambda L, option : calc_fitted_values(L, option, df_ref)
df['outputval'] = np.vectorize(f)(df['L'].values, df['option'].values)


But this appears to be very slow. Might be due to the calculation each time through with df_ref, so would it be better to have a function that returns a lambda-defined function? Not sure of the best approach to this.










share|improve this question

























  • one possible solution: torch.nn.CrossEntropyLoss discuss.pytorch.org/t/…

    – teng
    Nov 19 '18 at 21:57











  • If you use np.vectorize (for convenience, not speed), try the exclude parameter. And don't neglect the otypes parameter.

    – hpaulj
    Nov 19 '18 at 22:32











  • the parameter option is not used ...

    – B. M.
    Nov 20 '18 at 11:59











  • @B.M. sorry, fixed it

    – teepee
    Nov 20 '18 at 16:48














0












0








0








I have written a function that is meant to calculate a new dataframe column based on two other columns, as a few points of data from another dataframe. I want to apply this function in a vectorized way to the main dataframe, such that the 2 column inputs are calculated in such a way. At the same time, I want the third argument to be a constant dataframe that is used for a separate interpolation calculation (i.e not vectorized). How can this be accomplished?



Main function (as an example):



def calc_fitted_values(L, option, df_ref):
'''
This calculates an outputval for each combination of L and option, based
on intermediate calculations involving fitted values from df_ref.
- L is some column in my main dataframe
- option is a second column in the main dataframe
- df_ref is a separate data frame used in the pre-calculations here
'''
df_ref_option = df_ref[df_ref['option']==option] # take slice of df_ref based on option
x = df_ref_option['x'].values # get data columns to be used for polyfit
y = df_ref_option['y'].values
C = np.polyfit(np.log(x), np.log(y), 1); # use polyfit to get log fit of the reference data
a = np.exp(C[1]);
b = C[0];
outputval = a*(L**b)
return outputval


Usage wanted from function:



df['outputval']] = calc_fitted_values(df['L'], df['option'], df_ref)


In this example, L and option will be array values obtained from my main data frame columns (df), but df_ref is unrelated in in terms of shape and size.



How can I best write a function for this type of situation?



Thanks.



EDIT: My current "solution" is to use lambda...



f = lambda L, option : calc_fitted_values(L, option, df_ref)
df['outputval'] = np.vectorize(f)(df['L'].values, df['option'].values)


But this appears to be very slow. Might be due to the calculation each time through with df_ref, so would it be better to have a function that returns a lambda-defined function? Not sure of the best approach to this.










share|improve this question
















I have written a function that is meant to calculate a new dataframe column based on two other columns, as a few points of data from another dataframe. I want to apply this function in a vectorized way to the main dataframe, such that the 2 column inputs are calculated in such a way. At the same time, I want the third argument to be a constant dataframe that is used for a separate interpolation calculation (i.e not vectorized). How can this be accomplished?



Main function (as an example):



def calc_fitted_values(L, option, df_ref):
'''
This calculates an outputval for each combination of L and option, based
on intermediate calculations involving fitted values from df_ref.
- L is some column in my main dataframe
- option is a second column in the main dataframe
- df_ref is a separate data frame used in the pre-calculations here
'''
df_ref_option = df_ref[df_ref['option']==option] # take slice of df_ref based on option
x = df_ref_option['x'].values # get data columns to be used for polyfit
y = df_ref_option['y'].values
C = np.polyfit(np.log(x), np.log(y), 1); # use polyfit to get log fit of the reference data
a = np.exp(C[1]);
b = C[0];
outputval = a*(L**b)
return outputval


Usage wanted from function:



df['outputval']] = calc_fitted_values(df['L'], df['option'], df_ref)


In this example, L and option will be array values obtained from my main data frame columns (df), but df_ref is unrelated in in terms of shape and size.



How can I best write a function for this type of situation?



Thanks.



EDIT: My current "solution" is to use lambda...



f = lambda L, option : calc_fitted_values(L, option, df_ref)
df['outputval'] = np.vectorize(f)(df['L'].values, df['option'].values)


But this appears to be very slow. Might be due to the calculation each time through with df_ref, so would it be better to have a function that returns a lambda-defined function? Not sure of the best approach to this.







python pandas numpy dataframe vectorization






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 16:48







teepee

















asked Nov 19 '18 at 21:38









teepeeteepee

7021819




7021819













  • one possible solution: torch.nn.CrossEntropyLoss discuss.pytorch.org/t/…

    – teng
    Nov 19 '18 at 21:57











  • If you use np.vectorize (for convenience, not speed), try the exclude parameter. And don't neglect the otypes parameter.

    – hpaulj
    Nov 19 '18 at 22:32











  • the parameter option is not used ...

    – B. M.
    Nov 20 '18 at 11:59











  • @B.M. sorry, fixed it

    – teepee
    Nov 20 '18 at 16:48



















  • one possible solution: torch.nn.CrossEntropyLoss discuss.pytorch.org/t/…

    – teng
    Nov 19 '18 at 21:57











  • If you use np.vectorize (for convenience, not speed), try the exclude parameter. And don't neglect the otypes parameter.

    – hpaulj
    Nov 19 '18 at 22:32











  • the parameter option is not used ...

    – B. M.
    Nov 20 '18 at 11:59











  • @B.M. sorry, fixed it

    – teepee
    Nov 20 '18 at 16:48

















one possible solution: torch.nn.CrossEntropyLoss discuss.pytorch.org/t/…

– teng
Nov 19 '18 at 21:57





one possible solution: torch.nn.CrossEntropyLoss discuss.pytorch.org/t/…

– teng
Nov 19 '18 at 21:57













If you use np.vectorize (for convenience, not speed), try the exclude parameter. And don't neglect the otypes parameter.

– hpaulj
Nov 19 '18 at 22:32





If you use np.vectorize (for convenience, not speed), try the exclude parameter. And don't neglect the otypes parameter.

– hpaulj
Nov 19 '18 at 22:32













the parameter option is not used ...

– B. M.
Nov 20 '18 at 11:59





the parameter option is not used ...

– B. M.
Nov 20 '18 at 11:59













@B.M. sorry, fixed it

– teepee
Nov 20 '18 at 16:48





@B.M. sorry, fixed it

– teepee
Nov 20 '18 at 16:48












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