Width of right trapezoid at a given height?
I have a right angle trapezoid and would like to find the width $XY$.
The only known dimensions are $AX, XD, DC$. Angles $A, X$ and $D$ are $90$ degrees.
I wonder if it is possible to do this.
I have added a little sketch.
Thank you for your insight.
geometry
|
show 1 more comment
I have a right angle trapezoid and would like to find the width $XY$.
The only known dimensions are $AX, XD, DC$. Angles $A, X$ and $D$ are $90$ degrees.
I wonder if it is possible to do this.
I have added a little sketch.
Thank you for your insight.
geometry
The length of $XY$ depends on $alpha$.
– rogerl
Nov 21 '18 at 22:30
Imagine $AXD$ and $BYC$ are two sticks. Now you can rotate $BYC$ at point $C$ while still keeping $DC$ fixed, right?
– Alex Vong
Nov 21 '18 at 22:47
Both comments above are true.
– Pavlo Palagut
Nov 22 '18 at 23:13
Hint: Add a "vertical" line from $B$ to its intersection at $F$ with $DC$. Now $BF=AD$, so $FC$ can be computed from Alpha and $AB=DF=DC-FC$.
– random
Nov 22 '18 at 23:18
Thank you, but Alpha is not known...
– Pavlo Palagut
Nov 23 '18 at 14:07
|
show 1 more comment
I have a right angle trapezoid and would like to find the width $XY$.
The only known dimensions are $AX, XD, DC$. Angles $A, X$ and $D$ are $90$ degrees.
I wonder if it is possible to do this.
I have added a little sketch.
Thank you for your insight.
geometry
I have a right angle trapezoid and would like to find the width $XY$.
The only known dimensions are $AX, XD, DC$. Angles $A, X$ and $D$ are $90$ degrees.
I wonder if it is possible to do this.
I have added a little sketch.
Thank you for your insight.
geometry
geometry
edited Nov 21 '18 at 22:52
Alex Vong
1,286819
1,286819
asked Nov 21 '18 at 22:23
Pavlo PalagutPavlo Palagut
1
1
The length of $XY$ depends on $alpha$.
– rogerl
Nov 21 '18 at 22:30
Imagine $AXD$ and $BYC$ are two sticks. Now you can rotate $BYC$ at point $C$ while still keeping $DC$ fixed, right?
– Alex Vong
Nov 21 '18 at 22:47
Both comments above are true.
– Pavlo Palagut
Nov 22 '18 at 23:13
Hint: Add a "vertical" line from $B$ to its intersection at $F$ with $DC$. Now $BF=AD$, so $FC$ can be computed from Alpha and $AB=DF=DC-FC$.
– random
Nov 22 '18 at 23:18
Thank you, but Alpha is not known...
– Pavlo Palagut
Nov 23 '18 at 14:07
|
show 1 more comment
The length of $XY$ depends on $alpha$.
– rogerl
Nov 21 '18 at 22:30
Imagine $AXD$ and $BYC$ are two sticks. Now you can rotate $BYC$ at point $C$ while still keeping $DC$ fixed, right?
– Alex Vong
Nov 21 '18 at 22:47
Both comments above are true.
– Pavlo Palagut
Nov 22 '18 at 23:13
Hint: Add a "vertical" line from $B$ to its intersection at $F$ with $DC$. Now $BF=AD$, so $FC$ can be computed from Alpha and $AB=DF=DC-FC$.
– random
Nov 22 '18 at 23:18
Thank you, but Alpha is not known...
– Pavlo Palagut
Nov 23 '18 at 14:07
The length of $XY$ depends on $alpha$.
– rogerl
Nov 21 '18 at 22:30
The length of $XY$ depends on $alpha$.
– rogerl
Nov 21 '18 at 22:30
Imagine $AXD$ and $BYC$ are two sticks. Now you can rotate $BYC$ at point $C$ while still keeping $DC$ fixed, right?
– Alex Vong
Nov 21 '18 at 22:47
Imagine $AXD$ and $BYC$ are two sticks. Now you can rotate $BYC$ at point $C$ while still keeping $DC$ fixed, right?
– Alex Vong
Nov 21 '18 at 22:47
Both comments above are true.
– Pavlo Palagut
Nov 22 '18 at 23:13
Both comments above are true.
– Pavlo Palagut
Nov 22 '18 at 23:13
Hint: Add a "vertical" line from $B$ to its intersection at $F$ with $DC$. Now $BF=AD$, so $FC$ can be computed from Alpha and $AB=DF=DC-FC$.
– random
Nov 22 '18 at 23:18
Hint: Add a "vertical" line from $B$ to its intersection at $F$ with $DC$. Now $BF=AD$, so $FC$ can be computed from Alpha and $AB=DF=DC-FC$.
– random
Nov 22 '18 at 23:18
Thank you, but Alpha is not known...
– Pavlo Palagut
Nov 23 '18 at 14:07
Thank you, but Alpha is not known...
– Pavlo Palagut
Nov 23 '18 at 14:07
|
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The length of $XY$ depends on $alpha$.
– rogerl
Nov 21 '18 at 22:30
Imagine $AXD$ and $BYC$ are two sticks. Now you can rotate $BYC$ at point $C$ while still keeping $DC$ fixed, right?
– Alex Vong
Nov 21 '18 at 22:47
Both comments above are true.
– Pavlo Palagut
Nov 22 '18 at 23:13
Hint: Add a "vertical" line from $B$ to its intersection at $F$ with $DC$. Now $BF=AD$, so $FC$ can be computed from Alpha and $AB=DF=DC-FC$.
– random
Nov 22 '18 at 23:18
Thank you, but Alpha is not known...
– Pavlo Palagut
Nov 23 '18 at 14:07