Fill Chart dynamically with variables from Component












0















i am new to Angular so i think i'm missing something.



i have 3 variables in my component, those variables are being filled after calling .subscribe method on an observable object.



like this



this.interRetard = this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
});


the interRetard variable contains a number, i can display its value in the html by doing {{interRetard}} .



the problem is that when i try to display it with console.log() it says :



Subscriber {closed: false, _parent: null, _parents: null, _subscriptions: Array(1), syncErrorValue: null, …}


and i need it to give me the exact value like it is displaying it in the html so i can assign it to the chart like this



public doughnutChartData:number = [this.interRetard ,  5, 10];


Thank you.










share|improve this question


















  • 1





    You seem to be using this.interRetard 2 times. Once to hold the subscription returned by the subscribe, and again when you assign data to it inside the subscribe.

    – R. Richards
    Nov 21 '18 at 18:34






  • 1





    this.interRetard is being assigned twice in your statement. You only need to assign it inside the subscribe callback.

    – Wrokar
    Nov 21 '18 at 18:34











  • i removed it and something weird is happepning :/ when i do console.log(interRetard) it displayes undefined then when i trigger the method again (selection changed of a select box) it shows the right value :/ :/

    – kmar akrout
    Nov 21 '18 at 18:41













  • What is the type of your interRetard ?

    – Rahul
    Nov 21 '18 at 18:43











  • the type is any .. i have bad news also this is not working doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:46
















0















i am new to Angular so i think i'm missing something.



i have 3 variables in my component, those variables are being filled after calling .subscribe method on an observable object.



like this



this.interRetard = this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
});


the interRetard variable contains a number, i can display its value in the html by doing {{interRetard}} .



the problem is that when i try to display it with console.log() it says :



Subscriber {closed: false, _parent: null, _parents: null, _subscriptions: Array(1), syncErrorValue: null, …}


and i need it to give me the exact value like it is displaying it in the html so i can assign it to the chart like this



public doughnutChartData:number = [this.interRetard ,  5, 10];


Thank you.










share|improve this question


















  • 1





    You seem to be using this.interRetard 2 times. Once to hold the subscription returned by the subscribe, and again when you assign data to it inside the subscribe.

    – R. Richards
    Nov 21 '18 at 18:34






  • 1





    this.interRetard is being assigned twice in your statement. You only need to assign it inside the subscribe callback.

    – Wrokar
    Nov 21 '18 at 18:34











  • i removed it and something weird is happepning :/ when i do console.log(interRetard) it displayes undefined then when i trigger the method again (selection changed of a select box) it shows the right value :/ :/

    – kmar akrout
    Nov 21 '18 at 18:41













  • What is the type of your interRetard ?

    – Rahul
    Nov 21 '18 at 18:43











  • the type is any .. i have bad news also this is not working doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:46














0












0








0








i am new to Angular so i think i'm missing something.



i have 3 variables in my component, those variables are being filled after calling .subscribe method on an observable object.



like this



this.interRetard = this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
});


the interRetard variable contains a number, i can display its value in the html by doing {{interRetard}} .



the problem is that when i try to display it with console.log() it says :



Subscriber {closed: false, _parent: null, _parents: null, _subscriptions: Array(1), syncErrorValue: null, …}


and i need it to give me the exact value like it is displaying it in the html so i can assign it to the chart like this



public doughnutChartData:number = [this.interRetard ,  5, 10];


Thank you.










share|improve this question














i am new to Angular so i think i'm missing something.



i have 3 variables in my component, those variables are being filled after calling .subscribe method on an observable object.



like this



this.interRetard = this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
});


the interRetard variable contains a number, i can display its value in the html by doing {{interRetard}} .



the problem is that when i try to display it with console.log() it says :



Subscriber {closed: false, _parent: null, _parents: null, _subscriptions: Array(1), syncErrorValue: null, …}


and i need it to give me the exact value like it is displaying it in the html so i can assign it to the chart like this



public doughnutChartData:number = [this.interRetard ,  5, 10];


Thank you.







angular typescript






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 '18 at 18:29









kmar akroutkmar akrout

419




419








  • 1





    You seem to be using this.interRetard 2 times. Once to hold the subscription returned by the subscribe, and again when you assign data to it inside the subscribe.

    – R. Richards
    Nov 21 '18 at 18:34






  • 1





    this.interRetard is being assigned twice in your statement. You only need to assign it inside the subscribe callback.

    – Wrokar
    Nov 21 '18 at 18:34











  • i removed it and something weird is happepning :/ when i do console.log(interRetard) it displayes undefined then when i trigger the method again (selection changed of a select box) it shows the right value :/ :/

    – kmar akrout
    Nov 21 '18 at 18:41













  • What is the type of your interRetard ?

    – Rahul
    Nov 21 '18 at 18:43











  • the type is any .. i have bad news also this is not working doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:46














  • 1





    You seem to be using this.interRetard 2 times. Once to hold the subscription returned by the subscribe, and again when you assign data to it inside the subscribe.

    – R. Richards
    Nov 21 '18 at 18:34






  • 1





    this.interRetard is being assigned twice in your statement. You only need to assign it inside the subscribe callback.

    – Wrokar
    Nov 21 '18 at 18:34











  • i removed it and something weird is happepning :/ when i do console.log(interRetard) it displayes undefined then when i trigger the method again (selection changed of a select box) it shows the right value :/ :/

    – kmar akrout
    Nov 21 '18 at 18:41













  • What is the type of your interRetard ?

    – Rahul
    Nov 21 '18 at 18:43











  • the type is any .. i have bad news also this is not working doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:46








1




1





You seem to be using this.interRetard 2 times. Once to hold the subscription returned by the subscribe, and again when you assign data to it inside the subscribe.

– R. Richards
Nov 21 '18 at 18:34





You seem to be using this.interRetard 2 times. Once to hold the subscription returned by the subscribe, and again when you assign data to it inside the subscribe.

– R. Richards
Nov 21 '18 at 18:34




1




1





this.interRetard is being assigned twice in your statement. You only need to assign it inside the subscribe callback.

– Wrokar
Nov 21 '18 at 18:34





this.interRetard is being assigned twice in your statement. You only need to assign it inside the subscribe callback.

– Wrokar
Nov 21 '18 at 18:34













i removed it and something weird is happepning :/ when i do console.log(interRetard) it displayes undefined then when i trigger the method again (selection changed of a select box) it shows the right value :/ :/

– kmar akrout
Nov 21 '18 at 18:41







i removed it and something weird is happepning :/ when i do console.log(interRetard) it displayes undefined then when i trigger the method again (selection changed of a select box) it shows the right value :/ :/

– kmar akrout
Nov 21 '18 at 18:41















What is the type of your interRetard ?

– Rahul
Nov 21 '18 at 18:43





What is the type of your interRetard ?

– Rahul
Nov 21 '18 at 18:43













the type is any .. i have bad news also this is not working doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

– kmar akrout
Nov 21 '18 at 18:46





the type is any .. i have bad news also this is not working doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

– kmar akrout
Nov 21 '18 at 18:46












1 Answer
1






active

oldest

votes


















1














This should work:



   this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
console.log(this.iterRetard);
this.myFunction(this.iterRetard) or this.myFunction(data);
});

myFunction(p) {
// Your Logic //
}





share|improve this answer


























  • yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:52











  • can you please explain your last comment .. i don't seem to get what u're saying

    – kmar akrout
    Nov 21 '18 at 18:55











  • I edited the answer, let me know if that answers your question!

    – alokstar
    Nov 21 '18 at 18:56











  • @kmarakrout: that comment was partial, so removed it!

    – alokstar
    Nov 21 '18 at 19:08






  • 1





    no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

    – kmar akrout
    Nov 21 '18 at 19:23











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














This should work:



   this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
console.log(this.iterRetard);
this.myFunction(this.iterRetard) or this.myFunction(data);
});

myFunction(p) {
// Your Logic //
}





share|improve this answer


























  • yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:52











  • can you please explain your last comment .. i don't seem to get what u're saying

    – kmar akrout
    Nov 21 '18 at 18:55











  • I edited the answer, let me know if that answers your question!

    – alokstar
    Nov 21 '18 at 18:56











  • @kmarakrout: that comment was partial, so removed it!

    – alokstar
    Nov 21 '18 at 19:08






  • 1





    no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

    – kmar akrout
    Nov 21 '18 at 19:23
















1














This should work:



   this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
console.log(this.iterRetard);
this.myFunction(this.iterRetard) or this.myFunction(data);
});

myFunction(p) {
// Your Logic //
}





share|improve this answer


























  • yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:52











  • can you please explain your last comment .. i don't seem to get what u're saying

    – kmar akrout
    Nov 21 '18 at 18:55











  • I edited the answer, let me know if that answers your question!

    – alokstar
    Nov 21 '18 at 18:56











  • @kmarakrout: that comment was partial, so removed it!

    – alokstar
    Nov 21 '18 at 19:08






  • 1





    no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

    – kmar akrout
    Nov 21 '18 at 19:23














1












1








1







This should work:



   this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
console.log(this.iterRetard);
this.myFunction(this.iterRetard) or this.myFunction(data);
});

myFunction(p) {
// Your Logic //
}





share|improve this answer















This should work:



   this.technicienService.getInterRetard(id).subscribe(data => {
this.interRetard = data;
console.log(this.iterRetard);
this.myFunction(this.iterRetard) or this.myFunction(data);
});

myFunction(p) {
// Your Logic //
}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 '18 at 18:56

























answered Nov 21 '18 at 18:50









alokstaralokstar

46927




46927













  • yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:52











  • can you please explain your last comment .. i don't seem to get what u're saying

    – kmar akrout
    Nov 21 '18 at 18:55











  • I edited the answer, let me know if that answers your question!

    – alokstar
    Nov 21 '18 at 18:56











  • @kmarakrout: that comment was partial, so removed it!

    – alokstar
    Nov 21 '18 at 19:08






  • 1





    no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

    – kmar akrout
    Nov 21 '18 at 19:23



















  • yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

    – kmar akrout
    Nov 21 '18 at 18:52











  • can you please explain your last comment .. i don't seem to get what u're saying

    – kmar akrout
    Nov 21 '18 at 18:55











  • I edited the answer, let me know if that answers your question!

    – alokstar
    Nov 21 '18 at 18:56











  • @kmarakrout: that comment was partial, so removed it!

    – alokstar
    Nov 21 '18 at 19:08






  • 1





    no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

    – kmar akrout
    Nov 21 '18 at 19:23

















yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

– kmar akrout
Nov 21 '18 at 18:52





yes i know this works .. but i need the variable outside the method subscribe so i can put it in an array and assign the array to a chart like this ... public doughnutChartData:number = [this.interRetard ,this.interFinie,this.interAvance];

– kmar akrout
Nov 21 '18 at 18:52













can you please explain your last comment .. i don't seem to get what u're saying

– kmar akrout
Nov 21 '18 at 18:55





can you please explain your last comment .. i don't seem to get what u're saying

– kmar akrout
Nov 21 '18 at 18:55













I edited the answer, let me know if that answers your question!

– alokstar
Nov 21 '18 at 18:56





I edited the answer, let me know if that answers your question!

– alokstar
Nov 21 '18 at 18:56













@kmarakrout: that comment was partial, so removed it!

– alokstar
Nov 21 '18 at 19:08





@kmarakrout: that comment was partial, so removed it!

– alokstar
Nov 21 '18 at 19:08




1




1





no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

– kmar akrout
Nov 21 '18 at 19:23





no problem .. i think your answer is working .. i'm trying something if it works perfectly i'll let you know .. thanks

– kmar akrout
Nov 21 '18 at 19:23




















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