How can I append an alement after another element?
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
add a comment |
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
add a comment |
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
jquery append insertafter
asked Nov 21 '18 at 18:30
JarlaJarla
2,38811639
2,38811639
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Since your input tag has an id form_username
, you don't have to use [name]
attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you want to use attribute name
, you could rename the value form[username]
to form_username
, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
If you don't want to rename the name
attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
add a comment |
Alternatively, you could just use jQuery's .append()
method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418456%2fhow-can-i-append-an-alement-after-another-element%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Since your input tag has an id form_username
, you don't have to use [name]
attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you want to use attribute name
, you could rename the value form[username]
to form_username
, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
If you don't want to rename the name
attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
add a comment |
Since your input tag has an id form_username
, you don't have to use [name]
attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you want to use attribute name
, you could rename the value form[username]
to form_username
, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
If you don't want to rename the name
attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
add a comment |
Since your input tag has an id form_username
, you don't have to use [name]
attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you want to use attribute name
, you could rename the value form[username]
to form_username
, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
If you don't want to rename the name
attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Since your input tag has an id form_username
, you don't have to use [name]
attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
Or if you want to use attribute name
, you could rename the value form[username]
to form_username
, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
If you don't want to rename the name
attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('#form_username');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('input');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
edited Nov 21 '18 at 18:51
answered Nov 21 '18 at 18:35
FooFoo
1
1
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
add a comment |
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 '18 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
@Jarla I've updated new solution.
– Foo
Nov 21 '18 at 18:52
1
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 '18 at 18:53
add a comment |
Alternatively, you could just use jQuery's .append()
method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
add a comment |
Alternatively, you could just use jQuery's .append()
method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
add a comment |
Alternatively, you could just use jQuery's .append()
method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
Alternatively, you could just use jQuery's .append()
method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>
edited Nov 21 '18 at 18:55
answered Nov 21 '18 at 18:45
PeterPeter
477216
477216
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
add a comment |
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 '18 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
That's not a problem. I will update my snippet.
– Peter
Nov 21 '18 at 18:53
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418456%2fhow-can-i-append-an-alement-after-another-element%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown