How can I append an alement after another element?












-1















<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>


I try to append an element to the input field with the name "form[username]:



$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');


But it is not working. Nothing happens.



I expect this result:



<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>









share|improve this question



























    -1















    <div>
    <label for="form_username" class="required">Username</label>
    <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
    </div>


    I try to append an element to the input field with the name "form[username]:



    $( "<p>Test</p>" ).insertAfter('input[name=form[username]]');


    But it is not working. Nothing happens.



    I expect this result:



    <div>
    <label for="form_username" class="required">Username</label>
    <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
    <p>Test</p>
    </div>









    share|improve this question

























      -1












      -1








      -1








      <div>
      <label for="form_username" class="required">Username</label>
      <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
      </div>


      I try to append an element to the input field with the name "form[username]:



      $( "<p>Test</p>" ).insertAfter('input[name=form[username]]');


      But it is not working. Nothing happens.



      I expect this result:



      <div>
      <label for="form_username" class="required">Username</label>
      <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
      <p>Test</p>
      </div>









      share|improve this question














      <div>
      <label for="form_username" class="required">Username</label>
      <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
      </div>


      I try to append an element to the input field with the name "form[username]:



      $( "<p>Test</p>" ).insertAfter('input[name=form[username]]');


      But it is not working. Nothing happens.



      I expect this result:



      <div>
      <label for="form_username" class="required">Username</label>
      <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
      <p>Test</p>
      </div>






      jquery append insertafter






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 21 '18 at 18:30









      JarlaJarla

      2,38811639




      2,38811639
























          2 Answers
          2






          active

          oldest

          votes


















          1














          Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.






          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you have only 1 input tag, you could try:






          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:






          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>







          If you don't want to rename the name attribute value, you could try:






          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>








          share|improve this answer


























          • Thank you! What if I cannot rename it. Is it then not possible?

            – Jarla
            Nov 21 '18 at 18:47











          • @Jarla I've updated new solution.

            – Foo
            Nov 21 '18 at 18:52






          • 1





            This worked! Perfect. Thanks a lot!!

            – Jarla
            Nov 21 '18 at 18:53



















          0














          Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.






          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>








          share|improve this answer


























          • I have more than one div so I need to append it to the specific with the name form[username]

            – Jarla
            Nov 21 '18 at 18:52











          • That's not a problem. I will update my snippet.

            – Peter
            Nov 21 '18 at 18:53











          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418456%2fhow-can-i-append-an-alement-after-another-element%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.






          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you have only 1 input tag, you could try:






          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:






          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>







          If you don't want to rename the name attribute value, you could try:






          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>








          share|improve this answer


























          • Thank you! What if I cannot rename it. Is it then not possible?

            – Jarla
            Nov 21 '18 at 18:47











          • @Jarla I've updated new solution.

            – Foo
            Nov 21 '18 at 18:52






          • 1





            This worked! Perfect. Thanks a lot!!

            – Jarla
            Nov 21 '18 at 18:53
















          1














          Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.






          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you have only 1 input tag, you could try:






          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:






          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>







          If you don't want to rename the name attribute value, you could try:






          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>








          share|improve this answer


























          • Thank you! What if I cannot rename it. Is it then not possible?

            – Jarla
            Nov 21 '18 at 18:47











          • @Jarla I've updated new solution.

            – Foo
            Nov 21 '18 at 18:52






          • 1





            This worked! Perfect. Thanks a lot!!

            – Jarla
            Nov 21 '18 at 18:53














          1












          1








          1







          Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.






          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you have only 1 input tag, you could try:






          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:






          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>







          If you don't want to rename the name attribute value, you could try:






          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>








          share|improve this answer















          Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.






          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you have only 1 input tag, you could try:






          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>







          Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:






          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>







          If you don't want to rename the name attribute value, you could try:






          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>








          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('#form_username');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('input');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('[name=form_username]');
          $( "<p>" ).text("Test").insertAfter('input[name=form_username]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form_username" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>





          $( "<p>" ).text("Test").insertAfter('input[name*="username"]');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <div>
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 21 '18 at 18:51

























          answered Nov 21 '18 at 18:35









          FooFoo

          1




          1













          • Thank you! What if I cannot rename it. Is it then not possible?

            – Jarla
            Nov 21 '18 at 18:47











          • @Jarla I've updated new solution.

            – Foo
            Nov 21 '18 at 18:52






          • 1





            This worked! Perfect. Thanks a lot!!

            – Jarla
            Nov 21 '18 at 18:53



















          • Thank you! What if I cannot rename it. Is it then not possible?

            – Jarla
            Nov 21 '18 at 18:47











          • @Jarla I've updated new solution.

            – Foo
            Nov 21 '18 at 18:52






          • 1





            This worked! Perfect. Thanks a lot!!

            – Jarla
            Nov 21 '18 at 18:53

















          Thank you! What if I cannot rename it. Is it then not possible?

          – Jarla
          Nov 21 '18 at 18:47





          Thank you! What if I cannot rename it. Is it then not possible?

          – Jarla
          Nov 21 '18 at 18:47













          @Jarla I've updated new solution.

          – Foo
          Nov 21 '18 at 18:52





          @Jarla I've updated new solution.

          – Foo
          Nov 21 '18 at 18:52




          1




          1





          This worked! Perfect. Thanks a lot!!

          – Jarla
          Nov 21 '18 at 18:53





          This worked! Perfect. Thanks a lot!!

          – Jarla
          Nov 21 '18 at 18:53













          0














          Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.






          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>








          share|improve this answer


























          • I have more than one div so I need to append it to the specific with the name form[username]

            – Jarla
            Nov 21 '18 at 18:52











          • That's not a problem. I will update my snippet.

            – Peter
            Nov 21 '18 at 18:53
















          0














          Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.






          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>








          share|improve this answer


























          • I have more than one div so I need to append it to the specific with the name form[username]

            – Jarla
            Nov 21 '18 at 18:52











          • That's not a problem. I will update my snippet.

            – Peter
            Nov 21 '18 at 18:53














          0












          0








          0







          Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.






          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>








          share|improve this answer















          Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.






          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>








          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>





          $('#content_one').append('<p>Test 1</p>');
          $('#content_two').append('<p>Test 2</p>');

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div id="content_one">
          <label for="form_username" class="required">Username</label>
          <input type="text" id="form_username" name="form[username]" required="required" class="form-control">
          </div>

          <div id="content_two">
          <label for="form_password" class="required">Password</label>
          <input type="text" id="form_password" name="form[password]" required="required" class="form-control">
          </div>






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 21 '18 at 18:55

























          answered Nov 21 '18 at 18:45









          PeterPeter

          477216




          477216













          • I have more than one div so I need to append it to the specific with the name form[username]

            – Jarla
            Nov 21 '18 at 18:52











          • That's not a problem. I will update my snippet.

            – Peter
            Nov 21 '18 at 18:53



















          • I have more than one div so I need to append it to the specific with the name form[username]

            – Jarla
            Nov 21 '18 at 18:52











          • That's not a problem. I will update my snippet.

            – Peter
            Nov 21 '18 at 18:53

















          I have more than one div so I need to append it to the specific with the name form[username]

          – Jarla
          Nov 21 '18 at 18:52





          I have more than one div so I need to append it to the specific with the name form[username]

          – Jarla
          Nov 21 '18 at 18:52













          That's not a problem. I will update my snippet.

          – Peter
          Nov 21 '18 at 18:53





          That's not a problem. I will update my snippet.

          – Peter
          Nov 21 '18 at 18:53


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418456%2fhow-can-i-append-an-alement-after-another-element%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Can a sorcerer learn a 5th-level spell early by creating spell slots using the Font of Magic feature?

          Does disintegrating a polymorphed enemy still kill it after the 2018 errata?

          A Topological Invariant for $pi_3(U(n))$