Echo top 5 appearing words on page












0















Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.



For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.










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  • would you like to count the words on the backend (PHP/Wordpress) or frontend (JavaScript) ???

    – marvinIsSacul
    Nov 16 '18 at 7:19
















0















Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.



For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.










share|improve this question























  • would you like to count the words on the backend (PHP/Wordpress) or frontend (JavaScript) ???

    – marvinIsSacul
    Nov 16 '18 at 7:19














0












0








0








Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.



For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.










share|improve this question














Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.



For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.







javascript php wordpress count word






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asked Nov 15 '18 at 19:33









JGRJGR

246




246













  • would you like to count the words on the backend (PHP/Wordpress) or frontend (JavaScript) ???

    – marvinIsSacul
    Nov 16 '18 at 7:19



















  • would you like to count the words on the backend (PHP/Wordpress) or frontend (JavaScript) ???

    – marvinIsSacul
    Nov 16 '18 at 7:19

















would you like to count the words on the backend (PHP/Wordpress) or frontend (JavaScript) ???

– marvinIsSacul
Nov 16 '18 at 7:19





would you like to count the words on the backend (PHP/Wordpress) or frontend (JavaScript) ???

– marvinIsSacul
Nov 16 '18 at 7:19












1 Answer
1






active

oldest

votes


















1














I'm not sure how useful it would be. You end up with meaningless words.






let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





Filtering Added



We can filter the array before counting words, so you can add whatever you like to the filters array to get rid of those words. I probably should have thought of that to begin with...






const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>








share|improve this answer


























  • Thanks man, I will check this code. Looks good. I will let you know if it works

    – JGR
    Nov 20 '18 at 12:52











  • One little question. The code is working but can I skip numbers? So only text being counted.

    – JGR
    Nov 20 '18 at 13:12











  • Yep, added filtering.

    – Will
    Nov 21 '18 at 18:30











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














I'm not sure how useful it would be. You end up with meaningless words.






let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





Filtering Added



We can filter the array before counting words, so you can add whatever you like to the filters array to get rid of those words. I probably should have thought of that to begin with...






const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>








share|improve this answer


























  • Thanks man, I will check this code. Looks good. I will let you know if it works

    – JGR
    Nov 20 '18 at 12:52











  • One little question. The code is working but can I skip numbers? So only text being counted.

    – JGR
    Nov 20 '18 at 13:12











  • Yep, added filtering.

    – Will
    Nov 21 '18 at 18:30
















1














I'm not sure how useful it would be. You end up with meaningless words.






let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





Filtering Added



We can filter the array before counting words, so you can add whatever you like to the filters array to get rid of those words. I probably should have thought of that to begin with...






const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>








share|improve this answer


























  • Thanks man, I will check this code. Looks good. I will let you know if it works

    – JGR
    Nov 20 '18 at 12:52











  • One little question. The code is working but can I skip numbers? So only text being counted.

    – JGR
    Nov 20 '18 at 13:12











  • Yep, added filtering.

    – Will
    Nov 21 '18 at 18:30














1












1








1







I'm not sure how useful it would be. You end up with meaningless words.






let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





Filtering Added



We can filter the array before counting words, so you can add whatever you like to the filters array to get rid of those words. I probably should have thought of that to begin with...






const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>








share|improve this answer















I'm not sure how useful it would be. You end up with meaningless words.






let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





Filtering Added



We can filter the array before counting words, so you can add whatever you like to the filters array to get rid of those words. I probably should have thought of that to begin with...






const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>








let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>





const filters = ['a', 'to', 'the', 'for', 'i'];
let text = document.querySelector('#input').innerText.split(/s/);
let counts = text.map(w => w.toLowerCase()).filter(w => !filters.includes(w)).reduce((acc, cv) => {
if (cv.length > 0)
acc[cv] = acc[cv] + 1 || 1;
return acc;
}, {});
text = Object.keys(counts).sort((a, b) => counts[b] - counts[a]).slice(0, 5);
console.log(text);

<div id="input">
<p>
Is there a little function or plugin to get the top 5 most appearing words on a page? I am building a website with dynamic content and I want to check for most appearing same words.
</p>
<p>
For example: The word 'Spain' is on the page for around 12 times and the word 'Netherlands' for around 8 times. I want to have a function to check this automatically and echo this.
</p>
</div>






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 '18 at 18:29

























answered Nov 15 '18 at 20:37









WillWill

1,79411111




1,79411111













  • Thanks man, I will check this code. Looks good. I will let you know if it works

    – JGR
    Nov 20 '18 at 12:52











  • One little question. The code is working but can I skip numbers? So only text being counted.

    – JGR
    Nov 20 '18 at 13:12











  • Yep, added filtering.

    – Will
    Nov 21 '18 at 18:30



















  • Thanks man, I will check this code. Looks good. I will let you know if it works

    – JGR
    Nov 20 '18 at 12:52











  • One little question. The code is working but can I skip numbers? So only text being counted.

    – JGR
    Nov 20 '18 at 13:12











  • Yep, added filtering.

    – Will
    Nov 21 '18 at 18:30

















Thanks man, I will check this code. Looks good. I will let you know if it works

– JGR
Nov 20 '18 at 12:52





Thanks man, I will check this code. Looks good. I will let you know if it works

– JGR
Nov 20 '18 at 12:52













One little question. The code is working but can I skip numbers? So only text being counted.

– JGR
Nov 20 '18 at 13:12





One little question. The code is working but can I skip numbers? So only text being counted.

– JGR
Nov 20 '18 at 13:12













Yep, added filtering.

– Will
Nov 21 '18 at 18:30





Yep, added filtering.

– Will
Nov 21 '18 at 18:30




















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