Check if a solution exist for a linear congruence with possible zero variable
$begingroup$
(AX + B) mod D = C
I changed it form to AX ≡ (C-B) mod D then try to find if GCD(A,D)|(C-B) if so then a solution exist, but I think this method yields some false result when handling some zeros in it.
Is there any special case that must I know if I want to check if a linear congruence has a solution or not if there can be a one or more zero exist in the equation ?
Example : A and B could be zero, etc.
elementary-number-theory modular-arithmetic
$endgroup$
add a comment |
$begingroup$
(AX + B) mod D = C
I changed it form to AX ≡ (C-B) mod D then try to find if GCD(A,D)|(C-B) if so then a solution exist, but I think this method yields some false result when handling some zeros in it.
Is there any special case that must I know if I want to check if a linear congruence has a solution or not if there can be a one or more zero exist in the equation ?
Example : A and B could be zero, etc.
elementary-number-theory modular-arithmetic
$endgroup$
add a comment |
$begingroup$
(AX + B) mod D = C
I changed it form to AX ≡ (C-B) mod D then try to find if GCD(A,D)|(C-B) if so then a solution exist, but I think this method yields some false result when handling some zeros in it.
Is there any special case that must I know if I want to check if a linear congruence has a solution or not if there can be a one or more zero exist in the equation ?
Example : A and B could be zero, etc.
elementary-number-theory modular-arithmetic
$endgroup$
(AX + B) mod D = C
I changed it form to AX ≡ (C-B) mod D then try to find if GCD(A,D)|(C-B) if so then a solution exist, but I think this method yields some false result when handling some zeros in it.
Is there any special case that must I know if I want to check if a linear congruence has a solution or not if there can be a one or more zero exist in the equation ?
Example : A and B could be zero, etc.
elementary-number-theory modular-arithmetic
elementary-number-theory modular-arithmetic
asked Jan 15 at 4:48
Andrean LayAndrean Lay
83
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