Mixing
Find missing element in an array
3
I've an array consisting english letter a to z except one letter. I dont know which element is missing and I need to find that element using only one loop. I cant use if statements and inbuilt functions.
Is it really possible?. I got this question in an exam and couldn't find any solution and its eating my brain. Any insights appreciated.
// missing 'h'
var letters = ['a','b','c','d','e','f','g','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
for (var i = 0; i < letters.length; i++) {
// find missing letter in 1 loop with no if statements or built-in functions
}
c#
edited Nov 21 '18 at 18:27
mhodges
7,68311231
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
|
show 14 more comments
3
I've an array consisting english letter a to z except one letter. I dont know which element is missing and I need to find that element using only one loop. I cant use if statements and inbuilt functions.
Is it really possible?. I got this question in an exam and couldn't find any solution and its eating my brain. Any insights appreciated.
// missing 'h'
var letters = ['a','b','c','d','e','f','g','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
for (var i = 0; i < letters.length; i++) {
// find missing letter in 1 loop with no if statements or built-in functions
}
c#
edited Nov 21 '18 at 18:27
mhodges
7,68311231
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
4
Is it javascript or c#?
– Jabberwocky
Nov 21 '18 at 17:27
1
I can use either javascript or c#
– Optimus
Nov 21 '18 at 17:27
Does the array have an empty character? Can you use it compared to another array (e.g. the actual alphabet)? You need to have something to cross check.
– Jabberwocky
Nov 21 '18 at 17:28
8
If you give each number a value from 1 to 25 and then total all the number. The total for all 25 would be 325. Then then missing one is 325 - total.
– jdweng
Nov 21 '18 at 17:32
1
What does "can't use any conditions" even mean? Your for loop will have a condition underneath. Does that mean you can't write any if statements yourself?
– Sam Arustamyan
Nov 21 '18 at 17:35
|
show 14 more comments
3
3
3
1
I've an array consisting english letter a to z except one letter. I dont know which element is missing and I need to find that element using only one loop. I cant use if statements and inbuilt functions.
Is it really possible?. I got this question in an exam and couldn't find any solution and its eating my brain. Any insights appreciated.
// missing 'h'
var letters = ['a','b','c','d','e','f','g','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
for (var i = 0; i < letters.length; i++) {
// find missing letter in 1 loop with no if statements or built-in functions
}
c#
edited Nov 21 '18 at 18:27
mhodges
7,68311231
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
I've an array consisting english letter a to z except one letter. I dont know which element is missing and I need to find that element using only one loop. I cant use if statements and inbuilt functions.
Is it really possible?. I got this question in an exam and couldn't find any solution and its eating my brain. Any insights appreciated.
// missing 'h'
var letters = ['a','b','c','d','e','f','g','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
for (var i = 0; i < letters.length; i++) {
// find missing letter in 1 loop with no if statements or built-in functions
}
c#
c#
edited Nov 21 '18 at 18:27
mhodges
7,68311231
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
edited Nov 21 '18 at 18:27
mhodges
7,68311231
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
edited Nov 21 '18 at 18:27
mhodges
7,68311231
edited Nov 21 '18 at 18:27
mhodges
7,68311231
edited Nov 21 '18 at 18:27
mhodges
7,68311231
7,68311231
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
asked Nov 21 '18 at 17:24
OptimusOptimus
1,24262858
1,24262858
4
Is it javascript or c#?
– Jabberwocky
Nov 21 '18 at 17:27
1
I can use either javascript or c#
– Optimus
Nov 21 '18 at 17:27
Does the array have an empty character? Can you use it compared to another array (e.g. the actual alphabet)? You need to have something to cross check.
– Jabberwocky
Nov 21 '18 at 17:28
8
If you give each number a value from 1 to 25 and then total all the number. The total for all 25 would be 325. Then then missing one is 325 - total.
– jdweng
Nov 21 '18 at 17:32
1
What does "can't use any conditions" even mean? Your for loop will have a condition underneath. Does that mean you can't write any if statements yourself?
– Sam Arustamyan
Nov 21 '18 at 17:35
|
show 14 more comments
4
Is it javascript or c#?
– Jabberwocky
Nov 21 '18 at 17:27
1
I can use either javascript or c#
– Optimus
Nov 21 '18 at 17:27
Does the array have an empty character? Can you use it compared to another array (e.g. the actual alphabet)? You need to have something to cross check.
– Jabberwocky
Nov 21 '18 at 17:28
8
If you give each number a value from 1 to 25 and then total all the number. The total for all 25 would be 325. Then then missing one is 325 - total.
– jdweng
Nov 21 '18 at 17:32
1
What does "can't use any conditions" even mean? Your for loop will have a condition underneath. Does that mean you can't write any if statements yourself?
– Sam Arustamyan
Nov 21 '18 at 17:35
4
4
Is it javascript or c#?
– Jabberwocky
Nov 21 '18 at 17:27
Is it javascript or c#?
– Jabberwocky
Nov 21 '18 at 17:27
1
1
I can use either javascript or c#
– Optimus
Nov 21 '18 at 17:27
I can use either javascript or c#
– Optimus
Nov 21 '18 at 17:27
Does the array have an empty character? Can you use it compared to another array (e.g. the actual alphabet)? You need to have something to cross check.
– Jabberwocky
Nov 21 '18 at 17:28
Does the array have an empty character? Can you use it compared to another array (e.g. the actual alphabet)? You need to have something to cross check.
– Jabberwocky
Nov 21 '18 at 17:28
8
8
If you give each number a value from 1 to 25 and then total all the number. The total for all 25 would be 325. Then then missing one is 325 - total.
– jdweng
Nov 21 '18 at 17:32
If you give each number a value from 1 to 25 and then total all the number. The total for all 25 would be 325. Then then missing one is 325 - total.
– jdweng
Nov 21 '18 at 17:32
1
1
What does "can't use any conditions" even mean? Your for loop will have a condition underneath. Does that mean you can't write any if statements yourself?
– Sam Arustamyan
Nov 21 '18 at 17:35
What does "can't use any conditions" even mean? Your for loop will have a condition underneath. Does that mean you can't write any if statements yourself?
– Sam Arustamyan
Nov 21 '18 at 17:35
|
show 14 more comments
3 Answers
3
active
oldest
votes
3
Here is code :
char inputs = { 'a', 'b', 'c', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
int total = 0;
foreach (char c in inputs)
{
total += (int)c - (int)'a';
}
char missingChar = (char)((int)('a') + (325 - total));
// version 2
total = 0;
//from sum of a arithmetic sequence for even number of values
// for example 1 + 2 + 3 + 4 = (1 + 4) + (2 + 3) = 2 * 5 = 10
int expectedTotal = 13 * ((int)'a' + (int)'z');
foreach (char c in inputs)
{
total += (int)c;
}
missingChar = (char)((expectedTotal - total));
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
add a comment |
0
Here is another way of doing it without using any loop just list functions(Console Application) it also take care of lower upper case comparison issue:
namespace MissingAlphbetLetters
{
class Program
{
public static List<char> CheckDifferences(char str)
{
List<char> alphabet= new List<char>(new char
{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'});
List<char> compaired = str.ToList().ConvertAll(l => char.ToLower(l));
List<char> difference = new List<char>();
if (str.Length > 0)
{
difference = alphabet.Except(compaired).ToList();
}
return difference;
}
static void Main(string args)
{
Console.Write(string.Join(",",CheckDifferences(new char { 'A', 'g', 't', 'h', 'o', 'm', 'd', 'e' })));
Console.ReadLine();
}
}
}
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
add a comment |
0
class Program
{
private static void FindLetter(string alphabet, string yourMissingLetter)
{
for (var i = 0; i < yourMissingLetter.Length; i++)
{
var isit = alphabet[i] == yourMissingLetter[i];
Console.WriteLine("alphabet[{0}] = {1}", alphabet[i], isit);
}
}
static void Main(string args)
{
string alphabet = { "A", "B", "C", "D" };
// let's say your array is missing B
string yourMissingLetterArray = { "A", "C", "D" };
FindLetter(alphabet, yourMissingLetterArray);
}
}
not as brilliant as the actual answer but this will work:
The moment it starts missing the letter will turn false and the index will show you which letter it is.
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
|
show 3 more comments
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
Here is code :
char inputs = { 'a', 'b', 'c', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
int total = 0;
foreach (char c in inputs)
{
total += (int)c - (int)'a';
}
char missingChar = (char)((int)('a') + (325 - total));
// version 2
total = 0;
//from sum of a arithmetic sequence for even number of values
// for example 1 + 2 + 3 + 4 = (1 + 4) + (2 + 3) = 2 * 5 = 10
int expectedTotal = 13 * ((int)'a' + (int)'z');
foreach (char c in inputs)
{
total += (int)c;
}
missingChar = (char)((expectedTotal - total));
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
add a comment |
3
Here is code :
char inputs = { 'a', 'b', 'c', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
int total = 0;
foreach (char c in inputs)
{
total += (int)c - (int)'a';
}
char missingChar = (char)((int)('a') + (325 - total));
// version 2
total = 0;
//from sum of a arithmetic sequence for even number of values
// for example 1 + 2 + 3 + 4 = (1 + 4) + (2 + 3) = 2 * 5 = 10
int expectedTotal = 13 * ((int)'a' + (int)'z');
foreach (char c in inputs)
{
total += (int)c;
}
missingChar = (char)((expectedTotal - total));
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
add a comment |
3
3
3
Here is code :
char inputs = { 'a', 'b', 'c', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
int total = 0;
foreach (char c in inputs)
{
total += (int)c - (int)'a';
}
char missingChar = (char)((int)('a') + (325 - total));
// version 2
total = 0;
//from sum of a arithmetic sequence for even number of values
// for example 1 + 2 + 3 + 4 = (1 + 4) + (2 + 3) = 2 * 5 = 10
int expectedTotal = 13 * ((int)'a' + (int)'z');
foreach (char c in inputs)
{
total += (int)c;
}
missingChar = (char)((expectedTotal - total));
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
Here is code :
char inputs = { 'a', 'b', 'c', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
int total = 0;
foreach (char c in inputs)
{
total += (int)c - (int)'a';
}
char missingChar = (char)((int)('a') + (325 - total));
// version 2
total = 0;
//from sum of a arithmetic sequence for even number of values
// for example 1 + 2 + 3 + 4 = (1 + 4) + (2 + 3) = 2 * 5 = 10
int expectedTotal = 13 * ((int)'a' + (int)'z');
foreach (char c in inputs)
{
total += (int)c;
}
missingChar = (char)((expectedTotal - total));
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
edited Nov 22 '18 at 21:22
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
answered Nov 21 '18 at 18:03
jdwengjdweng
17.4k2717
17.4k2717
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
add a comment |
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Seriously man.. now I can sleep
– Optimus
Nov 21 '18 at 18:05
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
Super creative solution
– roozbeh S
Nov 21 '18 at 20:12
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I didn't event this. Learned it ages ago. The trick of programming is learning algorithms, remembering the algorithms, then applying algorithms to current programming task.
– jdweng
Nov 21 '18 at 22:15
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
I added a version 2 of the code which is even simpler than original.
– jdweng
Nov 22 '18 at 21:17
add a comment |
0
Here is another way of doing it without using any loop just list functions(Console Application) it also take care of lower upper case comparison issue:
namespace MissingAlphbetLetters
{
class Program
{
public static List<char> CheckDifferences(char str)
{
List<char> alphabet= new List<char>(new char
{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'});
List<char> compaired = str.ToList().ConvertAll(l => char.ToLower(l));
List<char> difference = new List<char>();
if (str.Length > 0)
{
difference = alphabet.Except(compaired).ToList();
}
return difference;
}
static void Main(string args)
{
Console.Write(string.Join(",",CheckDifferences(new char { 'A', 'g', 't', 'h', 'o', 'm', 'd', 'e' })));
Console.ReadLine();
}
}
}
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
add a comment |
0
Here is another way of doing it without using any loop just list functions(Console Application) it also take care of lower upper case comparison issue:
namespace MissingAlphbetLetters
{
class Program
{
public static List<char> CheckDifferences(char str)
{
List<char> alphabet= new List<char>(new char
{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'});
List<char> compaired = str.ToList().ConvertAll(l => char.ToLower(l));
List<char> difference = new List<char>();
if (str.Length > 0)
{
difference = alphabet.Except(compaired).ToList();
}
return difference;
}
static void Main(string args)
{
Console.Write(string.Join(",",CheckDifferences(new char { 'A', 'g', 't', 'h', 'o', 'm', 'd', 'e' })));
Console.ReadLine();
}
}
}
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
add a comment |
0
0
0
Here is another way of doing it without using any loop just list functions(Console Application) it also take care of lower upper case comparison issue:
namespace MissingAlphbetLetters
{
class Program
{
public static List<char> CheckDifferences(char str)
{
List<char> alphabet= new List<char>(new char
{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'});
List<char> compaired = str.ToList().ConvertAll(l => char.ToLower(l));
List<char> difference = new List<char>();
if (str.Length > 0)
{
difference = alphabet.Except(compaired).ToList();
}
return difference;
}
static void Main(string args)
{
Console.Write(string.Join(",",CheckDifferences(new char { 'A', 'g', 't', 'h', 'o', 'm', 'd', 'e' })));
Console.ReadLine();
}
}
}
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
Here is another way of doing it without using any loop just list functions(Console Application) it also take care of lower upper case comparison issue:
namespace MissingAlphbetLetters
{
class Program
{
public static List<char> CheckDifferences(char str)
{
List<char> alphabet= new List<char>(new char
{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'});
List<char> compaired = str.ToList().ConvertAll(l => char.ToLower(l));
List<char> difference = new List<char>();
if (str.Length > 0)
{
difference = alphabet.Except(compaired).ToList();
}
return difference;
}
static void Main(string args)
{
Console.Write(string.Join(",",CheckDifferences(new char { 'A', 'g', 't', 'h', 'o', 'm', 'd', 'e' })));
Console.ReadLine();
}
}
}
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
answered Nov 21 '18 at 18:37
GeorgeTGeorgeT
114
114
add a comment |
add a comment |
0
class Program
{
private static void FindLetter(string alphabet, string yourMissingLetter)
{
for (var i = 0; i < yourMissingLetter.Length; i++)
{
var isit = alphabet[i] == yourMissingLetter[i];
Console.WriteLine("alphabet[{0}] = {1}", alphabet[i], isit);
}
}
static void Main(string args)
{
string alphabet = { "A", "B", "C", "D" };
// let's say your array is missing B
string yourMissingLetterArray = { "A", "C", "D" };
FindLetter(alphabet, yourMissingLetterArray);
}
}
not as brilliant as the actual answer but this will work:
The moment it starts missing the letter will turn false and the index will show you which letter it is.
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
|
show 3 more comments
0
class Program
{
private static void FindLetter(string alphabet, string yourMissingLetter)
{
for (var i = 0; i < yourMissingLetter.Length; i++)
{
var isit = alphabet[i] == yourMissingLetter[i];
Console.WriteLine("alphabet[{0}] = {1}", alphabet[i], isit);
}
}
static void Main(string args)
{
string alphabet = { "A", "B", "C", "D" };
// let's say your array is missing B
string yourMissingLetterArray = { "A", "C", "D" };
FindLetter(alphabet, yourMissingLetterArray);
}
}
not as brilliant as the actual answer but this will work:
The moment it starts missing the letter will turn false and the index will show you which letter it is.
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
|
show 3 more comments
0
0
0
class Program
{
private static void FindLetter(string alphabet, string yourMissingLetter)
{
for (var i = 0; i < yourMissingLetter.Length; i++)
{
var isit = alphabet[i] == yourMissingLetter[i];
Console.WriteLine("alphabet[{0}] = {1}", alphabet[i], isit);
}
}
static void Main(string args)
{
string alphabet = { "A", "B", "C", "D" };
// let's say your array is missing B
string yourMissingLetterArray = { "A", "C", "D" };
FindLetter(alphabet, yourMissingLetterArray);
}
}
not as brilliant as the actual answer but this will work:
The moment it starts missing the letter will turn false and the index will show you which letter it is.
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
class Program
{
private static void FindLetter(string alphabet, string yourMissingLetter)
{
for (var i = 0; i < yourMissingLetter.Length; i++)
{
var isit = alphabet[i] == yourMissingLetter[i];
Console.WriteLine("alphabet[{0}] = {1}", alphabet[i], isit);
}
}
static void Main(string args)
{
string alphabet = { "A", "B", "C", "D" };
// let's say your array is missing B
string yourMissingLetterArray = { "A", "C", "D" };
FindLetter(alphabet, yourMissingLetterArray);
}
}
not as brilliant as the actual answer but this will work:
The moment it starts missing the letter will turn false and the index will show you which letter it is.
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
edited Nov 27 '18 at 17:20
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
answered Nov 21 '18 at 18:11
JabberwockyJabberwocky
1238
1238
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
|
show 3 more comments
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
This only works if the array is sorted. The actual answer work if the array is not sorted.
– jdweng
Nov 26 '18 at 10:09
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
@jdweng they asked the guy if the array is sorted and he said yes. So this works.
– Jabberwocky
Nov 26 '18 at 19:35
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
Did you test your code? How many print statements does your code output?
– jdweng
Nov 26 '18 at 20:15
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
@jdweng Assuming it would be the whole alphabet it would print 26 and once you've reached the false, you'd look at the index and find which letter it is. or vice versa. To answer your question, now it prints 3 times.
– Jabberwocky
Nov 27 '18 at 17:05
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
And what letters does it say that it is missing?
– jdweng
Nov 27 '18 at 17:11
|
show 3 more comments
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4
Is it javascript or c#?
– Jabberwocky
Nov 21 '18 at 17:27
1
I can use either javascript or c#
– Optimus
Nov 21 '18 at 17:27
Does the array have an empty character? Can you use it compared to another array (e.g. the actual alphabet)? You need to have something to cross check.
– Jabberwocky
Nov 21 '18 at 17:28
8
If you give each number a value from 1 to 25 and then total all the number. The total for all 25 would be 325. Then then missing one is 325 - total.
– jdweng
Nov 21 '18 at 17:32
1
What does "can't use any conditions" even mean? Your for loop will have a condition underneath. Does that mean you can't write any if statements yourself?
– Sam Arustamyan
Nov 21 '18 at 17:35