Mixing
How is the combinatorics formula derived [duplicate]
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This question already has an answer here:
How to understand the combination formula?
3 answers
Prove $binom{n}{k} = frac {n!}{k!(n - k)!} text { where } 0 le k le n.$
2 answers
Basically what I want to know is how you derive $$frac{n!}{r!(n-r)!}$$ from the number of combinations of $r$ objects in n places. Essentially I couldn't work out why it was and just need an explanation. Any help appreciated. Thank you.
combinatorics
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
asked Jan 14 at 22:35
TommyTommy
1
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Jan 14 at 22:54
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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$begingroup$
This question already has an answer here:
How to understand the combination formula?
3 answers
Prove $binom{n}{k} = frac {n!}{k!(n - k)!} text { where } 0 le k le n.$
2 answers
Basically what I want to know is how you derive $$frac{n!}{r!(n-r)!}$$ from the number of combinations of $r$ objects in n places. Essentially I couldn't work out why it was and just need an explanation. Any help appreciated. Thank you.
combinatorics
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
asked Jan 14 at 22:35
TommyTommy
1
$endgroup$
marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig combinatorics
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Jan 14 at 22:54
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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there are n! total ways to permute the n objects. But you can permute the r indistinguishable objects in r! ways. Likewise with the (n-r)! spaces that are not occupied by anything.
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– Justin Stevenson
Jan 14 at 22:43
add a comment |
$begingroup$
This question already has an answer here:
How to understand the combination formula?
3 answers
Prove $binom{n}{k} = frac {n!}{k!(n - k)!} text { where } 0 le k le n.$
2 answers
Basically what I want to know is how you derive $$frac{n!}{r!(n-r)!}$$ from the number of combinations of $r$ objects in n places. Essentially I couldn't work out why it was and just need an explanation. Any help appreciated. Thank you.
combinatorics
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
asked Jan 14 at 22:35
TommyTommy
1
$endgroup$
This question already has an answer here:
How to understand the combination formula?
3 answers
Prove $binom{n}{k} = frac {n!}{k!(n - k)!} text { where } 0 le k le n.$
2 answers
Basically what I want to know is how you derive $$frac{n!}{r!(n-r)!}$$ from the number of combinations of $r$ objects in n places. Essentially I couldn't work out why it was and just need an explanation. Any help appreciated. Thank you.
This question already has an answer here:
How to understand the combination formula?
3 answers
Prove $binom{n}{k} = frac {n!}{k!(n - k)!} text { where } 0 le k le n.$
2 answers
combinatorics
combinatorics
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
asked Jan 14 at 22:35
TommyTommy
1
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
asked Jan 14 at 22:35
TommyTommy
1
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
edited Jan 14 at 22:53
N. F. Taussig
44.3k93356
44.3k93356
asked Jan 14 at 22:35
TommyTommy
1
asked Jan 14 at 22:35
TommyTommy
1
asked Jan 14 at 22:35
TommyTommy
1
1
marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig combinatorics
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Jan 14 at 22:54
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by GNUSupporter 8964民主女神 地下教會, N. F. Taussig combinatorics
Users with the combinatorics badge can single-handedly close combinatorics questions as duplicates and reopen them as needed.
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Jan 14 at 22:54
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
$begingroup$
there are n! total ways to permute the n objects. But you can permute the r indistinguishable objects in r! ways. Likewise with the (n-r)! spaces that are not occupied by anything.
$endgroup$
– Justin Stevenson
Jan 14 at 22:43
add a comment |
$begingroup$
there are n! total ways to permute the n objects. But you can permute the r indistinguishable objects in r! ways. Likewise with the (n-r)! spaces that are not occupied by anything.
$endgroup$
– Justin Stevenson
Jan 14 at 22:43
$begingroup$
there are n! total ways to permute the n objects. But you can permute the r indistinguishable objects in r! ways. Likewise with the (n-r)! spaces that are not occupied by anything.
$endgroup$
– Justin Stevenson
Jan 14 at 22:43
$begingroup$
there are n! total ways to permute the n objects. But you can permute the r indistinguishable objects in r! ways. Likewise with the (n-r)! spaces that are not occupied by anything.
$endgroup$
– Justin Stevenson
Jan 14 at 22:43
add a comment |
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$begingroup$
there are n! total ways to permute the n objects. But you can permute the r indistinguishable objects in r! ways. Likewise with the (n-r)! spaces that are not occupied by anything.
$endgroup$
– Justin Stevenson
Jan 14 at 22:43