Mixing
how to check my file is created within 10 days in shell script
0
I have a bunch of log files which are named according to their creation dates. For example; if my log file is created on 12 March 2018, the name of the logfile is log-2018-03-12.log
Here is what I want to do: From today's date, I want to check the name of my log files and zip the log files which are created in last 10 days.
Here is my code that zip all log files in a specific directory:
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/opt/MyStore/action_scripts/deneme/
tendaysbefore= date -d "$now - 10 days" '+%F'
for file in $scripthome;
do
find "$(basename "$file")" | zip -R $backupfile.zip "log-2*.log"
done
But I want to zip last 10 days log file, not all log files, and also I want to continue doing it for every 10 days after this. Also, after having zip file, I want to delete old log files.
In other words, I am trying to write a log-backup script. Can you help me please?
Thank you very much!
linux shell date
asked Nov 19 '18 at 13:14
smsms
54
add a comment |
0
I have a bunch of log files which are named according to their creation dates. For example; if my log file is created on 12 March 2018, the name of the logfile is log-2018-03-12.log
Here is what I want to do: From today's date, I want to check the name of my log files and zip the log files which are created in last 10 days.
Here is my code that zip all log files in a specific directory:
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/opt/MyStore/action_scripts/deneme/
tendaysbefore= date -d "$now - 10 days" '+%F'
for file in $scripthome;
do
find "$(basename "$file")" | zip -R $backupfile.zip "log-2*.log"
done
But I want to zip last 10 days log file, not all log files, and also I want to continue doing it for every 10 days after this. Also, after having zip file, I want to delete old log files.
In other words, I am trying to write a log-backup script. Can you help me please?
Thank you very much!
linux shell date
asked Nov 19 '18 at 13:14
smsms
54
Does this help you? stackoverflow.com/questions/158044/…
– Dominique
Nov 19 '18 at 13:21
@Dominique I tried adding find . -type f -newerct $tendaysbefore ! -newerct $now But it gives me this error: find: I cannot figure out how to interpret ‘!’ as a date or time
– smsms
Nov 19 '18 at 13:53
That is because your$tendaysbeforeis empty thus executing the actual commandfind . -type f -newerct ! …. Probably because your script above is incorrect. At the very least you want something like:tendaysbefore=$(date -d "$now - 10 days" '+%F')
– grifferz
Nov 19 '18 at 21:22
Actually it is not empty. I can print the value in it and it is correct. The error is most probably caused by syntax that '!' is not understood by the compiler. Any suggestion about this? @grifferz
– smsms
Nov 20 '18 at 6:14
I'm sorry, but you are mistaken. Running your code above results intendaysbeforebeing left empty, that is why find gives you that error. Your assignment totendaysbeforeis missing$()around the date command as I said.
– grifferz
Nov 20 '18 at 15:00
add a comment |
0
0
0
I have a bunch of log files which are named according to their creation dates. For example; if my log file is created on 12 March 2018, the name of the logfile is log-2018-03-12.log
Here is what I want to do: From today's date, I want to check the name of my log files and zip the log files which are created in last 10 days.
Here is my code that zip all log files in a specific directory:
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/opt/MyStore/action_scripts/deneme/
tendaysbefore= date -d "$now - 10 days" '+%F'
for file in $scripthome;
do
find "$(basename "$file")" | zip -R $backupfile.zip "log-2*.log"
done
But I want to zip last 10 days log file, not all log files, and also I want to continue doing it for every 10 days after this. Also, after having zip file, I want to delete old log files.
In other words, I am trying to write a log-backup script. Can you help me please?
Thank you very much!
linux shell date
asked Nov 19 '18 at 13:14
smsms
54
I have a bunch of log files which are named according to their creation dates. For example; if my log file is created on 12 March 2018, the name of the logfile is log-2018-03-12.log
Here is what I want to do: From today's date, I want to check the name of my log files and zip the log files which are created in last 10 days.
Here is my code that zip all log files in a specific directory:
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/opt/MyStore/action_scripts/deneme/
tendaysbefore= date -d "$now - 10 days" '+%F'
for file in $scripthome;
do
find "$(basename "$file")" | zip -R $backupfile.zip "log-2*.log"
done
But I want to zip last 10 days log file, not all log files, and also I want to continue doing it for every 10 days after this. Also, after having zip file, I want to delete old log files.
In other words, I am trying to write a log-backup script. Can you help me please?
Thank you very much!
linux shell date
linux shell date
asked Nov 19 '18 at 13:14
smsms
54
asked Nov 19 '18 at 13:14
smsms
54
edited Nov 21 '18 at 6:02
asked Nov 19 '18 at 13:14
smsms
54
asked Nov 19 '18 at 13:14
smsms
54
asked Nov 19 '18 at 13:14
smsms
54
54
Does this help you? stackoverflow.com/questions/158044/…
– Dominique
Nov 19 '18 at 13:21
@Dominique I tried adding find . -type f -newerct $tendaysbefore ! -newerct $now But it gives me this error: find: I cannot figure out how to interpret ‘!’ as a date or time
– smsms
Nov 19 '18 at 13:53
That is because your$tendaysbeforeis empty thus executing the actual commandfind . -type f -newerct ! …. Probably because your script above is incorrect. At the very least you want something like:tendaysbefore=$(date -d "$now - 10 days" '+%F')
– grifferz
Nov 19 '18 at 21:22
Actually it is not empty. I can print the value in it and it is correct. The error is most probably caused by syntax that '!' is not understood by the compiler. Any suggestion about this? @grifferz
– smsms
Nov 20 '18 at 6:14
I'm sorry, but you are mistaken. Running your code above results intendaysbeforebeing left empty, that is why find gives you that error. Your assignment totendaysbeforeis missing$()around the date command as I said.
– grifferz
Nov 20 '18 at 15:00
add a comment |
Does this help you? stackoverflow.com/questions/158044/…
– Dominique
Nov 19 '18 at 13:21
@Dominique I tried adding find . -type f -newerct $tendaysbefore ! -newerct $now But it gives me this error: find: I cannot figure out how to interpret ‘!’ as a date or time
– smsms
Nov 19 '18 at 13:53
That is because your$tendaysbeforeis empty thus executing the actual commandfind . -type f -newerct ! …. Probably because your script above is incorrect. At the very least you want something like:tendaysbefore=$(date -d "$now - 10 days" '+%F')
– grifferz
Nov 19 '18 at 21:22
Actually it is not empty. I can print the value in it and it is correct. The error is most probably caused by syntax that '!' is not understood by the compiler. Any suggestion about this? @grifferz
– smsms
Nov 20 '18 at 6:14
I'm sorry, but you are mistaken. Running your code above results intendaysbeforebeing left empty, that is why find gives you that error. Your assignment totendaysbeforeis missing$()around the date command as I said.
– grifferz
Nov 20 '18 at 15:00
Does this help you? stackoverflow.com/questions/158044/…
– Dominique
Nov 19 '18 at 13:21
Does this help you? stackoverflow.com/questions/158044/…
– Dominique
Nov 19 '18 at 13:21
@Dominique I tried adding find . -type f -newerct $tendaysbefore ! -newerct $now But it gives me this error: find: I cannot figure out how to interpret ‘!’ as a date or time
– smsms
Nov 19 '18 at 13:53
@Dominique I tried adding find . -type f -newerct $tendaysbefore ! -newerct $now But it gives me this error: find: I cannot figure out how to interpret ‘!’ as a date or time
– smsms
Nov 19 '18 at 13:53
That is because your
$tendaysbefore is empty thus executing the actual command find . -type f -newerct ! …. Probably because your script above is incorrect. At the very least you want something like: tendaysbefore=$(date -d "$now - 10 days" '+%F')– grifferz
Nov 19 '18 at 21:22
That is because your
$tendaysbefore is empty thus executing the actual command find . -type f -newerct ! …. Probably because your script above is incorrect. At the very least you want something like: tendaysbefore=$(date -d "$now - 10 days" '+%F')– grifferz
Nov 19 '18 at 21:22
Actually it is not empty. I can print the value in it and it is correct. The error is most probably caused by syntax that '!' is not understood by the compiler. Any suggestion about this? @grifferz
– smsms
Nov 20 '18 at 6:14
Actually it is not empty. I can print the value in it and it is correct. The error is most probably caused by syntax that '!' is not understood by the compiler. Any suggestion about this? @grifferz
– smsms
Nov 20 '18 at 6:14
I'm sorry, but you are mistaken. Running your code above results in
tendaysbefore being left empty, that is why find gives you that error. Your assignment to tendaysbefore is missing $() around the date command as I said.– grifferz
Nov 20 '18 at 15:00
I'm sorry, but you are mistaken. Running your code above results in
tendaysbefore being left empty, that is why find gives you that error. Your assignment to tendaysbefore is missing $() around the date command as I said.– grifferz
Nov 20 '18 at 15:00
add a comment |
1 Answer
1
active
oldest
votes
0
#!/bin/bash
END=10
for ((i=1;i<=END;i++)); do
file=log-`date -d "$i days ago" +"%F"`.log
echo $file
done
With the above script you have file names for last 10 days. Later(inside loop) you can do whatever you want like adding it to existing zip or searching for its existence.
Edit:
Following code may be useful according to your requirement
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/home/bhanu/opt/MyStore/action_scripts/deneme/
tendaysbefore=`date -d "$now - 10 days" '+%F'`
for file in $scripthome;
do
zip -r -tt $now -t $tendaysbefore "$backupfile.zip" $scripthome/log-*.log > add.log 2>&1
zip "$backupfile.zip" -d "*" -tt $tendaysbefore > delete.log 2>&1
done
answered Nov 19 '18 at 14:15
bhanu7k
535
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
|
show 2 more comments
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0
#!/bin/bash
END=10
for ((i=1;i<=END;i++)); do
file=log-`date -d "$i days ago" +"%F"`.log
echo $file
done
With the above script you have file names for last 10 days. Later(inside loop) you can do whatever you want like adding it to existing zip or searching for its existence.
Edit:
Following code may be useful according to your requirement
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/home/bhanu/opt/MyStore/action_scripts/deneme/
tendaysbefore=`date -d "$now - 10 days" '+%F'`
for file in $scripthome;
do
zip -r -tt $now -t $tendaysbefore "$backupfile.zip" $scripthome/log-*.log > add.log 2>&1
zip "$backupfile.zip" -d "*" -tt $tendaysbefore > delete.log 2>&1
done
answered Nov 19 '18 at 14:15
bhanu7k
535
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
|
show 2 more comments
0
#!/bin/bash
END=10
for ((i=1;i<=END;i++)); do
file=log-`date -d "$i days ago" +"%F"`.log
echo $file
done
With the above script you have file names for last 10 days. Later(inside loop) you can do whatever you want like adding it to existing zip or searching for its existence.
Edit:
Following code may be useful according to your requirement
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/home/bhanu/opt/MyStore/action_scripts/deneme/
tendaysbefore=`date -d "$now - 10 days" '+%F'`
for file in $scripthome;
do
zip -r -tt $now -t $tendaysbefore "$backupfile.zip" $scripthome/log-*.log > add.log 2>&1
zip "$backupfile.zip" -d "*" -tt $tendaysbefore > delete.log 2>&1
done
answered Nov 19 '18 at 14:15
bhanu7k
535
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
|
show 2 more comments
0
0
0
#!/bin/bash
END=10
for ((i=1;i<=END;i++)); do
file=log-`date -d "$i days ago" +"%F"`.log
echo $file
done
With the above script you have file names for last 10 days. Later(inside loop) you can do whatever you want like adding it to existing zip or searching for its existence.
Edit:
Following code may be useful according to your requirement
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/home/bhanu/opt/MyStore/action_scripts/deneme/
tendaysbefore=`date -d "$now - 10 days" '+%F'`
for file in $scripthome;
do
zip -r -tt $now -t $tendaysbefore "$backupfile.zip" $scripthome/log-*.log > add.log 2>&1
zip "$backupfile.zip" -d "*" -tt $tendaysbefore > delete.log 2>&1
done
answered Nov 19 '18 at 14:15
bhanu7k
535
#!/bin/bash
END=10
for ((i=1;i<=END;i++)); do
file=log-`date -d "$i days ago" +"%F"`.log
echo $file
done
With the above script you have file names for last 10 days. Later(inside loop) you can do whatever you want like adding it to existing zip or searching for its existence.
Edit:
Following code may be useful according to your requirement
#!/bin/bash
# current time
now=$(date +"%F")
backupfile="backup-$now"
scripthome=/home/bhanu/opt/MyStore/action_scripts/deneme/
tendaysbefore=`date -d "$now - 10 days" '+%F'`
for file in $scripthome;
do
zip -r -tt $now -t $tendaysbefore "$backupfile.zip" $scripthome/log-*.log > add.log 2>&1
zip "$backupfile.zip" -d "*" -tt $tendaysbefore > delete.log 2>&1
done
answered Nov 19 '18 at 14:15
bhanu7k
535
edited Nov 20 '18 at 7:38
answered Nov 19 '18 at 14:15
bhanu7k
535
answered Nov 19 '18 at 14:15
bhanu7k
535
answered Nov 19 '18 at 14:15
bhanu7k
535
535
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
|
show 2 more comments
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Thx for your answer. But I already have many log files and do not need to create any more. What I am asking for is how to find the ones that are created in last 10 days and I also want to zip these log files (which are created in last 10 days) in every 10 days. So this is like making a back-up script for my log files(which are created every day) in every 10 days. So your answer is not what I am looking for. Now, do you have any other suggestion?
– smsms
Nov 19 '18 at 14:51
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Updated my answer
– bhanu7k
Nov 20 '18 at 7:38
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Thanks! I guess it is working.. but I am a lil bit confused..what does 2>&1 mean? also -tt?
– smsms
Nov 20 '18 at 12:29
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
Oh I got 2>&1 but -tt and -t still are still confusing. Can you please briefly explain them? Thanks!
– smsms
Nov 20 '18 at 14:35
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
try to read the output of zip -h2. It will give description of lot of options using zip. -t and -tt are the options to set the date range.
– bhanu7k
Nov 21 '18 at 6:01
|
show 2 more comments
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Does this help you? stackoverflow.com/questions/158044/…
– Dominique
Nov 19 '18 at 13:21
@Dominique I tried adding find . -type f -newerct $tendaysbefore ! -newerct $now But it gives me this error: find: I cannot figure out how to interpret ‘!’ as a date or time
– smsms
Nov 19 '18 at 13:53
That is because your
$tendaysbeforeis empty thus executing the actual commandfind . -type f -newerct ! …. Probably because your script above is incorrect. At the very least you want something like:tendaysbefore=$(date -d "$now - 10 days" '+%F')– grifferz
Nov 19 '18 at 21:22
Actually it is not empty. I can print the value in it and it is correct. The error is most probably caused by syntax that '!' is not understood by the compiler. Any suggestion about this? @grifferz
– smsms
Nov 20 '18 at 6:14
I'm sorry, but you are mistaken. Running your code above results in
tendaysbeforebeing left empty, that is why find gives you that error. Your assignment totendaysbeforeis missing$()around the date command as I said.– grifferz
Nov 20 '18 at 15:00