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There is a particle moving along the $x$ -axis at any time $t geq 0$ . The velocity of this particle is given by $$v(t) = cos(πt) - t(6-2pi).$$ I am supposed to find the particle's minimum velocity over the interval $[0,2]$ . I found the derivative of this velocity function and set it equal to zero, but I am having trouble with getting the right answer. I used the option on my calculator to find the min, but I can’t seen to find it using calculus. Help is greatly appreciated!
calculus derivatives
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edited Jan 16 at 4:16
AEngineer
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