Integral with respect to the uniform measure on the sphere












0














I would need a hint to solve the following problem.



Let $d varphi$ be denote the normalised uniform measure on $mathbb{S}^{N-1}$, which is the $N-1$ dimensional sphere, where $N in mathbb{N}_{>0}$. How to prove that,
for arbitrary non-negative integers, $n_1$, $ldots$, $n_N$, we have that
$$
int_{mathbb{S}^{N-1}} d varphi , , {big ( varphi^1 big )}^{2 n_1} ldots
{big (varphi^N big )}^{2 n_N} =
frac{ Gamma(N/2)}{2^n Gamma(n + N/2)} prod_{i=1}^{N} (2n_i - 1)!!,
$$

where $n= n_1 + ldots + n_N$ and we used the notation $varphi =( varphi^1, ldots, varphi^N) in mathbb{R}^N$.



Here $Gamma(x)$ is the *Gamma function" and "!!" is the double factorial. These objects are defined here:
https://en.wikipedia.org/wiki/Double_factorial;
https://en.wikipedia.org/wiki/Gamma_function.










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    0














    I would need a hint to solve the following problem.



    Let $d varphi$ be denote the normalised uniform measure on $mathbb{S}^{N-1}$, which is the $N-1$ dimensional sphere, where $N in mathbb{N}_{>0}$. How to prove that,
    for arbitrary non-negative integers, $n_1$, $ldots$, $n_N$, we have that
    $$
    int_{mathbb{S}^{N-1}} d varphi , , {big ( varphi^1 big )}^{2 n_1} ldots
    {big (varphi^N big )}^{2 n_N} =
    frac{ Gamma(N/2)}{2^n Gamma(n + N/2)} prod_{i=1}^{N} (2n_i - 1)!!,
    $$

    where $n= n_1 + ldots + n_N$ and we used the notation $varphi =( varphi^1, ldots, varphi^N) in mathbb{R}^N$.



    Here $Gamma(x)$ is the *Gamma function" and "!!" is the double factorial. These objects are defined here:
    https://en.wikipedia.org/wiki/Double_factorial;
    https://en.wikipedia.org/wiki/Gamma_function.










    share|cite|improve this question



























      0












      0








      0







      I would need a hint to solve the following problem.



      Let $d varphi$ be denote the normalised uniform measure on $mathbb{S}^{N-1}$, which is the $N-1$ dimensional sphere, where $N in mathbb{N}_{>0}$. How to prove that,
      for arbitrary non-negative integers, $n_1$, $ldots$, $n_N$, we have that
      $$
      int_{mathbb{S}^{N-1}} d varphi , , {big ( varphi^1 big )}^{2 n_1} ldots
      {big (varphi^N big )}^{2 n_N} =
      frac{ Gamma(N/2)}{2^n Gamma(n + N/2)} prod_{i=1}^{N} (2n_i - 1)!!,
      $$

      where $n= n_1 + ldots + n_N$ and we used the notation $varphi =( varphi^1, ldots, varphi^N) in mathbb{R}^N$.



      Here $Gamma(x)$ is the *Gamma function" and "!!" is the double factorial. These objects are defined here:
      https://en.wikipedia.org/wiki/Double_factorial;
      https://en.wikipedia.org/wiki/Gamma_function.










      share|cite|improve this question















      I would need a hint to solve the following problem.



      Let $d varphi$ be denote the normalised uniform measure on $mathbb{S}^{N-1}$, which is the $N-1$ dimensional sphere, where $N in mathbb{N}_{>0}$. How to prove that,
      for arbitrary non-negative integers, $n_1$, $ldots$, $n_N$, we have that
      $$
      int_{mathbb{S}^{N-1}} d varphi , , {big ( varphi^1 big )}^{2 n_1} ldots
      {big (varphi^N big )}^{2 n_N} =
      frac{ Gamma(N/2)}{2^n Gamma(n + N/2)} prod_{i=1}^{N} (2n_i - 1)!!,
      $$

      where $n= n_1 + ldots + n_N$ and we used the notation $varphi =( varphi^1, ldots, varphi^N) in mathbb{R}^N$.



      Here $Gamma(x)$ is the *Gamma function" and "!!" is the double factorial. These objects are defined here:
      https://en.wikipedia.org/wiki/Double_factorial;
      https://en.wikipedia.org/wiki/Gamma_function.







      real-analysis probability geometry measure-theory






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      edited Nov 20 '18 at 14:24

























      asked Nov 20 '18 at 13:47









      QuantumLogarithm

      533315




      533315






















          1 Answer
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          Clearly
          $$
          Icdotomega_{N-1}cdotint_0^infty r^{2n}expleft(-frac12r^2right),r^{N-1},mathrm{d}r=prod_{i=1}^Nint_{-infty}^infty x_i^{2n_i}expleft(-frac12x_i^2right),mathrm{d}x_i
          $$

          where $omega_{N-1}=dfrac{2pi^{N/2}}{Gamma(N/2)}$ is the volume of the standard $mathbb{S}^{N-1}$ and
          $$
          I:=-!!!!!!!int_{mathbb{S}^{N-1}} left(varphi^1right)^{2 n_1} dots
          left(varphi^Nright)^{2 n_N},mathrm{d}mathcal{H}^{N-1}.
          $$

          Now you can compute these integrals.






          share|cite|improve this answer























          • Thank you. What is $I$ in your text?
            – QuantumLogarithm
            Nov 20 '18 at 18:08










          • $I$ is your integral in the LHS
            – user10354138
            Nov 21 '18 at 1:06











          Your Answer





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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

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          1














          Clearly
          $$
          Icdotomega_{N-1}cdotint_0^infty r^{2n}expleft(-frac12r^2right),r^{N-1},mathrm{d}r=prod_{i=1}^Nint_{-infty}^infty x_i^{2n_i}expleft(-frac12x_i^2right),mathrm{d}x_i
          $$

          where $omega_{N-1}=dfrac{2pi^{N/2}}{Gamma(N/2)}$ is the volume of the standard $mathbb{S}^{N-1}$ and
          $$
          I:=-!!!!!!!int_{mathbb{S}^{N-1}} left(varphi^1right)^{2 n_1} dots
          left(varphi^Nright)^{2 n_N},mathrm{d}mathcal{H}^{N-1}.
          $$

          Now you can compute these integrals.






          share|cite|improve this answer























          • Thank you. What is $I$ in your text?
            – QuantumLogarithm
            Nov 20 '18 at 18:08










          • $I$ is your integral in the LHS
            – user10354138
            Nov 21 '18 at 1:06
















          1














          Clearly
          $$
          Icdotomega_{N-1}cdotint_0^infty r^{2n}expleft(-frac12r^2right),r^{N-1},mathrm{d}r=prod_{i=1}^Nint_{-infty}^infty x_i^{2n_i}expleft(-frac12x_i^2right),mathrm{d}x_i
          $$

          where $omega_{N-1}=dfrac{2pi^{N/2}}{Gamma(N/2)}$ is the volume of the standard $mathbb{S}^{N-1}$ and
          $$
          I:=-!!!!!!!int_{mathbb{S}^{N-1}} left(varphi^1right)^{2 n_1} dots
          left(varphi^Nright)^{2 n_N},mathrm{d}mathcal{H}^{N-1}.
          $$

          Now you can compute these integrals.






          share|cite|improve this answer























          • Thank you. What is $I$ in your text?
            – QuantumLogarithm
            Nov 20 '18 at 18:08










          • $I$ is your integral in the LHS
            – user10354138
            Nov 21 '18 at 1:06














          1












          1








          1






          Clearly
          $$
          Icdotomega_{N-1}cdotint_0^infty r^{2n}expleft(-frac12r^2right),r^{N-1},mathrm{d}r=prod_{i=1}^Nint_{-infty}^infty x_i^{2n_i}expleft(-frac12x_i^2right),mathrm{d}x_i
          $$

          where $omega_{N-1}=dfrac{2pi^{N/2}}{Gamma(N/2)}$ is the volume of the standard $mathbb{S}^{N-1}$ and
          $$
          I:=-!!!!!!!int_{mathbb{S}^{N-1}} left(varphi^1right)^{2 n_1} dots
          left(varphi^Nright)^{2 n_N},mathrm{d}mathcal{H}^{N-1}.
          $$

          Now you can compute these integrals.






          share|cite|improve this answer














          Clearly
          $$
          Icdotomega_{N-1}cdotint_0^infty r^{2n}expleft(-frac12r^2right),r^{N-1},mathrm{d}r=prod_{i=1}^Nint_{-infty}^infty x_i^{2n_i}expleft(-frac12x_i^2right),mathrm{d}x_i
          $$

          where $omega_{N-1}=dfrac{2pi^{N/2}}{Gamma(N/2)}$ is the volume of the standard $mathbb{S}^{N-1}$ and
          $$
          I:=-!!!!!!!int_{mathbb{S}^{N-1}} left(varphi^1right)^{2 n_1} dots
          left(varphi^Nright)^{2 n_N},mathrm{d}mathcal{H}^{N-1}.
          $$

          Now you can compute these integrals.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Nov 21 '18 at 1:05

























          answered Nov 20 '18 at 14:29









          user10354138

          7,4142824




          7,4142824












          • Thank you. What is $I$ in your text?
            – QuantumLogarithm
            Nov 20 '18 at 18:08










          • $I$ is your integral in the LHS
            – user10354138
            Nov 21 '18 at 1:06


















          • Thank you. What is $I$ in your text?
            – QuantumLogarithm
            Nov 20 '18 at 18:08










          • $I$ is your integral in the LHS
            – user10354138
            Nov 21 '18 at 1:06
















          Thank you. What is $I$ in your text?
          – QuantumLogarithm
          Nov 20 '18 at 18:08




          Thank you. What is $I$ in your text?
          – QuantumLogarithm
          Nov 20 '18 at 18:08












          $I$ is your integral in the LHS
          – user10354138
          Nov 21 '18 at 1:06




          $I$ is your integral in the LHS
          – user10354138
          Nov 21 '18 at 1:06


















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