Mixing
Probability of selecting more than x of a color given distribution?
1
$begingroup$
If you have 2000 candies distributed uniformly over 5 colors, what is the probability of getting more than 300 blue candies?
I was thinking of doing complementary counting, so
$$ 1-sum_{i=0}^{300} {2000choose{i}}left(frac 15right)^{i}left(frac45right)^{2000-i}$$
Would this be correct?
probability binomial-distribution
edited Jan 13 at 16:16
saulspatz
15.1k31331
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
$endgroup$
add a comment |
1
$begingroup$
If you have 2000 candies distributed uniformly over 5 colors, what is the probability of getting more than 300 blue candies?
I was thinking of doing complementary counting, so
$$ 1-sum_{i=0}^{300} {2000choose{i}}left(frac 15right)^{i}left(frac45right)^{2000-i}$$
Would this be correct?
probability binomial-distribution
edited Jan 13 at 16:16
saulspatz
15.1k31331
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
$endgroup$
$begingroup$
What you've written is certainly correct, but I wonder if it's the answer your instructor is looking for. Have you been studying anything about approximating probabilities? The central limit theorem, for instance?
$endgroup$
– saulspatz
Jan 13 at 16:20
$begingroup$
@saulspatz Yes, I felt like this answer was correct but perhaps not what the question is going for. What would be a way to approximate this using CLT?
$endgroup$
– javafrapp90
Jan 13 at 18:42
$begingroup$
newonlinecourses.science.psu.edu/stat414/node/179
$endgroup$
– saulspatz
Jan 13 at 22:12
add a comment |
1
1
1
$begingroup$
If you have 2000 candies distributed uniformly over 5 colors, what is the probability of getting more than 300 blue candies?
I was thinking of doing complementary counting, so
$$ 1-sum_{i=0}^{300} {2000choose{i}}left(frac 15right)^{i}left(frac45right)^{2000-i}$$
Would this be correct?
probability binomial-distribution
edited Jan 13 at 16:16
saulspatz
15.1k31331
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
$endgroup$
If you have 2000 candies distributed uniformly over 5 colors, what is the probability of getting more than 300 blue candies?
I was thinking of doing complementary counting, so
$$ 1-sum_{i=0}^{300} {2000choose{i}}left(frac 15right)^{i}left(frac45right)^{2000-i}$$
Would this be correct?
probability binomial-distribution
probability binomial-distribution
edited Jan 13 at 16:16
saulspatz
15.1k31331
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
edited Jan 13 at 16:16
saulspatz
15.1k31331
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
edited Jan 13 at 16:16
saulspatz
15.1k31331
edited Jan 13 at 16:16
saulspatz
15.1k31331
edited Jan 13 at 16:16
saulspatz
15.1k31331
15.1k31331
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
asked Jan 13 at 16:06
javafrapp90javafrapp90
61
61
$begingroup$
What you've written is certainly correct, but I wonder if it's the answer your instructor is looking for. Have you been studying anything about approximating probabilities? The central limit theorem, for instance?
$endgroup$
– saulspatz
Jan 13 at 16:20
$begingroup$
@saulspatz Yes, I felt like this answer was correct but perhaps not what the question is going for. What would be a way to approximate this using CLT?
$endgroup$
– javafrapp90
Jan 13 at 18:42
$begingroup$
newonlinecourses.science.psu.edu/stat414/node/179
$endgroup$
– saulspatz
Jan 13 at 22:12
add a comment |
$begingroup$
What you've written is certainly correct, but I wonder if it's the answer your instructor is looking for. Have you been studying anything about approximating probabilities? The central limit theorem, for instance?
$endgroup$
– saulspatz
Jan 13 at 16:20
$begingroup$
@saulspatz Yes, I felt like this answer was correct but perhaps not what the question is going for. What would be a way to approximate this using CLT?
$endgroup$
– javafrapp90
Jan 13 at 18:42
$begingroup$
newonlinecourses.science.psu.edu/stat414/node/179
$endgroup$
– saulspatz
Jan 13 at 22:12
$begingroup$
What you've written is certainly correct, but I wonder if it's the answer your instructor is looking for. Have you been studying anything about approximating probabilities? The central limit theorem, for instance?
$endgroup$
– saulspatz
Jan 13 at 16:20
$begingroup$
What you've written is certainly correct, but I wonder if it's the answer your instructor is looking for. Have you been studying anything about approximating probabilities? The central limit theorem, for instance?
$endgroup$
– saulspatz
Jan 13 at 16:20
$begingroup$
@saulspatz Yes, I felt like this answer was correct but perhaps not what the question is going for. What would be a way to approximate this using CLT?
$endgroup$
– javafrapp90
Jan 13 at 18:42
$begingroup$
@saulspatz Yes, I felt like this answer was correct but perhaps not what the question is going for. What would be a way to approximate this using CLT?
$endgroup$
– javafrapp90
Jan 13 at 18:42
$begingroup$
newonlinecourses.science.psu.edu/stat414/node/179
$endgroup$
– saulspatz
Jan 13 at 22:12
$begingroup$
newonlinecourses.science.psu.edu/stat414/node/179
$endgroup$
– saulspatz
Jan 13 at 22:12
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3072155%2fprobability-of-selecting-more-than-x-of-a-color-given-distribution%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
draft saved
draft discarded
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3072155%2fprobability-of-selecting-more-than-x-of-a-color-given-distribution%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
What you've written is certainly correct, but I wonder if it's the answer your instructor is looking for. Have you been studying anything about approximating probabilities? The central limit theorem, for instance?
$endgroup$
– saulspatz
Jan 13 at 16:20
$begingroup$
@saulspatz Yes, I felt like this answer was correct but perhaps not what the question is going for. What would be a way to approximate this using CLT?
$endgroup$
– javafrapp90
Jan 13 at 18:42
$begingroup$
newonlinecourses.science.psu.edu/stat414/node/179
$endgroup$
– saulspatz
Jan 13 at 22:12