Ricci Tensor and Einstein Manifolds
$begingroup$
What can we say about an hypersurface Einstein manifolds on $mathbb{R}^{n+1}$ when $ngeq 3$ ?
The manifolds is Einstein so Ricci tensor is a multiply of the metric $g$ on manifold:
$Ric=lambda g$ where $lambdain C^infty(M)$
If $S$ is the scalar curvature of $M$ then the relationship between $S$ and $lambda$ is
$lambda=frac{S}{n}$
Because the scalar curvature of $M$ is the trace of Ricci tensor.
So using the condition that $ngeq 3$ and using a contraction of the second Bianchi Identity we have that the scalar curvature of $M$ is costant so $lambda$ is costant.
Another condition that we have is that $M$ is an hypersurface of $mathbb{R}^{n+1}$ so we can use also the Codazzi-Mainardi Equation ti get some equation between the mean curvature $H$ of $M$, the metric $g$ and the second fondamental formula of $M$.
What can other we say about $M$, it is possible classify it?
general-topology geometry analysis riemannian-geometry riemann-surfaces
$endgroup$
add a comment |
$begingroup$
What can we say about an hypersurface Einstein manifolds on $mathbb{R}^{n+1}$ when $ngeq 3$ ?
The manifolds is Einstein so Ricci tensor is a multiply of the metric $g$ on manifold:
$Ric=lambda g$ where $lambdain C^infty(M)$
If $S$ is the scalar curvature of $M$ then the relationship between $S$ and $lambda$ is
$lambda=frac{S}{n}$
Because the scalar curvature of $M$ is the trace of Ricci tensor.
So using the condition that $ngeq 3$ and using a contraction of the second Bianchi Identity we have that the scalar curvature of $M$ is costant so $lambda$ is costant.
Another condition that we have is that $M$ is an hypersurface of $mathbb{R}^{n+1}$ so we can use also the Codazzi-Mainardi Equation ti get some equation between the mean curvature $H$ of $M$, the metric $g$ and the second fondamental formula of $M$.
What can other we say about $M$, it is possible classify it?
general-topology geometry analysis riemannian-geometry riemann-surfaces
$endgroup$
$begingroup$
Take a look here: researchgate.net/profile/Bang_Yen_Chen/publication/…
$endgroup$
– Moishe Cohen
Jan 13 at 18:06
$begingroup$
What I must search in this book? There are a lot of sections
$endgroup$
– Federico Fallucca
Jan 13 at 18:34
add a comment |
$begingroup$
What can we say about an hypersurface Einstein manifolds on $mathbb{R}^{n+1}$ when $ngeq 3$ ?
The manifolds is Einstein so Ricci tensor is a multiply of the metric $g$ on manifold:
$Ric=lambda g$ where $lambdain C^infty(M)$
If $S$ is the scalar curvature of $M$ then the relationship between $S$ and $lambda$ is
$lambda=frac{S}{n}$
Because the scalar curvature of $M$ is the trace of Ricci tensor.
So using the condition that $ngeq 3$ and using a contraction of the second Bianchi Identity we have that the scalar curvature of $M$ is costant so $lambda$ is costant.
Another condition that we have is that $M$ is an hypersurface of $mathbb{R}^{n+1}$ so we can use also the Codazzi-Mainardi Equation ti get some equation between the mean curvature $H$ of $M$, the metric $g$ and the second fondamental formula of $M$.
What can other we say about $M$, it is possible classify it?
general-topology geometry analysis riemannian-geometry riemann-surfaces
$endgroup$
What can we say about an hypersurface Einstein manifolds on $mathbb{R}^{n+1}$ when $ngeq 3$ ?
The manifolds is Einstein so Ricci tensor is a multiply of the metric $g$ on manifold:
$Ric=lambda g$ where $lambdain C^infty(M)$
If $S$ is the scalar curvature of $M$ then the relationship between $S$ and $lambda$ is
$lambda=frac{S}{n}$
Because the scalar curvature of $M$ is the trace of Ricci tensor.
So using the condition that $ngeq 3$ and using a contraction of the second Bianchi Identity we have that the scalar curvature of $M$ is costant so $lambda$ is costant.
Another condition that we have is that $M$ is an hypersurface of $mathbb{R}^{n+1}$ so we can use also the Codazzi-Mainardi Equation ti get some equation between the mean curvature $H$ of $M$, the metric $g$ and the second fondamental formula of $M$.
What can other we say about $M$, it is possible classify it?
general-topology geometry analysis riemannian-geometry riemann-surfaces
general-topology geometry analysis riemannian-geometry riemann-surfaces
asked Jan 13 at 15:33
Federico FalluccaFederico Fallucca
1,959110
1,959110
$begingroup$
Take a look here: researchgate.net/profile/Bang_Yen_Chen/publication/…
$endgroup$
– Moishe Cohen
Jan 13 at 18:06
$begingroup$
What I must search in this book? There are a lot of sections
$endgroup$
– Federico Fallucca
Jan 13 at 18:34
add a comment |
$begingroup$
Take a look here: researchgate.net/profile/Bang_Yen_Chen/publication/…
$endgroup$
– Moishe Cohen
Jan 13 at 18:06
$begingroup$
What I must search in this book? There are a lot of sections
$endgroup$
– Federico Fallucca
Jan 13 at 18:34
$begingroup$
Take a look here: researchgate.net/profile/Bang_Yen_Chen/publication/…
$endgroup$
– Moishe Cohen
Jan 13 at 18:06
$begingroup$
Take a look here: researchgate.net/profile/Bang_Yen_Chen/publication/…
$endgroup$
– Moishe Cohen
Jan 13 at 18:06
$begingroup$
What I must search in this book? There are a lot of sections
$endgroup$
– Federico Fallucca
Jan 13 at 18:34
$begingroup$
What I must search in this book? There are a lot of sections
$endgroup$
– Federico Fallucca
Jan 13 at 18:34
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3072116%2fricci-tensor-and-einstein-manifolds%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3072116%2fricci-tensor-and-einstein-manifolds%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Take a look here: researchgate.net/profile/Bang_Yen_Chen/publication/…
$endgroup$
– Moishe Cohen
Jan 13 at 18:06
$begingroup$
What I must search in this book? There are a lot of sections
$endgroup$
– Federico Fallucca
Jan 13 at 18:34