Mixing
Area of a right trapezoid with bases $15$ and $8$, and height $9$
$begingroup$
I can't figure out how they got that.
I got 1080, they got 103.5.
How???
education area
edited Jan 22 at 19:04
Blue
49k870156
asked Jan 22 at 18:48
DuelDuel
153
$endgroup$
|
show 8 more comments
$begingroup$
I can't figure out how they got that.
I got 1080, they got 103.5.
How???
education area
edited Jan 22 at 19:04
Blue
49k870156
asked Jan 22 at 18:48
DuelDuel
153
$endgroup$
$begingroup$
How did you find $1080$ ?
$endgroup$
– Yves Daoust
Jan 22 at 18:50
$begingroup$
I multiplied 15 by 9, then that by 8
$endgroup$
– Duel
Jan 22 at 18:51
$begingroup$
What is the rationale behind multiplying these three numbers ??
$endgroup$
– Yves Daoust
Jan 22 at 18:52
$begingroup$
I got 103.5 too. How on earth did you get 1080? (You can put it inside a $9times 15$ rectangle, so it must be less than 135)
$endgroup$
– Lord Shark the Unknown
Jan 22 at 18:52
1
$begingroup$
Just as a sanity check, it should be obvious that the shape fits inside a $9times 15$ rectangle, so the area cannot be more than $9times 15 mathrm m^2.$
$endgroup$
– David K
Jan 22 at 18:54
|
show 8 more comments
$begingroup$
I can't figure out how they got that.
I got 1080, they got 103.5.
How???
education area
edited Jan 22 at 19:04
Blue
49k870156
asked Jan 22 at 18:48
DuelDuel
153
$endgroup$
I can't figure out how they got that.
I got 1080, they got 103.5.
How???
education area
education area
edited Jan 22 at 19:04
Blue
49k870156
asked Jan 22 at 18:48
DuelDuel
153
edited Jan 22 at 19:04
Blue
49k870156
asked Jan 22 at 18:48
DuelDuel
153
edited Jan 22 at 19:04
Blue
49k870156
edited Jan 22 at 19:04
Blue
49k870156
edited Jan 22 at 19:04
Blue
49k870156
49k870156
asked Jan 22 at 18:48
DuelDuel
153
asked Jan 22 at 18:48
DuelDuel
153
asked Jan 22 at 18:48
DuelDuel
153
153
$begingroup$
How did you find $1080$ ?
$endgroup$
– Yves Daoust
Jan 22 at 18:50
$begingroup$
I multiplied 15 by 9, then that by 8
$endgroup$
– Duel
Jan 22 at 18:51
$begingroup$
What is the rationale behind multiplying these three numbers ??
$endgroup$
– Yves Daoust
Jan 22 at 18:52
$begingroup$
I got 103.5 too. How on earth did you get 1080? (You can put it inside a $9times 15$ rectangle, so it must be less than 135)
$endgroup$
– Lord Shark the Unknown
Jan 22 at 18:52
1
$begingroup$
Just as a sanity check, it should be obvious that the shape fits inside a $9times 15$ rectangle, so the area cannot be more than $9times 15 mathrm m^2.$
$endgroup$
– David K
Jan 22 at 18:54
|
show 8 more comments
$begingroup$
How did you find $1080$ ?
$endgroup$
– Yves Daoust
Jan 22 at 18:50
$begingroup$
I multiplied 15 by 9, then that by 8
$endgroup$
– Duel
Jan 22 at 18:51
$begingroup$
What is the rationale behind multiplying these three numbers ??
$endgroup$
– Yves Daoust
Jan 22 at 18:52
$begingroup$
I got 103.5 too. How on earth did you get 1080? (You can put it inside a $9times 15$ rectangle, so it must be less than 135)
$endgroup$
– Lord Shark the Unknown
Jan 22 at 18:52
1
$begingroup$
Just as a sanity check, it should be obvious that the shape fits inside a $9times 15$ rectangle, so the area cannot be more than $9times 15 mathrm m^2.$
$endgroup$
– David K
Jan 22 at 18:54
$begingroup$
How did you find $1080$ ?
$endgroup$
– Yves Daoust
Jan 22 at 18:50
$begingroup$
How did you find $1080$ ?
$endgroup$
– Yves Daoust
Jan 22 at 18:50
$begingroup$
I multiplied 15 by 9, then that by 8
$endgroup$
– Duel
Jan 22 at 18:51
$begingroup$
I multiplied 15 by 9, then that by 8
$endgroup$
– Duel
Jan 22 at 18:51
$begingroup$
What is the rationale behind multiplying these three numbers ??
$endgroup$
– Yves Daoust
Jan 22 at 18:52
$begingroup$
What is the rationale behind multiplying these three numbers ??
$endgroup$
– Yves Daoust
Jan 22 at 18:52
$begingroup$
I got 103.5 too. How on earth did you get 1080? (You can put it inside a $9times 15$ rectangle, so it must be less than 135)
$endgroup$
– Lord Shark the Unknown
Jan 22 at 18:52
$begingroup$
I got 103.5 too. How on earth did you get 1080? (You can put it inside a $9times 15$ rectangle, so it must be less than 135)
$endgroup$
– Lord Shark the Unknown
Jan 22 at 18:52
1
1
$begingroup$
Just as a sanity check, it should be obvious that the shape fits inside a $9times 15$ rectangle, so the area cannot be more than $9times 15 mathrm m^2.$
$endgroup$
– David K
Jan 22 at 18:54
$begingroup$
Just as a sanity check, it should be obvious that the shape fits inside a $9times 15$ rectangle, so the area cannot be more than $9times 15 mathrm m^2.$
$endgroup$
– David K
Jan 22 at 18:54
|
show 8 more comments
3 Answers
3
active
oldest
votes
$begingroup$
Hint : area of Trapezoid is calculated by
$$ frac{base_a + base_b}{2} cdot height $$
answered Jan 22 at 18:55
kelalakakelalaka
3351314
$endgroup$
add a comment |
$begingroup$
As has been explained in comments, your formula doesn't work. Instead, split it up into two shapes. You have two shapes, a $7times 9$ right-angled triangle, and an $8times 9$ rectangle. Calculate their areas and the area of the trapezium is their sum.
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
$endgroup$
add a comment |
$begingroup$
Hint
Divide it into these polygons and determinate the areas separately. You might need to use the Pythagorean theorem.
If not, you might want to use the formula for the area of trapezoides:
$$text{Area}=frac{text{base1}+text{base2}}{2}·text{height}$$
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint : area of Trapezoid is calculated by
$$ frac{base_a + base_b}{2} cdot height $$
answered Jan 22 at 18:55
kelalakakelalaka
3351314
$endgroup$
add a comment |
$begingroup$
Hint : area of Trapezoid is calculated by
$$ frac{base_a + base_b}{2} cdot height $$
answered Jan 22 at 18:55
kelalakakelalaka
3351314
$endgroup$
add a comment |
$begingroup$
Hint : area of Trapezoid is calculated by
$$ frac{base_a + base_b}{2} cdot height $$
answered Jan 22 at 18:55
kelalakakelalaka
3351314
$endgroup$
Hint : area of Trapezoid is calculated by
$$ frac{base_a + base_b}{2} cdot height $$
answered Jan 22 at 18:55
kelalakakelalaka
3351314
answered Jan 22 at 18:55
kelalakakelalaka
3351314
answered Jan 22 at 18:55
kelalakakelalaka
3351314
answered Jan 22 at 18:55
kelalakakelalaka
3351314
3351314
add a comment |
add a comment |
$begingroup$
As has been explained in comments, your formula doesn't work. Instead, split it up into two shapes. You have two shapes, a $7times 9$ right-angled triangle, and an $8times 9$ rectangle. Calculate their areas and the area of the trapezium is their sum.
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
$endgroup$
add a comment |
$begingroup$
As has been explained in comments, your formula doesn't work. Instead, split it up into two shapes. You have two shapes, a $7times 9$ right-angled triangle, and an $8times 9$ rectangle. Calculate their areas and the area of the trapezium is their sum.
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
$endgroup$
add a comment |
$begingroup$
As has been explained in comments, your formula doesn't work. Instead, split it up into two shapes. You have two shapes, a $7times 9$ right-angled triangle, and an $8times 9$ rectangle. Calculate their areas and the area of the trapezium is their sum.
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
$endgroup$
As has been explained in comments, your formula doesn't work. Instead, split it up into two shapes. You have two shapes, a $7times 9$ right-angled triangle, and an $8times 9$ rectangle. Calculate their areas and the area of the trapezium is their sum.
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
answered Jan 22 at 18:56
Rhys HughesRhys Hughes
6,9691530
6,9691530
add a comment |
add a comment |
$begingroup$
Hint
Divide it into these polygons and determinate the areas separately. You might need to use the Pythagorean theorem.
If not, you might want to use the formula for the area of trapezoides:
$$text{Area}=frac{text{base1}+text{base2}}{2}·text{height}$$
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
$endgroup$
add a comment |
$begingroup$
Hint
Divide it into these polygons and determinate the areas separately. You might need to use the Pythagorean theorem.
If not, you might want to use the formula for the area of trapezoides:
$$text{Area}=frac{text{base1}+text{base2}}{2}·text{height}$$
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
$endgroup$
add a comment |
$begingroup$
Hint
Divide it into these polygons and determinate the areas separately. You might need to use the Pythagorean theorem.
If not, you might want to use the formula for the area of trapezoides:
$$text{Area}=frac{text{base1}+text{base2}}{2}·text{height}$$
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
$endgroup$
Hint
Divide it into these polygons and determinate the areas separately. You might need to use the Pythagorean theorem.
If not, you might want to use the formula for the area of trapezoides:
$$text{Area}=frac{text{base1}+text{base2}}{2}·text{height}$$
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
answered Jan 22 at 18:57
Dr. MathvaDr. Mathva
2,241526
2,241526
add a comment |
add a comment |
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$begingroup$
How did you find $1080$ ?
$endgroup$
– Yves Daoust
Jan 22 at 18:50
$begingroup$
I multiplied 15 by 9, then that by 8
$endgroup$
– Duel
Jan 22 at 18:51
$begingroup$
What is the rationale behind multiplying these three numbers ??
$endgroup$
– Yves Daoust
Jan 22 at 18:52
$begingroup$
I got 103.5 too. How on earth did you get 1080? (You can put it inside a $9times 15$ rectangle, so it must be less than 135)
$endgroup$
– Lord Shark the Unknown
Jan 22 at 18:52
1
$begingroup$
Just as a sanity check, it should be obvious that the shape fits inside a $9times 15$ rectangle, so the area cannot be more than $9times 15 mathrm m^2.$
$endgroup$
– David K
Jan 22 at 18:54