Compute the probability that the maximum of the bootstrap dataset equals 1.56.
$begingroup$
We generate a bootstrap dataset $x^*_1, . . . ,x^*_{10}$ from the empirical distribution function $F_n$ obtained from the dataset
$$1.34,1.24,1.56,1.37,1.41$$
$$1.37,1.31,1.33,1.32,1.34$$
Compute the probability that the maximum of the bootstrap dataset equals 1.56.
Solve:
A bootstrap dataset can be seen as a realization of drawing 10 times with replacement from the original dataset.
$M^∗ = max X^∗_1 , . . . ,X^∗_{10}$ and $P(M^∗ = 1.56) = 1 − P(M^∗ neq 1.56)$, but how can I calculate $P(M^∗ neq 1.56)$?
probability
$endgroup$
add a comment |
$begingroup$
We generate a bootstrap dataset $x^*_1, . . . ,x^*_{10}$ from the empirical distribution function $F_n$ obtained from the dataset
$$1.34,1.24,1.56,1.37,1.41$$
$$1.37,1.31,1.33,1.32,1.34$$
Compute the probability that the maximum of the bootstrap dataset equals 1.56.
Solve:
A bootstrap dataset can be seen as a realization of drawing 10 times with replacement from the original dataset.
$M^∗ = max X^∗_1 , . . . ,X^∗_{10}$ and $P(M^∗ = 1.56) = 1 − P(M^∗ neq 1.56)$, but how can I calculate $P(M^∗ neq 1.56)$?
probability
$endgroup$
add a comment |
$begingroup$
We generate a bootstrap dataset $x^*_1, . . . ,x^*_{10}$ from the empirical distribution function $F_n$ obtained from the dataset
$$1.34,1.24,1.56,1.37,1.41$$
$$1.37,1.31,1.33,1.32,1.34$$
Compute the probability that the maximum of the bootstrap dataset equals 1.56.
Solve:
A bootstrap dataset can be seen as a realization of drawing 10 times with replacement from the original dataset.
$M^∗ = max X^∗_1 , . . . ,X^∗_{10}$ and $P(M^∗ = 1.56) = 1 − P(M^∗ neq 1.56)$, but how can I calculate $P(M^∗ neq 1.56)$?
probability
$endgroup$
We generate a bootstrap dataset $x^*_1, . . . ,x^*_{10}$ from the empirical distribution function $F_n$ obtained from the dataset
$$1.34,1.24,1.56,1.37,1.41$$
$$1.37,1.31,1.33,1.32,1.34$$
Compute the probability that the maximum of the bootstrap dataset equals 1.56.
Solve:
A bootstrap dataset can be seen as a realization of drawing 10 times with replacement from the original dataset.
$M^∗ = max X^∗_1 , . . . ,X^∗_{10}$ and $P(M^∗ = 1.56) = 1 − P(M^∗ neq 1.56)$, but how can I calculate $P(M^∗ neq 1.56)$?
probability
probability
asked Jan 24 at 12:12
FTACFTAC
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