Mixing
Select by Attributes With OR Operator
I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.
Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.
"H1" = '31p' OR '34n' OR '61f' OR '31q'
"H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'
None of them work. Should I use "IS" logical operator instead of "="?
qgis
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
asked Jan 24 at 10:59
dmasanadmasana
334
add a comment |
I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.
Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.
"H1" = '31p' OR '34n' OR '61f' OR '31q'
"H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'
None of them work. Should I use "IS" logical operator instead of "="?
qgis
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
asked Jan 24 at 10:59
dmasanadmasana
334
add a comment |
I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.
Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.
"H1" = '31p' OR '34n' OR '61f' OR '31q'
"H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'
None of them work. Should I use "IS" logical operator instead of "="?
qgis
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
asked Jan 24 at 10:59
dmasanadmasana
334
I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.
Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.
"H1" = '31p' OR '34n' OR '61f' OR '31q'
"H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'
None of them work. Should I use "IS" logical operator instead of "="?
qgis
qgis
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
asked Jan 24 at 10:59
dmasanadmasana
334
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
asked Jan 24 at 10:59
dmasanadmasana
334
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
edited Jan 24 at 20:13
PolyGeo♦
53.7k1781244
53.7k1781244
asked Jan 24 at 10:59
dmasanadmasana
334
asked Jan 24 at 10:59
dmasanadmasana
334
asked Jan 24 at 10:59
dmasanadmasana
334
334
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You should repeat the column name for each value in the query
"H1" = '31p' or "H1" = '34n' ...
You had better to use "in" operator like
"H1" in ('31p', '34n', '31q', '61f')
edited Jan 24 at 11:40
BERA
16.5k52043
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should repeat the column name for each value in the query
"H1" = '31p' or "H1" = '34n' ...
You had better to use "in" operator like
"H1" in ('31p', '34n', '31q', '61f')
edited Jan 24 at 11:40
BERA
16.5k52043
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
add a comment |
You should repeat the column name for each value in the query
"H1" = '31p' or "H1" = '34n' ...
You had better to use "in" operator like
"H1" in ('31p', '34n', '31q', '61f')
edited Jan 24 at 11:40
BERA
16.5k52043
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
add a comment |
You should repeat the column name for each value in the query
"H1" = '31p' or "H1" = '34n' ...
You had better to use "in" operator like
"H1" in ('31p', '34n', '31q', '61f')
edited Jan 24 at 11:40
BERA
16.5k52043
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
You should repeat the column name for each value in the query
"H1" = '31p' or "H1" = '34n' ...
You had better to use "in" operator like
"H1" in ('31p', '34n', '31q', '61f')
edited Jan 24 at 11:40
BERA
16.5k52043
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
edited Jan 24 at 11:40
BERA
16.5k52043
edited Jan 24 at 11:40
BERA
16.5k52043
edited Jan 24 at 11:40
BERA
16.5k52043
16.5k52043
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
answered Jan 24 at 11:09
ZoltanZoltan
3,319917
3,319917
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
add a comment |
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks
– dmasana
Jan 24 at 13:17
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.
– Zoltan
Jan 24 at 15:54
add a comment |
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