Mixing
Exit Jupyter Notebook .ipynb cell based on a condition
1
from sys import exit
import sys
i=0
while i < 10:
print(i)
i=i+1
if i==5:
exit(0)
print(' i do not want to print this')
Based on the above code snippet , I am looking to exit Jupyter Notebook cell.
Error I am getting is :
/usr/local/lib/python3.6/site-packages/IPython/core/interactiveshell.py:3275: UserWarning: To exit: use 'exit', 'quit', or Ctrl-D.
warn("To exit: use 'exit', 'quit', or Ctrl-D.", stacklevel=1)
I tried
sys.exit(0)
but still not able to exit the execution gracefully
An exception has occurred, use %tb to see the full traceback.
SystemExit: 0
python jupyter-notebook ipython
asked Jan 2 at 16:44
K.PilK.Pil
102111
add a comment |
1
from sys import exit
import sys
i=0
while i < 10:
print(i)
i=i+1
if i==5:
exit(0)
print(' i do not want to print this')
Based on the above code snippet , I am looking to exit Jupyter Notebook cell.
Error I am getting is :
/usr/local/lib/python3.6/site-packages/IPython/core/interactiveshell.py:3275: UserWarning: To exit: use 'exit', 'quit', or Ctrl-D.
warn("To exit: use 'exit', 'quit', or Ctrl-D.", stacklevel=1)
I tried
sys.exit(0)
but still not able to exit the execution gracefully
An exception has occurred, use %tb to see the full traceback.
SystemExit: 0
python jupyter-notebook ipython
asked Jan 2 at 16:44
K.PilK.Pil
102111
usequit()-The kernel appears to have died. It will restart automatically.
– Rohit-Pandey
Jan 2 at 16:49
1
Why would you want to do so?exit()normally would kill the kernel, not just the cell. If you simply want to bypass some piece of code, you can put it under a boolean flag. Something like:for i in range(10): i+=1, if i==5: flag= Trueand then outside offorloop:if not flag: print('this will be printed')?
– Quang Hoang
Jan 2 at 16:52
Introducing a flag variable is a good idea , I was trying to replicate the problem with a simple code snippet. As same code works in databricks
– K.Pil
Jan 2 at 23:13
add a comment |
1
1
1
1
from sys import exit
import sys
i=0
while i < 10:
print(i)
i=i+1
if i==5:
exit(0)
print(' i do not want to print this')
Based on the above code snippet , I am looking to exit Jupyter Notebook cell.
Error I am getting is :
/usr/local/lib/python3.6/site-packages/IPython/core/interactiveshell.py:3275: UserWarning: To exit: use 'exit', 'quit', or Ctrl-D.
warn("To exit: use 'exit', 'quit', or Ctrl-D.", stacklevel=1)
I tried
sys.exit(0)
but still not able to exit the execution gracefully
An exception has occurred, use %tb to see the full traceback.
SystemExit: 0
python jupyter-notebook ipython
asked Jan 2 at 16:44
K.PilK.Pil
102111
from sys import exit
import sys
i=0
while i < 10:
print(i)
i=i+1
if i==5:
exit(0)
print(' i do not want to print this')
Based on the above code snippet , I am looking to exit Jupyter Notebook cell.
Error I am getting is :
/usr/local/lib/python3.6/site-packages/IPython/core/interactiveshell.py:3275: UserWarning: To exit: use 'exit', 'quit', or Ctrl-D.
warn("To exit: use 'exit', 'quit', or Ctrl-D.", stacklevel=1)
I tried
sys.exit(0)
but still not able to exit the execution gracefully
An exception has occurred, use %tb to see the full traceback.
SystemExit: 0
python jupyter-notebook ipython
python jupyter-notebook ipython
asked Jan 2 at 16:44
K.PilK.Pil
102111
asked Jan 2 at 16:44
K.PilK.Pil
102111
asked Jan 2 at 16:44
K.PilK.Pil
102111
asked Jan 2 at 16:44
K.PilK.Pil
102111
asked Jan 2 at 16:44
K.PilK.Pil
102111
102111
usequit()-The kernel appears to have died. It will restart automatically.
– Rohit-Pandey
Jan 2 at 16:49
1
Why would you want to do so?exit()normally would kill the kernel, not just the cell. If you simply want to bypass some piece of code, you can put it under a boolean flag. Something like:for i in range(10): i+=1, if i==5: flag= Trueand then outside offorloop:if not flag: print('this will be printed')?
– Quang Hoang
Jan 2 at 16:52
Introducing a flag variable is a good idea , I was trying to replicate the problem with a simple code snippet. As same code works in databricks
– K.Pil
Jan 2 at 23:13
add a comment |
usequit()-The kernel appears to have died. It will restart automatically.
– Rohit-Pandey
Jan 2 at 16:49
1
Why would you want to do so?exit()normally would kill the kernel, not just the cell. If you simply want to bypass some piece of code, you can put it under a boolean flag. Something like:for i in range(10): i+=1, if i==5: flag= Trueand then outside offorloop:if not flag: print('this will be printed')?
– Quang Hoang
Jan 2 at 16:52
Introducing a flag variable is a good idea , I was trying to replicate the problem with a simple code snippet. As same code works in databricks
– K.Pil
Jan 2 at 23:13
use
quit() - The kernel appears to have died. It will restart automatically.– Rohit-Pandey
Jan 2 at 16:49
use
quit() - The kernel appears to have died. It will restart automatically.– Rohit-Pandey
Jan 2 at 16:49
1
1
Why would you want to do so?
exit() normally would kill the kernel, not just the cell. If you simply want to bypass some piece of code, you can put it under a boolean flag. Something like: for i in range(10): i+=1, if i==5: flag= True and then outside of for loop: if not flag: print('this will be printed')?– Quang Hoang
Jan 2 at 16:52
Why would you want to do so?
exit() normally would kill the kernel, not just the cell. If you simply want to bypass some piece of code, you can put it under a boolean flag. Something like: for i in range(10): i+=1, if i==5: flag= True and then outside of for loop: if not flag: print('this will be printed')?– Quang Hoang
Jan 2 at 16:52
Introducing a flag variable is a good idea , I was trying to replicate the problem with a simple code snippet. As same code works in databricks
– K.Pil
Jan 2 at 23:13
Introducing a flag variable is a good idea , I was trying to replicate the problem with a simple code snippet. As same code works in databricks
– K.Pil
Jan 2 at 23:13
add a comment |
0
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use
quit()-The kernel appears to have died. It will restart automatically.– Rohit-Pandey
Jan 2 at 16:49
1
Why would you want to do so?
exit()normally would kill the kernel, not just the cell. If you simply want to bypass some piece of code, you can put it under a boolean flag. Something like:for i in range(10): i+=1, if i==5: flag= Trueand then outside offorloop:if not flag: print('this will be printed')?– Quang Hoang
Jan 2 at 16:52
Introducing a flag variable is a good idea , I was trying to replicate the problem with a simple code snippet. As same code works in databricks
– K.Pil
Jan 2 at 23:13