Mixing
Filter EntityCollection based on a single attribute using LINQ:
I have an entitycollection composed from a fetchXML query.
string fetch = @"
<fetch version='1.0' output-format='xml-platform' mapping='logical' distinct='false'>
<entity name='new_rl'>
<attribute name='new_rlsid' />
<attribute name='new_productid' />
<attribute name='new_subquantity' />
<filter type='and'>
<condition attribute='new_sg' operator='eq' value='" + servingGroup.Value.ToString() + @"' />
<condition attribute='new_s' operator='eq' value='' />
<condition attribute='new_ld' operator='eq' value='" + location + @"' />
<condition attribute='new_productid' operator='not-null' />
</filter>
<link-entity name='new_ys' from='new_ysid' to='new_orderid' link-type='inner' alias='ae'>
<filter type='and'>
<condition attribute='new_ysid' operator='eq' value='{" + yGuid.ToString() + @"}' />
</filter>
</link-entity>
</entity>
</fetch>";
EntityCollection Labels = service.RetrieveMultiple(new FetchExpression(fetch));
I need to filter the above entitycollection based on the 'new_productid' attribute. If two entities have the same value for 'new_productid', then I only want one of those entities to be rendered into a new filtered entity collection. I would need new_productid and new_subquantity and new_rlsid to be in my new entitycollection.
I noticed that LINQ has the .Distinct() property, but all the msdn examples for CRM show how to do this with LINQ using early binding. All of my plugins are late bound and need a Linq solution for late binding.
c# linq dynamics-crm dynamics-crm-online dynamics-365
edited Jan 2 at 21:39
Hogan
55.6k967103
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
add a comment |
I have an entitycollection composed from a fetchXML query.
string fetch = @"
<fetch version='1.0' output-format='xml-platform' mapping='logical' distinct='false'>
<entity name='new_rl'>
<attribute name='new_rlsid' />
<attribute name='new_productid' />
<attribute name='new_subquantity' />
<filter type='and'>
<condition attribute='new_sg' operator='eq' value='" + servingGroup.Value.ToString() + @"' />
<condition attribute='new_s' operator='eq' value='' />
<condition attribute='new_ld' operator='eq' value='" + location + @"' />
<condition attribute='new_productid' operator='not-null' />
</filter>
<link-entity name='new_ys' from='new_ysid' to='new_orderid' link-type='inner' alias='ae'>
<filter type='and'>
<condition attribute='new_ysid' operator='eq' value='{" + yGuid.ToString() + @"}' />
</filter>
</link-entity>
</entity>
</fetch>";
EntityCollection Labels = service.RetrieveMultiple(new FetchExpression(fetch));
I need to filter the above entitycollection based on the 'new_productid' attribute. If two entities have the same value for 'new_productid', then I only want one of those entities to be rendered into a new filtered entity collection. I would need new_productid and new_subquantity and new_rlsid to be in my new entitycollection.
I noticed that LINQ has the .Distinct() property, but all the msdn examples for CRM show how to do this with LINQ using early binding. All of my plugins are late bound and need a Linq solution for late binding.
c# linq dynamics-crm dynamics-crm-online dynamics-365
edited Jan 2 at 21:39
Hogan
55.6k967103
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
add a comment |
I have an entitycollection composed from a fetchXML query.
string fetch = @"
<fetch version='1.0' output-format='xml-platform' mapping='logical' distinct='false'>
<entity name='new_rl'>
<attribute name='new_rlsid' />
<attribute name='new_productid' />
<attribute name='new_subquantity' />
<filter type='and'>
<condition attribute='new_sg' operator='eq' value='" + servingGroup.Value.ToString() + @"' />
<condition attribute='new_s' operator='eq' value='' />
<condition attribute='new_ld' operator='eq' value='" + location + @"' />
<condition attribute='new_productid' operator='not-null' />
</filter>
<link-entity name='new_ys' from='new_ysid' to='new_orderid' link-type='inner' alias='ae'>
<filter type='and'>
<condition attribute='new_ysid' operator='eq' value='{" + yGuid.ToString() + @"}' />
</filter>
</link-entity>
</entity>
</fetch>";
EntityCollection Labels = service.RetrieveMultiple(new FetchExpression(fetch));
I need to filter the above entitycollection based on the 'new_productid' attribute. If two entities have the same value for 'new_productid', then I only want one of those entities to be rendered into a new filtered entity collection. I would need new_productid and new_subquantity and new_rlsid to be in my new entitycollection.
I noticed that LINQ has the .Distinct() property, but all the msdn examples for CRM show how to do this with LINQ using early binding. All of my plugins are late bound and need a Linq solution for late binding.
c# linq dynamics-crm dynamics-crm-online dynamics-365
edited Jan 2 at 21:39
Hogan
55.6k967103
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
I have an entitycollection composed from a fetchXML query.
string fetch = @"
<fetch version='1.0' output-format='xml-platform' mapping='logical' distinct='false'>
<entity name='new_rl'>
<attribute name='new_rlsid' />
<attribute name='new_productid' />
<attribute name='new_subquantity' />
<filter type='and'>
<condition attribute='new_sg' operator='eq' value='" + servingGroup.Value.ToString() + @"' />
<condition attribute='new_s' operator='eq' value='' />
<condition attribute='new_ld' operator='eq' value='" + location + @"' />
<condition attribute='new_productid' operator='not-null' />
</filter>
<link-entity name='new_ys' from='new_ysid' to='new_orderid' link-type='inner' alias='ae'>
<filter type='and'>
<condition attribute='new_ysid' operator='eq' value='{" + yGuid.ToString() + @"}' />
</filter>
</link-entity>
</entity>
</fetch>";
EntityCollection Labels = service.RetrieveMultiple(new FetchExpression(fetch));
I need to filter the above entitycollection based on the 'new_productid' attribute. If two entities have the same value for 'new_productid', then I only want one of those entities to be rendered into a new filtered entity collection. I would need new_productid and new_subquantity and new_rlsid to be in my new entitycollection.
I noticed that LINQ has the .Distinct() property, but all the msdn examples for CRM show how to do this with LINQ using early binding. All of my plugins are late bound and need a Linq solution for late binding.
c# linq dynamics-crm dynamics-crm-online dynamics-365
c# linq dynamics-crm dynamics-crm-online dynamics-365
edited Jan 2 at 21:39
Hogan
55.6k967103
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
edited Jan 2 at 21:39
Hogan
55.6k967103
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
edited Jan 2 at 21:39
Hogan
55.6k967103
edited Jan 2 at 21:39
Hogan
55.6k967103
edited Jan 2 at 21:39
Hogan
55.6k967103
55.6k967103
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
asked Jan 2 at 21:00
Alan JudiAlan Judi
351315
351315
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
This example shows late bound with LINQ:
using (var context = new OrganizationServiceContext(service))
{
var result = (from a in context.CreateQuery("account")
join o in context.CreateQuery("opportunity")
on a.GetAttributeValue<Guid>("accountid") equals o.GetAttributeValue<Guid>("new_officeid")
where a.GetAttributeValue<OptionSetValue>("statecode").Value == 0
where o.GetAttributeValue<Guid>("parentaccountid") != Guid.Empty
orderby a.GetAttributeValue<string>("name")
select new KeyValuePair<Guid, string>(a.GetAttributeValue<Guid>("accountid"), a.GetAttributeValue<string>("name")))
.Distinct();
}
answered Jan 3 at 2:15
AronAron
2,37031019
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This example shows late bound with LINQ:
using (var context = new OrganizationServiceContext(service))
{
var result = (from a in context.CreateQuery("account")
join o in context.CreateQuery("opportunity")
on a.GetAttributeValue<Guid>("accountid") equals o.GetAttributeValue<Guid>("new_officeid")
where a.GetAttributeValue<OptionSetValue>("statecode").Value == 0
where o.GetAttributeValue<Guid>("parentaccountid") != Guid.Empty
orderby a.GetAttributeValue<string>("name")
select new KeyValuePair<Guid, string>(a.GetAttributeValue<Guid>("accountid"), a.GetAttributeValue<string>("name")))
.Distinct();
}
answered Jan 3 at 2:15
AronAron
2,37031019
add a comment |
This example shows late bound with LINQ:
using (var context = new OrganizationServiceContext(service))
{
var result = (from a in context.CreateQuery("account")
join o in context.CreateQuery("opportunity")
on a.GetAttributeValue<Guid>("accountid") equals o.GetAttributeValue<Guid>("new_officeid")
where a.GetAttributeValue<OptionSetValue>("statecode").Value == 0
where o.GetAttributeValue<Guid>("parentaccountid") != Guid.Empty
orderby a.GetAttributeValue<string>("name")
select new KeyValuePair<Guid, string>(a.GetAttributeValue<Guid>("accountid"), a.GetAttributeValue<string>("name")))
.Distinct();
}
answered Jan 3 at 2:15
AronAron
2,37031019
add a comment |
This example shows late bound with LINQ:
using (var context = new OrganizationServiceContext(service))
{
var result = (from a in context.CreateQuery("account")
join o in context.CreateQuery("opportunity")
on a.GetAttributeValue<Guid>("accountid") equals o.GetAttributeValue<Guid>("new_officeid")
where a.GetAttributeValue<OptionSetValue>("statecode").Value == 0
where o.GetAttributeValue<Guid>("parentaccountid") != Guid.Empty
orderby a.GetAttributeValue<string>("name")
select new KeyValuePair<Guid, string>(a.GetAttributeValue<Guid>("accountid"), a.GetAttributeValue<string>("name")))
.Distinct();
}
answered Jan 3 at 2:15
AronAron
2,37031019
This example shows late bound with LINQ:
using (var context = new OrganizationServiceContext(service))
{
var result = (from a in context.CreateQuery("account")
join o in context.CreateQuery("opportunity")
on a.GetAttributeValue<Guid>("accountid") equals o.GetAttributeValue<Guid>("new_officeid")
where a.GetAttributeValue<OptionSetValue>("statecode").Value == 0
where o.GetAttributeValue<Guid>("parentaccountid") != Guid.Empty
orderby a.GetAttributeValue<string>("name")
select new KeyValuePair<Guid, string>(a.GetAttributeValue<Guid>("accountid"), a.GetAttributeValue<string>("name")))
.Distinct();
}
answered Jan 3 at 2:15
AronAron
2,37031019
answered Jan 3 at 2:15
AronAron
2,37031019
answered Jan 3 at 2:15
AronAron
2,37031019
answered Jan 3 at 2:15
AronAron
2,37031019
2,37031019
add a comment |
add a comment |
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