Questions about Functions












-1












$begingroup$


The function $f$ is defined by $f(x)=frac{(m+x)}{(2+3x)}$ for all values of $x$ except when $x=h$ and $m$ is a constant. Given that value of $1$ is unchanged under this mapping, how should I find the value of $m$?






functions







share|cite|improve this question











$endgroup$












  • $begingroup$
    @KushalBhuyan: I re-added the dollar signs around "m" and "1" because all mathematics should be set in math-mode. (I also added them around $f$ at the start of the first sentence.) Does that make sense?
    $endgroup$
    – John Hughes
    Jan 29 at 13:14










  • $begingroup$
    @JohnHughes Yes thank you. It does make sense.
    $endgroup$
    – Kushal Bhuyan
    Jan 29 at 14:48










  • $begingroup$
    You recieved 2 answers to your question. Is any of them what you needed? If so, you should upvote all the useful answers and accept the answer that is most useful to you.
    $endgroup$
    – 5xum
    Feb 11 at 11:33
















-1












$begingroup$


The function $f$ is defined by $f(x)=frac{(m+x)}{(2+3x)}$ for all values of $x$ except when $x=h$ and $m$ is a constant. Given that value of $1$ is unchanged under this mapping, how should I find the value of $m$?






functions







share|cite|improve this question











$endgroup$












  • $begingroup$
    @KushalBhuyan: I re-added the dollar signs around "m" and "1" because all mathematics should be set in math-mode. (I also added them around $f$ at the start of the first sentence.) Does that make sense?
    $endgroup$
    – John Hughes
    Jan 29 at 13:14










  • $begingroup$
    @JohnHughes Yes thank you. It does make sense.
    $endgroup$
    – Kushal Bhuyan
    Jan 29 at 14:48










  • $begingroup$
    You recieved 2 answers to your question. Is any of them what you needed? If so, you should upvote all the useful answers and accept the answer that is most useful to you.
    $endgroup$
    – 5xum
    Feb 11 at 11:33














-1












-1








-1


0



$begingroup$


The function $f$ is defined by $f(x)=frac{(m+x)}{(2+3x)}$ for all values of $x$ except when $x=h$ and $m$ is a constant. Given that value of $1$ is unchanged under this mapping, how should I find the value of $m$?






functions







share|cite|improve this question











$endgroup$




The function $f$ is defined by $f(x)=frac{(m+x)}{(2+3x)}$ for all values of $x$ except when $x=h$ and $m$ is a constant. Given that value of $1$ is unchanged under this mapping, how should I find the value of $m$?






functions




functions






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 29 at 13:12









John Hughes

65.1k24292




65.1k24292










asked Jan 29 at 12:48









LeonLeon

21




21












  • $begingroup$
    @KushalBhuyan: I re-added the dollar signs around "m" and "1" because all mathematics should be set in math-mode. (I also added them around $f$ at the start of the first sentence.) Does that make sense?
    $endgroup$
    – John Hughes
    Jan 29 at 13:14










  • $begingroup$
    @JohnHughes Yes thank you. It does make sense.
    $endgroup$
    – Kushal Bhuyan
    Jan 29 at 14:48










  • $begingroup$
    You recieved 2 answers to your question. Is any of them what you needed? If so, you should upvote all the useful answers and accept the answer that is most useful to you.
    $endgroup$
    – 5xum
    Feb 11 at 11:33


















  • $begingroup$
    @KushalBhuyan: I re-added the dollar signs around "m" and "1" because all mathematics should be set in math-mode. (I also added them around $f$ at the start of the first sentence.) Does that make sense?
    $endgroup$
    – John Hughes
    Jan 29 at 13:14










  • $begingroup$
    @JohnHughes Yes thank you. It does make sense.
    $endgroup$
    – Kushal Bhuyan
    Jan 29 at 14:48










  • $begingroup$
    You recieved 2 answers to your question. Is any of them what you needed? If so, you should upvote all the useful answers and accept the answer that is most useful to you.
    $endgroup$
    – 5xum
    Feb 11 at 11:33
















$begingroup$
@KushalBhuyan: I re-added the dollar signs around "m" and "1" because all mathematics should be set in math-mode. (I also added them around $f$ at the start of the first sentence.) Does that make sense?
$endgroup$
– John Hughes
Jan 29 at 13:14




$begingroup$
@KushalBhuyan: I re-added the dollar signs around "m" and "1" because all mathematics should be set in math-mode. (I also added them around $f$ at the start of the first sentence.) Does that make sense?
$endgroup$
– John Hughes
Jan 29 at 13:14












$begingroup$
@JohnHughes Yes thank you. It does make sense.
$endgroup$
– Kushal Bhuyan
Jan 29 at 14:48




$begingroup$
@JohnHughes Yes thank you. It does make sense.
$endgroup$
– Kushal Bhuyan
Jan 29 at 14:48












$begingroup$
You recieved 2 answers to your question. Is any of them what you needed? If so, you should upvote all the useful answers and accept the answer that is most useful to you.
$endgroup$
– 5xum
Feb 11 at 11:33




$begingroup$
You recieved 2 answers to your question. Is any of them what you needed? If so, you should upvote all the useful answers and accept the answer that is most useful to you.
$endgroup$
– 5xum
Feb 11 at 11:33










2 Answers
2






active

oldest

votes


















2












$begingroup$

Hint



The sentence




The value of $1$ is unchanged under this mapping




translates into the equation $$f(1)=1.$$






share|cite|improve this answer









$endgroup$





















    2












    $begingroup$

    $f(1)=frac{m+1}{2+3}=1 iff m+1=5 iff m=4.$






    share|cite|improve this answer









    $endgroup$














      Your Answer





      StackExchange.ifUsing("editor", function () {
      return StackExchange.using("mathjaxEditing", function () {
      StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
      StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
      });
      });
      }, "mathjax-editing");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "69"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      noCode: true, onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3092125%2fquestions-about-functions%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2












      $begingroup$

      Hint



      The sentence




      The value of $1$ is unchanged under this mapping




      translates into the equation $$f(1)=1.$$






      share|cite|improve this answer









      $endgroup$


















        2












        $begingroup$

        Hint



        The sentence




        The value of $1$ is unchanged under this mapping




        translates into the equation $$f(1)=1.$$






        share|cite|improve this answer









        $endgroup$
















          2












          2








          2





          $begingroup$

          Hint



          The sentence




          The value of $1$ is unchanged under this mapping




          translates into the equation $$f(1)=1.$$






          share|cite|improve this answer









          $endgroup$



          Hint



          The sentence




          The value of $1$ is unchanged under this mapping




          translates into the equation $$f(1)=1.$$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 29 at 12:49









          5xum5xum

          91.9k394161




          91.9k394161























              2












              $begingroup$

              $f(1)=frac{m+1}{2+3}=1 iff m+1=5 iff m=4.$






              share|cite|improve this answer









              $endgroup$


















                2












                $begingroup$

                $f(1)=frac{m+1}{2+3}=1 iff m+1=5 iff m=4.$






                share|cite|improve this answer









                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  $f(1)=frac{m+1}{2+3}=1 iff m+1=5 iff m=4.$






                  share|cite|improve this answer









                  $endgroup$



                  $f(1)=frac{m+1}{2+3}=1 iff m+1=5 iff m=4.$







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jan 29 at 12:50









                  FredFred

                  48.9k11849




                  48.9k11849






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Mathematics Stack Exchange!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid …



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      Use MathJax to format equations. MathJax reference.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3092125%2fquestions-about-functions%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Can a sorcerer learn a 5th-level spell early by creating spell slots using the Font of Magic feature?

                      Image
                      28 6 $begingroup$ Per the Font of Magic feature, sorcerer can use Flexible Casting to create 5th-level spell slots at level 7, even though they are not typically available until level 9. You can transform unexpended sorcery points into one spell slot as a bonus action on your turn. The Creating Spell Slots table shows the cost of creating a spell slot of [5th level is 7] If such a sorcerer levels up while still having this 5th-level spell slot, can they choose a 5th-level spell as the spell they gain upon levelling up? The Spellcasting feature states: Additionally, when you gain a level in this class, you can choose one of the sorcerer spells you know and replace it with another spell from the sorcerer spell list, which also must be of a level for which you have spell slots.
                      Read more

                      Does disintegrating a polymorphed enemy still kill it after the 2018 errata?

                      Image
                      up vote 13 down vote favorite 1 After the 2018 errata, the disintegrate spell description now reads: A creature targeted by this spell must make a Dexterity saving throw. On a failed save, the target takes 10d6 + 40 force damage. The target is disintegrated if this damage leaves it with 0 hit points. If you were to polymorph an enemy into a rat and then disintegrate it, would the enemy be disintegrated or would it just return to its original form? I know that for Druids, it’s not an instant kill anymore, but is this the case for polymorph as well? dnd-5e spells polymorph errata share | improve this question edited 18 hours ago
                      Read more

                      A Topological Invariant for $pi_3(U(n))$

                      Image
                      3 3 $begingroup$ Recently, I saw a construction of topological invariant for $pi_3(U(n))$ with $ngeq 2$ : $$ N=frac{1}{24pi^2}int_{S^3} d^3x epsilon^{ijk} Tr[(U^{-1}partial_{x_i}U)(U^{-1}partial_{x_j}U)(U^{-1}partial_{x_k}U)] , $$ where $Uin U(n)$ depends on $boldsymbol{x}=(x_1,x_2,x_3)in S^3$ , $epsilon^{ijk}$ is the Levi-Civita symbol, $i,j,k=1,2,3$ , and the duplicated indexes are summed over. It is claimed that $N$ is an integer, but why? Update 02/02/2019 I think I got an argument for $n=2$ . In this case, $U=e^{i varphi} q$ with $qin SU(2)$ . Due to the trace and the Levi-Civita symbol in $N$ , $varphi$ does not contribute to $N$ . As $Tr[q^{dagger}partial_i q]=0$ and $(q^{dagger}partial_i q)^{dagger}=-q^{dagger}partial_i q$ , $q^{dagger}partial_i q$ in geneeral has the form $q^{dagger}partia
                      Read more