How to make R skip for 2:n cycle in case n = 1?












2















I have the next query.
I have a cycle



for (i in 2:n) { ... }


and it executes twice in case n = 1 for i equals 2 and then for 1, but I want this cycle isn't been executed at all in such case.
I've also tried



seq(from = 2, to = 1, by = 1)


but it generates exception.



I guess than common question, but I am new in that language and wasn't able to bypass it or find workaround in internet.
Thank you in advance.






r range







share|improve this question


















  • 2





    : or seq don't work that way. You could use the length.out param in seq: seq(from = 2, to = n,length.out = (n-2)+1)

    – Omri374
    Jan 1 at 13:37


















2















I have the next query.
I have a cycle



for (i in 2:n) { ... }


and it executes twice in case n = 1 for i equals 2 and then for 1, but I want this cycle isn't been executed at all in such case.
I've also tried



seq(from = 2, to = 1, by = 1)


but it generates exception.



I guess than common question, but I am new in that language and wasn't able to bypass it or find workaround in internet.
Thank you in advance.






r range







share|improve this question


















  • 2





    : or seq don't work that way. You could use the length.out param in seq: seq(from = 2, to = n,length.out = (n-2)+1)

    – Omri374
    Jan 1 at 13:37
















2












2








2








I have the next query.
I have a cycle



for (i in 2:n) { ... }


and it executes twice in case n = 1 for i equals 2 and then for 1, but I want this cycle isn't been executed at all in such case.
I've also tried



seq(from = 2, to = 1, by = 1)


but it generates exception.



I guess than common question, but I am new in that language and wasn't able to bypass it or find workaround in internet.
Thank you in advance.






r range







share|improve this question














I have the next query.
I have a cycle



for (i in 2:n) { ... }


and it executes twice in case n = 1 for i equals 2 and then for 1, but I want this cycle isn't been executed at all in such case.
I've also tried



seq(from = 2, to = 1, by = 1)


but it generates exception.



I guess than common question, but I am new in that language and wasn't able to bypass it or find workaround in internet.
Thank you in advance.






r range




r range






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 1 at 13:24









LinearLeopardLinearLeopard

981111




981111








  • 2





    : or seq don't work that way. You could use the length.out param in seq: seq(from = 2, to = n,length.out = (n-2)+1)

    – Omri374
    Jan 1 at 13:37
















  • 2





    : or seq don't work that way. You could use the length.out param in seq: seq(from = 2, to = n,length.out = (n-2)+1)

    – Omri374
    Jan 1 at 13:37










2




2





: or seq don't work that way. You could use the length.out param in seq: seq(from = 2, to = n,length.out = (n-2)+1)

– Omri374
Jan 1 at 13:37







: or seq don't work that way. You could use the length.out param in seq: seq(from = 2, to = n,length.out = (n-2)+1)

– Omri374
Jan 1 at 13:37














1 Answer
1






active

oldest

votes


















7














Use seq_len which is safer to use



n <- 1

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Does not print anything



n <- 4

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Check 2 

#Check 3 

#Check 4


When you use 2:n and when n = 1 it gives



2:1

#[1] 2 1


hence, it runs the loop twice.






share|improve this answer



















  • 2





    I made a stupid mistake. It should be seq_len(n-1) + 1.

    – mt1022
    Jan 1 at 14:51











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









7














Use seq_len which is safer to use



n <- 1

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Does not print anything



n <- 4

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Check 2 

#Check 3 

#Check 4


When you use 2:n and when n = 1 it gives



2:1

#[1] 2 1


hence, it runs the loop twice.






share|improve this answer



















  • 2





    I made a stupid mistake. It should be seq_len(n-1) + 1.

    – mt1022
    Jan 1 at 14:51
















7














Use seq_len which is safer to use



n <- 1

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Does not print anything



n <- 4

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Check 2 

#Check 3 

#Check 4


When you use 2:n and when n = 1 it gives



2:1

#[1] 2 1


hence, it runs the loop twice.






share|improve this answer



















  • 2





    I made a stupid mistake. It should be seq_len(n-1) + 1.

    – mt1022
    Jan 1 at 14:51














7












7








7







Use seq_len which is safer to use



n <- 1

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Does not print anything



n <- 4

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Check 2 

#Check 3 

#Check 4


When you use 2:n and when n = 1 it gives



2:1

#[1] 2 1


hence, it runs the loop twice.






share|improve this answer













Use seq_len which is safer to use



n <- 1

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Does not print anything



n <- 4

for (i in seq_len(n)[-1]) {

  cat("Check", i, "n")

}



#Check 2 

#Check 3 

#Check 4


When you use 2:n and when n = 1 it gives



2:1

#[1] 2 1


hence, it runs the loop twice.







share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 1 at 13:33









Ronak ShahRonak Shah

39.8k104162




39.8k104162








  • 2





    I made a stupid mistake. It should be seq_len(n-1) + 1.

    – mt1022
    Jan 1 at 14:51














  • 2





    I made a stupid mistake. It should be seq_len(n-1) + 1.

    – mt1022
    Jan 1 at 14:51








2




2





I made a stupid mistake. It should be seq_len(n-1) + 1.

– mt1022
Jan 1 at 14:51





I made a stupid mistake. It should be seq_len(n-1) + 1.

– mt1022
Jan 1 at 14:51




















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