I need to identify local users vs. sssd users in /etc/bashrc
I have a CentOS system. There are local users (root, etc.) and Active Directory users via sssd/realm. Is there a way in /etc/bashrc to test for local users?
I'm using a structure like this:
GROUPS=`id -Gr $USER`
for i in "${GROUPS[@]}"; do
#admin check
if [ $i == 199299399 ]; then
to identify specific groups for the Active Directory users. It isn't practical for me to enumerate all the local groups.
linux security ldap centos7
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I have a CentOS system. There are local users (root, etc.) and Active Directory users via sssd/realm. Is there a way in /etc/bashrc to test for local users?
I'm using a structure like this:
GROUPS=`id -Gr $USER`
for i in "${GROUPS[@]}"; do
#admin check
if [ $i == 199299399 ]; then
to identify specific groups for the Active Directory users. It isn't practical for me to enumerate all the local groups.
linux security ldap centos7
add a comment |
I have a CentOS system. There are local users (root, etc.) and Active Directory users via sssd/realm. Is there a way in /etc/bashrc to test for local users?
I'm using a structure like this:
GROUPS=`id -Gr $USER`
for i in "${GROUPS[@]}"; do
#admin check
if [ $i == 199299399 ]; then
to identify specific groups for the Active Directory users. It isn't practical for me to enumerate all the local groups.
linux security ldap centos7
I have a CentOS system. There are local users (root, etc.) and Active Directory users via sssd/realm. Is there a way in /etc/bashrc to test for local users?
I'm using a structure like this:
GROUPS=`id -Gr $USER`
for i in "${GROUPS[@]}"; do
#admin check
if [ $i == 199299399 ]; then
to identify specific groups for the Active Directory users. It isn't practical for me to enumerate all the local groups.
linux security ldap centos7
linux security ldap centos7
edited Jan 2 at 20:14
C Bar
asked Jan 2 at 20:02
C BarC Bar
12
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1 Answer
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Found this, which works for my situation:
elif [[ -z `grep $USER /etc/passwd 1> /dev/null` ]]; then
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Found this, which works for my situation:
elif [[ -z `grep $USER /etc/passwd 1> /dev/null` ]]; then
add a comment |
Found this, which works for my situation:
elif [[ -z `grep $USER /etc/passwd 1> /dev/null` ]]; then
add a comment |
Found this, which works for my situation:
elif [[ -z `grep $USER /etc/passwd 1> /dev/null` ]]; then
Found this, which works for my situation:
elif [[ -z `grep $USER /etc/passwd 1> /dev/null` ]]; then
answered Jan 3 at 13:00
C BarC Bar
12
12
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add a comment |
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