Return JSON response from Flask view

338

I have a function that analyzes a CSV file with Pandas and produces a dict with summary information. I want to return the results as a response from a Flask view. How do I return a JSON response?

@app.route("/summary")

def summary():

    d = make_summary()

    # send it back as json

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

add a comment |

338

I have a function that analyzes a CSV file with Pandas and produces a dict with summary information. I want to return the results as a response from a Flask view. How do I return a JSON response?

@app.route("/summary")

def summary():

    d = make_summary()

    # send it back as json

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

add a comment |

338

I have a function that analyzes a CSV file with Pandas and produces a dict with summary information. I want to return the results as a response from a Flask view. How do I return a JSON response?

@app.route("/summary")

def summary():

    d = make_summary()

    # send it back as json

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

I have a function that analyzes a CSV file with Pandas and produces a dict with summary information. I want to return the results as a response from a Flask view. How do I return a JSON response?

@app.route("/summary")

def summary():

    d = make_summary()

    # send it back as json

python json flask

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

edited Jan 26 '17 at 16:45

davidism

65.8k12178191

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

asked Oct 26 '12 at 5:56

Code Ninja

1,83131111

add a comment |

9 Answers
9

active

oldest

votes

555

Pass the summary data to the jsonify function, which returns a JSON response.

from flask import jsonify



@app.route('/summary')

def summary():

    d = make_summary()

    return jsonify(d)

As of Flask 0.11, you can pass any JSON-serializable type, not just dict, as the top level object.

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

As of flask version 1.0.2, jsonify will not preserve the attribute order of a passed dict. If you need that, use the Response class, see other answers.

– Wolfgang Kuehn
Feb 21 at 16:24

Why is the browser output an ugly string? app.config['JSONIFY_PRETTYPRINT_REGULAR'] = True, does nothing

– F. Malina
Mar 13 at 15:31

add a comment |

154

jsonify serializes the data you pass it to JSON. If you want to serialize the data yourself, do what jsonify does by building a response with status=200 and mimetype='application/json'.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        status=200,

        mimetype='application/json'

    )

    return response

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

answered Nov 16 '14 at 20:16

scls

6,53862839

@Tjorriemorrie Might not want a top level list. See stackoverflow.com/questions/3503102/…

– rob
Jun 16 '15 at 0:41

8

you can return status code with jsonify too return jsonify({"Error" : "Access restricted"}), 403

– naXa
Apr 11 '16 at 20:46

2

or just return json.dumps(data), 200, 'application/json' is shorter

– CpILL
Aug 27 '18 at 9:33

For some use cases, you can use jsonify(data) in place of json.dumps(data) and it will work fine.

– Patrick Mutuku
Feb 15 at 14:59

add a comment |

101

Pass keyword arguments to flask.jsonify and they will be output as a JSON object.

@app.route('/_get_current_user')

def get_current_user():

    return jsonify(

        username=g.user.username,

        email=g.user.email,

        id=g.user.id

    )

{

    "username": "admin",

    "email": "admin@localhost",

    "id": 42

}

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

can you please elaborate me with the code to identify filename.

– Code Ninja
Oct 26 '12 at 8:23

@CodeNinja What do you mean? If you want to putput the f dict from your original code, you should do return jsonify(**f).

– Markus Unterwaditzer
Oct 30 '12 at 6:59

1

What if I want to return structure like { 'names': { 'first': 'Frank', last: 'Sinatra'}, 'age': 98} ?

– David Sergey
Nov 13 '13 at 15:39

3

It's just a nested dict. Try this: jsonify({ 'names': { 'first': 'Frank', 'last': 'Sinatra'}, 'age': 98})

– zengr
Nov 13 '13 at 16:06

add a comment |

If you don't want to use jsonify for some reason, you can do what it does manually. Call flask.json.dumps to create JSON data, then return a response with the application/json content type.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        mimetype='application/json'

    )

    return response

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

import json (instead of from flask ...) works just as well.

– Uri Goren
Jan 11 at 18:03

add a comment |

If you want to analyze a file uploaded by the user, the Flask quickstart shows how to get files from users and access them. Get the file from request.files and pass it to the summary function.

from flask import request, jsonify

from werkzeug import secure_filename



@app.route('/summary', methods=['GET', 'POST'])

def summary():

    if request.method == 'POST':

        csv = request.files['data']

        return jsonify(

            summary=make_summary(csv),

            csv_name=secure_filename(csv.filename)

        )



    return render_template('submit_data.html')

Replace the 'data' key for request.files with the name of the file input in your HTML form.

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

answered Dec 5 '13 at 16:44

teechap

54656

add a comment |

You can write a decorator to convert the return value from a view function into a JSON response.

def return_json(view):

    @functools.wraps(view)

    def wrapped_view(**values):

        return jsonify(view(**values))

    return wrapped_view





@app.route('/test/<arg>')

@return_json

def test(arg):

    if arg == 'list':

        return [1, 2, 3]

    elif arg == 'dict':

        return {'a': 1, 'b': 2}

    elif arg == 'bool':

        return True

    return 'non of them'

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

answered Jun 10 '16 at 13:37

iman

9,22162421

1

@return_json doesn't work with status codes.

– Roman Orac
Sep 24 '18 at 9:11

add a comment |

Prior to Flask 0.11, jsonfiy would not allow returning an array directly. Instead, pass the list as a keyword argument.

@app.route('/get_records')

def get_records():

    results = [

        {

          "rec_create_date": "12 Jun 2016",

          "rec_dietary_info": "nothing",

          "rec_dob": "01 Apr 1988",

          "rec_first_name": "New",

          "rec_last_name": "Guy",

        },

        {

          "rec_create_date": "1 Apr 2016",

          "rec_dietary_info": "Nut allergy",

          "rec_dob": "01 Feb 1988",

          "rec_first_name": "Old",

          "rec_last_name": "Guy",

        },

    ]

    return jsonify(results=list)

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

answered Jun 26 '16 at 15:42

mania_device

11517

add a comment |

-2

Like said previously jsonify is the best way or you could also use Flask-responses' package at https://github.com/Parkayun/flask-responses

@app.route("/json")

def hello():

    return json_response(your_dict, status_code=201)

edited May 3 '16 at 16:56

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

add a comment |

-2

You can try this approach:

from flask import jsonify, Flask



app = Flask(__name__)



@app.route("/summary")

def summary():

    d = make_summary()

    return jsonify(d)

edited Jan 21 at 10:32

iamdanchiv

2,67642432

answered Jan 21 at 9:49

theophilus okoye

add a comment |

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9 Answers
9

active

oldest

votes

9 Answers
9

active

oldest

votes

555

Pass the summary data to the jsonify function, which returns a JSON response.

from flask import jsonify



@app.route('/summary')

def summary():

    d = make_summary()

    return jsonify(d)

As of Flask 0.11, you can pass any JSON-serializable type, not just dict, as the top level object.

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

As of flask version 1.0.2, jsonify will not preserve the attribute order of a passed dict. If you need that, use the Response class, see other answers.

– Wolfgang Kuehn
Feb 21 at 16:24

Why is the browser output an ugly string? app.config['JSONIFY_PRETTYPRINT_REGULAR'] = True, does nothing

– F. Malina
Mar 13 at 15:31

add a comment |

555

Pass the summary data to the jsonify function, which returns a JSON response.

from flask import jsonify



@app.route('/summary')

def summary():

    d = make_summary()

    return jsonify(d)

As of Flask 0.11, you can pass any JSON-serializable type, not just dict, as the top level object.

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

As of flask version 1.0.2, jsonify will not preserve the attribute order of a passed dict. If you need that, use the Response class, see other answers.

– Wolfgang Kuehn
Feb 21 at 16:24

Why is the browser output an ugly string? app.config['JSONIFY_PRETTYPRINT_REGULAR'] = True, does nothing

– F. Malina
Mar 13 at 15:31

add a comment |

555

Pass the summary data to the jsonify function, which returns a JSON response.

from flask import jsonify



@app.route('/summary')

def summary():

    d = make_summary()

    return jsonify(d)

As of Flask 0.11, you can pass any JSON-serializable type, not just dict, as the top level object.

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

Pass the summary data to the jsonify function, which returns a JSON response.

from flask import jsonify



@app.route('/summary')

def summary():

    d = make_summary()

    return jsonify(d)

As of Flask 0.11, you can pass any JSON-serializable type, not just dict, as the top level object.

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

edited Jan 26 '17 at 16:41

davidism

65.8k12178191

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

answered Oct 26 '12 at 15:33

codegeek

18.6k84859

As of flask version 1.0.2, jsonify will not preserve the attribute order of a passed dict. If you need that, use the Response class, see other answers.

– Wolfgang Kuehn
Feb 21 at 16:24

Why is the browser output an ugly string? app.config['JSONIFY_PRETTYPRINT_REGULAR'] = True, does nothing

– F. Malina
Mar 13 at 15:31

add a comment |

As of flask version 1.0.2, jsonify will not preserve the attribute order of a passed dict. If you need that, use the Response class, see other answers.

– Wolfgang Kuehn
Feb 21 at 16:24

Why is the browser output an ugly string? app.config['JSONIFY_PRETTYPRINT_REGULAR'] = True, does nothing

– F. Malina
Mar 13 at 15:31

As of flask version 1.0.2, jsonify will not preserve the attribute order of a passed dict. If you need that, use the Response class, see other answers.

– Wolfgang Kuehn
Feb 21 at 16:24

Why is the browser output an ugly string? app.config['JSONIFY_PRETTYPRINT_REGULAR'] = True, does nothing

– F. Malina
Mar 13 at 15:31

add a comment |

154

jsonify serializes the data you pass it to JSON. If you want to serialize the data yourself, do what jsonify does by building a response with status=200 and mimetype='application/json'.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        status=200,

        mimetype='application/json'

    )

    return response

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

answered Nov 16 '14 at 20:16

scls

6,53862839

@Tjorriemorrie Might not want a top level list. See stackoverflow.com/questions/3503102/…

– rob
Jun 16 '15 at 0:41

8

you can return status code with jsonify too return jsonify({"Error" : "Access restricted"}), 403

– naXa
Apr 11 '16 at 20:46

2

or just return json.dumps(data), 200, 'application/json' is shorter

– CpILL
Aug 27 '18 at 9:33

For some use cases, you can use jsonify(data) in place of json.dumps(data) and it will work fine.

– Patrick Mutuku
Feb 15 at 14:59

add a comment |

154

jsonify serializes the data you pass it to JSON. If you want to serialize the data yourself, do what jsonify does by building a response with status=200 and mimetype='application/json'.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        status=200,

        mimetype='application/json'

    )

    return response

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

answered Nov 16 '14 at 20:16

scls

6,53862839

@Tjorriemorrie Might not want a top level list. See stackoverflow.com/questions/3503102/…

– rob
Jun 16 '15 at 0:41

8

you can return status code with jsonify too return jsonify({"Error" : "Access restricted"}), 403

– naXa
Apr 11 '16 at 20:46

2

or just return json.dumps(data), 200, 'application/json' is shorter

– CpILL
Aug 27 '18 at 9:33

For some use cases, you can use jsonify(data) in place of json.dumps(data) and it will work fine.

– Patrick Mutuku
Feb 15 at 14:59

add a comment |

154

jsonify serializes the data you pass it to JSON. If you want to serialize the data yourself, do what jsonify does by building a response with status=200 and mimetype='application/json'.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        status=200,

        mimetype='application/json'

    )

    return response

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

answered Nov 16 '14 at 20:16

scls

6,53862839

jsonify serializes the data you pass it to JSON. If you want to serialize the data yourself, do what jsonify does by building a response with status=200 and mimetype='application/json'.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        status=200,

        mimetype='application/json'

    )

    return response

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

answered Nov 16 '14 at 20:16

scls

6,53862839

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

edited Jan 26 '17 at 16:51

davidism

65.8k12178191

answered Nov 16 '14 at 20:16

scls

6,53862839

answered Nov 16 '14 at 20:16

scls

6,53862839

answered Nov 16 '14 at 20:16

scls

6,53862839

@Tjorriemorrie Might not want a top level list. See stackoverflow.com/questions/3503102/…

– rob
Jun 16 '15 at 0:41

8

you can return status code with jsonify too return jsonify({"Error" : "Access restricted"}), 403

– naXa
Apr 11 '16 at 20:46

2

or just return json.dumps(data), 200, 'application/json' is shorter

– CpILL
Aug 27 '18 at 9:33

For some use cases, you can use jsonify(data) in place of json.dumps(data) and it will work fine.

– Patrick Mutuku
Feb 15 at 14:59

add a comment |

@Tjorriemorrie Might not want a top level list. See stackoverflow.com/questions/3503102/…

– rob
Jun 16 '15 at 0:41

8

you can return status code with jsonify too return jsonify({"Error" : "Access restricted"}), 403

– naXa
Apr 11 '16 at 20:46

2

or just return json.dumps(data), 200, 'application/json' is shorter

– CpILL
Aug 27 '18 at 9:33

For some use cases, you can use jsonify(data) in place of json.dumps(data) and it will work fine.

– Patrick Mutuku
Feb 15 at 14:59

@Tjorriemorrie Might not want a top level list. See stackoverflow.com/questions/3503102/…

– rob
Jun 16 '15 at 0:41

you can return status code with jsonify too return jsonify({"Error" : "Access restricted"}), 403

– naXa
Apr 11 '16 at 20:46

or just return json.dumps(data), 200, 'application/json' is shorter

– CpILL
Aug 27 '18 at 9:33

For some use cases, you can use jsonify(data) in place of json.dumps(data) and it will work fine.

– Patrick Mutuku
Feb 15 at 14:59

add a comment |

101

Pass keyword arguments to flask.jsonify and they will be output as a JSON object.

@app.route('/_get_current_user')

def get_current_user():

    return jsonify(

        username=g.user.username,

        email=g.user.email,

        id=g.user.id

    )

{

    "username": "admin",

    "email": "admin@localhost",

    "id": 42

}

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

can you please elaborate me with the code to identify filename.

– Code Ninja
Oct 26 '12 at 8:23

@CodeNinja What do you mean? If you want to putput the f dict from your original code, you should do return jsonify(**f).

– Markus Unterwaditzer
Oct 30 '12 at 6:59

1

What if I want to return structure like { 'names': { 'first': 'Frank', last: 'Sinatra'}, 'age': 98} ?

– David Sergey
Nov 13 '13 at 15:39

3

It's just a nested dict. Try this: jsonify({ 'names': { 'first': 'Frank', 'last': 'Sinatra'}, 'age': 98})

– zengr
Nov 13 '13 at 16:06

add a comment |

101

Pass keyword arguments to flask.jsonify and they will be output as a JSON object.

@app.route('/_get_current_user')

def get_current_user():

    return jsonify(

        username=g.user.username,

        email=g.user.email,

        id=g.user.id

    )

{

    "username": "admin",

    "email": "admin@localhost",

    "id": 42

}

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

can you please elaborate me with the code to identify filename.

– Code Ninja
Oct 26 '12 at 8:23

@CodeNinja What do you mean? If you want to putput the f dict from your original code, you should do return jsonify(**f).

– Markus Unterwaditzer
Oct 30 '12 at 6:59

1

What if I want to return structure like { 'names': { 'first': 'Frank', last: 'Sinatra'}, 'age': 98} ?

– David Sergey
Nov 13 '13 at 15:39

3

It's just a nested dict. Try this: jsonify({ 'names': { 'first': 'Frank', 'last': 'Sinatra'}, 'age': 98})

– zengr
Nov 13 '13 at 16:06

add a comment |

101

Pass keyword arguments to flask.jsonify and they will be output as a JSON object.

@app.route('/_get_current_user')

def get_current_user():

    return jsonify(

        username=g.user.username,

        email=g.user.email,

        id=g.user.id

    )

{

    "username": "admin",

    "email": "admin@localhost",

    "id": 42

}

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

Pass keyword arguments to flask.jsonify and they will be output as a JSON object.

@app.route('/_get_current_user')

def get_current_user():

    return jsonify(

        username=g.user.username,

        email=g.user.email,

        id=g.user.id

    )

{

    "username": "admin",

    "email": "admin@localhost",

    "id": 42

}

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

edited Jan 26 '17 at 20:30

davidism

65.8k12178191

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

answered Oct 26 '12 at 6:11

zengr

26.4k32110179

can you please elaborate me with the code to identify filename.

– Code Ninja
Oct 26 '12 at 8:23

@CodeNinja What do you mean? If you want to putput the f dict from your original code, you should do return jsonify(**f).

– Markus Unterwaditzer
Oct 30 '12 at 6:59

1

What if I want to return structure like { 'names': { 'first': 'Frank', last: 'Sinatra'}, 'age': 98} ?

– David Sergey
Nov 13 '13 at 15:39

3

It's just a nested dict. Try this: jsonify({ 'names': { 'first': 'Frank', 'last': 'Sinatra'}, 'age': 98})

– zengr
Nov 13 '13 at 16:06

add a comment |

can you please elaborate me with the code to identify filename.

– Code Ninja
Oct 26 '12 at 8:23

@CodeNinja What do you mean? If you want to putput the f dict from your original code, you should do return jsonify(**f).

– Markus Unterwaditzer
Oct 30 '12 at 6:59

1

What if I want to return structure like { 'names': { 'first': 'Frank', last: 'Sinatra'}, 'age': 98} ?

– David Sergey
Nov 13 '13 at 15:39

3

It's just a nested dict. Try this: jsonify({ 'names': { 'first': 'Frank', 'last': 'Sinatra'}, 'age': 98})

– zengr
Nov 13 '13 at 16:06

can you please elaborate me with the code to identify filename.

– Code Ninja
Oct 26 '12 at 8:23

@CodeNinja What do you mean? If you want to putput the f dict from your original code, you should do return jsonify(**f).

– Markus Unterwaditzer
Oct 30 '12 at 6:59

What if I want to return structure like { 'names': { 'first': 'Frank', last: 'Sinatra'}, 'age': 98} ?

– David Sergey
Nov 13 '13 at 15:39

It's just a nested dict. Try this: jsonify({ 'names': { 'first': 'Frank', 'last': 'Sinatra'}, 'age': 98})

– zengr
Nov 13 '13 at 16:06

add a comment |

If you don't want to use jsonify for some reason, you can do what it does manually. Call flask.json.dumps to create JSON data, then return a response with the application/json content type.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        mimetype='application/json'

    )

    return response

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

import json (instead of from flask ...) works just as well.

– Uri Goren
Jan 11 at 18:03

add a comment |

If you don't want to use jsonify for some reason, you can do what it does manually. Call flask.json.dumps to create JSON data, then return a response with the application/json content type.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        mimetype='application/json'

    )

    return response

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

import json (instead of from flask ...) works just as well.

– Uri Goren
Jan 11 at 18:03

add a comment |

If you don't want to use jsonify for some reason, you can do what it does manually. Call flask.json.dumps to create JSON data, then return a response with the application/json content type.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        mimetype='application/json'

    )

    return response

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

If you don't want to use jsonify for some reason, you can do what it does manually. Call flask.json.dumps to create JSON data, then return a response with the application/json content type.

from flask import json



@app.route('/summary')

def summary():

    data = make_summary()

    response = app.response_class(

        response=json.dumps(data),

        mimetype='application/json'

    )

    return response

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

edited Jul 25 '18 at 23:15

davidism

65.8k12178191

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

answered Jan 23 '18 at 19:54

Anthony Awuley

64469

import json (instead of from flask ...) works just as well.

– Uri Goren
Jan 11 at 18:03

add a comment |

import json (instead of from flask ...) works just as well.

– Uri Goren
Jan 11 at 18:03

import json (instead of from flask ...) works just as well.

– Uri Goren
Jan 11 at 18:03

add a comment |

If you want to analyze a file uploaded by the user, the Flask quickstart shows how to get files from users and access them. Get the file from request.files and pass it to the summary function.

from flask import request, jsonify

from werkzeug import secure_filename



@app.route('/summary', methods=['GET', 'POST'])

def summary():

    if request.method == 'POST':

        csv = request.files['data']

        return jsonify(

            summary=make_summary(csv),

            csv_name=secure_filename(csv.filename)

        )



    return render_template('submit_data.html')

Replace the 'data' key for request.files with the name of the file input in your HTML form.

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

answered Dec 5 '13 at 16:44

teechap

54656

add a comment |

If you want to analyze a file uploaded by the user, the Flask quickstart shows how to get files from users and access them. Get the file from request.files and pass it to the summary function.

from flask import request, jsonify

from werkzeug import secure_filename



@app.route('/summary', methods=['GET', 'POST'])

def summary():

    if request.method == 'POST':

        csv = request.files['data']

        return jsonify(

            summary=make_summary(csv),

            csv_name=secure_filename(csv.filename)

        )



    return render_template('submit_data.html')

Replace the 'data' key for request.files with the name of the file input in your HTML form.

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

answered Dec 5 '13 at 16:44

teechap

54656

add a comment |

If you want to analyze a file uploaded by the user, the Flask quickstart shows how to get files from users and access them. Get the file from request.files and pass it to the summary function.

from flask import request, jsonify

from werkzeug import secure_filename



@app.route('/summary', methods=['GET', 'POST'])

def summary():

    if request.method == 'POST':

        csv = request.files['data']

        return jsonify(

            summary=make_summary(csv),

            csv_name=secure_filename(csv.filename)

        )



    return render_template('submit_data.html')

Replace the 'data' key for request.files with the name of the file input in your HTML form.

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

answered Dec 5 '13 at 16:44

teechap

54656

If you want to analyze a file uploaded by the user, the Flask quickstart shows how to get files from users and access them. Get the file from request.files and pass it to the summary function.

from flask import request, jsonify

from werkzeug import secure_filename



@app.route('/summary', methods=['GET', 'POST'])

def summary():

    if request.method == 'POST':

        csv = request.files['data']

        return jsonify(

            summary=make_summary(csv),

            csv_name=secure_filename(csv.filename)

        )



    return render_template('submit_data.html')

Replace the 'data' key for request.files with the name of the file input in your HTML form.

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

answered Dec 5 '13 at 16:44

teechap

54656

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

edited Jan 26 '17 at 16:58

davidism

65.8k12178191

answered Dec 5 '13 at 16:44

teechap

54656

answered Dec 5 '13 at 16:44

teechap

54656

answered Dec 5 '13 at 16:44

teechap

54656

add a comment |

You can write a decorator to convert the return value from a view function into a JSON response.

def return_json(view):

    @functools.wraps(view)

    def wrapped_view(**values):

        return jsonify(view(**values))

    return wrapped_view





@app.route('/test/<arg>')

@return_json

def test(arg):

    if arg == 'list':

        return [1, 2, 3]

    elif arg == 'dict':

        return {'a': 1, 'b': 2}

    elif arg == 'bool':

        return True

    return 'non of them'

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

answered Jun 10 '16 at 13:37

iman

9,22162421

1

@return_json doesn't work with status codes.

– Roman Orac
Sep 24 '18 at 9:11

add a comment |

You can write a decorator to convert the return value from a view function into a JSON response.

def return_json(view):

    @functools.wraps(view)

    def wrapped_view(**values):

        return jsonify(view(**values))

    return wrapped_view





@app.route('/test/<arg>')

@return_json

def test(arg):

    if arg == 'list':

        return [1, 2, 3]

    elif arg == 'dict':

        return {'a': 1, 'b': 2}

    elif arg == 'bool':

        return True

    return 'non of them'

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

answered Jun 10 '16 at 13:37

iman

9,22162421

1

@return_json doesn't work with status codes.

– Roman Orac
Sep 24 '18 at 9:11

add a comment |

You can write a decorator to convert the return value from a view function into a JSON response.

def return_json(view):

    @functools.wraps(view)

    def wrapped_view(**values):

        return jsonify(view(**values))

    return wrapped_view





@app.route('/test/<arg>')

@return_json

def test(arg):

    if arg == 'list':

        return [1, 2, 3]

    elif arg == 'dict':

        return {'a': 1, 'b': 2}

    elif arg == 'bool':

        return True

    return 'non of them'

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

answered Jun 10 '16 at 13:37

iman

9,22162421

You can write a decorator to convert the return value from a view function into a JSON response.

def return_json(view):

    @functools.wraps(view)

    def wrapped_view(**values):

        return jsonify(view(**values))

    return wrapped_view





@app.route('/test/<arg>')

@return_json

def test(arg):

    if arg == 'list':

        return [1, 2, 3]

    elif arg == 'dict':

        return {'a': 1, 'b': 2}

    elif arg == 'bool':

        return True

    return 'non of them'

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

answered Jun 10 '16 at 13:37

iman

9,22162421

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

edited Jul 25 '18 at 23:13

davidism

65.8k12178191

answered Jun 10 '16 at 13:37

iman

9,22162421

answered Jun 10 '16 at 13:37

iman

9,22162421

answered Jun 10 '16 at 13:37

iman

9,22162421

1

@return_json doesn't work with status codes.

– Roman Orac
Sep 24 '18 at 9:11

add a comment |

1

@return_json doesn't work with status codes.

– Roman Orac
Sep 24 '18 at 9:11

@return_json doesn't work with status codes.

– Roman Orac
Sep 24 '18 at 9:11

add a comment |

Prior to Flask 0.11, jsonfiy would not allow returning an array directly. Instead, pass the list as a keyword argument.

@app.route('/get_records')

def get_records():

    results = [

        {

          "rec_create_date": "12 Jun 2016",

          "rec_dietary_info": "nothing",

          "rec_dob": "01 Apr 1988",

          "rec_first_name": "New",

          "rec_last_name": "Guy",

        },

        {

          "rec_create_date": "1 Apr 2016",

          "rec_dietary_info": "Nut allergy",

          "rec_dob": "01 Feb 1988",

          "rec_first_name": "Old",

          "rec_last_name": "Guy",

        },

    ]

    return jsonify(results=list)

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

answered Jun 26 '16 at 15:42

mania_device

11517

add a comment |

Prior to Flask 0.11, jsonfiy would not allow returning an array directly. Instead, pass the list as a keyword argument.

@app.route('/get_records')

def get_records():

    results = [

        {

          "rec_create_date": "12 Jun 2016",

          "rec_dietary_info": "nothing",

          "rec_dob": "01 Apr 1988",

          "rec_first_name": "New",

          "rec_last_name": "Guy",

        },

        {

          "rec_create_date": "1 Apr 2016",

          "rec_dietary_info": "Nut allergy",

          "rec_dob": "01 Feb 1988",

          "rec_first_name": "Old",

          "rec_last_name": "Guy",

        },

    ]

    return jsonify(results=list)

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

answered Jun 26 '16 at 15:42

mania_device

11517

add a comment |

Prior to Flask 0.11, jsonfiy would not allow returning an array directly. Instead, pass the list as a keyword argument.

@app.route('/get_records')

def get_records():

    results = [

        {

          "rec_create_date": "12 Jun 2016",

          "rec_dietary_info": "nothing",

          "rec_dob": "01 Apr 1988",

          "rec_first_name": "New",

          "rec_last_name": "Guy",

        },

        {

          "rec_create_date": "1 Apr 2016",

          "rec_dietary_info": "Nut allergy",

          "rec_dob": "01 Feb 1988",

          "rec_first_name": "Old",

          "rec_last_name": "Guy",

        },

    ]

    return jsonify(results=list)

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

answered Jun 26 '16 at 15:42

mania_device

11517

Prior to Flask 0.11, jsonfiy would not allow returning an array directly. Instead, pass the list as a keyword argument.

@app.route('/get_records')

def get_records():

    results = [

        {

          "rec_create_date": "12 Jun 2016",

          "rec_dietary_info": "nothing",

          "rec_dob": "01 Apr 1988",

          "rec_first_name": "New",

          "rec_last_name": "Guy",

        },

        {

          "rec_create_date": "1 Apr 2016",

          "rec_dietary_info": "Nut allergy",

          "rec_dob": "01 Feb 1988",

          "rec_first_name": "Old",

          "rec_last_name": "Guy",

        },

    ]

    return jsonify(results=list)

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

answered Jun 26 '16 at 15:42

mania_device

11517

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

edited Jul 25 '18 at 23:10

davidism

65.8k12178191

answered Jun 26 '16 at 15:42

mania_device

11517

answered Jun 26 '16 at 15:42

mania_device

11517

answered Jun 26 '16 at 15:42

mania_device

11517

add a comment |

-2

Like said previously jsonify is the best way or you could also use Flask-responses' package at https://github.com/Parkayun/flask-responses

@app.route("/json")

def hello():

    return json_response(your_dict, status_code=201)

edited May 3 '16 at 16:56

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

add a comment |

-2

Like said previously jsonify is the best way or you could also use Flask-responses' package at https://github.com/Parkayun/flask-responses

@app.route("/json")

def hello():

    return json_response(your_dict, status_code=201)

edited May 3 '16 at 16:56

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

add a comment |

-2

Like said previously jsonify is the best way or you could also use Flask-responses' package at https://github.com/Parkayun/flask-responses

@app.route("/json")

def hello():

    return json_response(your_dict, status_code=201)

edited May 3 '16 at 16:56

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

Like said previously jsonify is the best way or you could also use Flask-responses' package at https://github.com/Parkayun/flask-responses

@app.route("/json")

def hello():

    return json_response(your_dict, status_code=201)

edited May 3 '16 at 16:56

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

edited May 3 '16 at 16:56

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

answered Jul 28 '15 at 19:05

Papouche Guinslyzinho

2,40742753

add a comment |

-2

You can try this approach:

from flask import jsonify, Flask



app = Flask(__name__)



@app.route("/summary")

def summary():

    d = make_summary()

    return jsonify(d)

edited Jan 21 at 10:32

iamdanchiv

2,67642432

answered Jan 21 at 9:49

theophilus okoye

add a comment |

-2

You can try this approach:

from flask import jsonify, Flask



app = Flask(__name__)



@app.route("/summary")

def summary():

    d = make_summary()

    return jsonify(d)

edited Jan 21 at 10:32

iamdanchiv

2,67642432

answered Jan 21 at 9:49

theophilus okoye

add a comment |

-2

You can try this approach:

from flask import jsonify, Flask



app = Flask(__name__)



@app.route("/summary")

def summary():

    d = make_summary()

    return jsonify(d)

edited Jan 21 at 10:32

iamdanchiv

2,67642432

answered Jan 21 at 9:49

theophilus okoye

You can try this approach:

from flask import jsonify, Flask



app = Flask(__name__)



@app.route("/summary")

def summary():

    d = make_summary()

    return jsonify(d)

edited Jan 21 at 10:32

iamdanchiv

2,67642432

answered Jan 21 at 9:49

theophilus okoye

edited Jan 21 at 10:32

iamdanchiv

2,67642432

edited Jan 21 at 10:32

iamdanchiv

2,67642432

edited Jan 21 at 10:32

iamdanchiv

2,67642432

answered Jan 21 at 9:49

theophilus okoye

answered Jan 21 at 9:49

theophilus okoye

answered Jan 21 at 9:49

theophilus okoye

add a comment |

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