Two sides of a triangle have equal length if the angles opposite them are equal. Is this true? If so, what is...
$begingroup$
I am told that two sides of a triangle have equal length if the angles opposite them are equal.
Is this true? If so, I would appreciate it if someone could tell me what the theorem called.
Thank you.
geometry
$endgroup$
add a comment |
$begingroup$
I am told that two sides of a triangle have equal length if the angles opposite them are equal.
Is this true? If so, I would appreciate it if someone could tell me what the theorem called.
Thank you.
geometry
$endgroup$
1
$begingroup$
It defines an isosceles triangle
$endgroup$
– imranfat
Nov 24 '16 at 4:24
$begingroup$
@imranfat I see. Is there a name for this theorem?
$endgroup$
– The Pointer
Nov 24 '16 at 4:25
2
$begingroup$
That's the converse of Proposition 5 of Book 1 in Euclid's Elements. Lookup 'pons asinorum`.
$endgroup$
– dxiv
Nov 24 '16 at 4:25
1
$begingroup$
@dxiv Got it. Thank you.
$endgroup$
– The Pointer
Nov 24 '16 at 4:26
1
$begingroup$
It isn't really named per se. People didn't really name things back then. Euclid just compiled 90% of the knowledge of the geometry he knew from Egypt and other places around Greece. The only thing truly 100% credible to him was the idea of the postulates and his proofs using them. He may have made a few propositions of his own, but I imagine the first 7 or 8 were already known to people. Just pointing that out.
$endgroup$
– The Great Duck
Nov 24 '16 at 4:30
add a comment |
$begingroup$
I am told that two sides of a triangle have equal length if the angles opposite them are equal.
Is this true? If so, I would appreciate it if someone could tell me what the theorem called.
Thank you.
geometry
$endgroup$
I am told that two sides of a triangle have equal length if the angles opposite them are equal.
Is this true? If so, I would appreciate it if someone could tell me what the theorem called.
Thank you.
geometry
geometry
asked Nov 24 '16 at 4:23
The PointerThe Pointer
2,64421638
2,64421638
1
$begingroup$
It defines an isosceles triangle
$endgroup$
– imranfat
Nov 24 '16 at 4:24
$begingroup$
@imranfat I see. Is there a name for this theorem?
$endgroup$
– The Pointer
Nov 24 '16 at 4:25
2
$begingroup$
That's the converse of Proposition 5 of Book 1 in Euclid's Elements. Lookup 'pons asinorum`.
$endgroup$
– dxiv
Nov 24 '16 at 4:25
1
$begingroup$
@dxiv Got it. Thank you.
$endgroup$
– The Pointer
Nov 24 '16 at 4:26
1
$begingroup$
It isn't really named per se. People didn't really name things back then. Euclid just compiled 90% of the knowledge of the geometry he knew from Egypt and other places around Greece. The only thing truly 100% credible to him was the idea of the postulates and his proofs using them. He may have made a few propositions of his own, but I imagine the first 7 or 8 were already known to people. Just pointing that out.
$endgroup$
– The Great Duck
Nov 24 '16 at 4:30
add a comment |
1
$begingroup$
It defines an isosceles triangle
$endgroup$
– imranfat
Nov 24 '16 at 4:24
$begingroup$
@imranfat I see. Is there a name for this theorem?
$endgroup$
– The Pointer
Nov 24 '16 at 4:25
2
$begingroup$
That's the converse of Proposition 5 of Book 1 in Euclid's Elements. Lookup 'pons asinorum`.
$endgroup$
– dxiv
Nov 24 '16 at 4:25
1
$begingroup$
@dxiv Got it. Thank you.
$endgroup$
– The Pointer
Nov 24 '16 at 4:26
1
$begingroup$
It isn't really named per se. People didn't really name things back then. Euclid just compiled 90% of the knowledge of the geometry he knew from Egypt and other places around Greece. The only thing truly 100% credible to him was the idea of the postulates and his proofs using them. He may have made a few propositions of his own, but I imagine the first 7 or 8 were already known to people. Just pointing that out.
$endgroup$
– The Great Duck
Nov 24 '16 at 4:30
1
1
$begingroup$
It defines an isosceles triangle
$endgroup$
– imranfat
Nov 24 '16 at 4:24
$begingroup$
It defines an isosceles triangle
$endgroup$
– imranfat
Nov 24 '16 at 4:24
$begingroup$
@imranfat I see. Is there a name for this theorem?
$endgroup$
– The Pointer
Nov 24 '16 at 4:25
$begingroup$
@imranfat I see. Is there a name for this theorem?
$endgroup$
– The Pointer
Nov 24 '16 at 4:25
2
2
$begingroup$
That's the converse of Proposition 5 of Book 1 in Euclid's Elements. Lookup 'pons asinorum`.
$endgroup$
– dxiv
Nov 24 '16 at 4:25
$begingroup$
That's the converse of Proposition 5 of Book 1 in Euclid's Elements. Lookup 'pons asinorum`.
$endgroup$
– dxiv
Nov 24 '16 at 4:25
1
1
$begingroup$
@dxiv Got it. Thank you.
$endgroup$
– The Pointer
Nov 24 '16 at 4:26
$begingroup$
@dxiv Got it. Thank you.
$endgroup$
– The Pointer
Nov 24 '16 at 4:26
1
1
$begingroup$
It isn't really named per se. People didn't really name things back then. Euclid just compiled 90% of the knowledge of the geometry he knew from Egypt and other places around Greece. The only thing truly 100% credible to him was the idea of the postulates and his proofs using them. He may have made a few propositions of his own, but I imagine the first 7 or 8 were already known to people. Just pointing that out.
$endgroup$
– The Great Duck
Nov 24 '16 at 4:30
$begingroup$
It isn't really named per se. People didn't really name things back then. Euclid just compiled 90% of the knowledge of the geometry he knew from Egypt and other places around Greece. The only thing truly 100% credible to him was the idea of the postulates and his proofs using them. He may have made a few propositions of his own, but I imagine the first 7 or 8 were already known to people. Just pointing that out.
$endgroup$
– The Great Duck
Nov 24 '16 at 4:30
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
It's an immediate consequence of the ASA congruence theorem (or axiom?): A triangle with equal angles at $A$ and $B$ is congruent to itself under $(A,B,C)mapsto(B,A,C)$, hence $|AC|=|BC|$.
$endgroup$
add a comment |
$begingroup$
It is called "sides opposite equal angles".
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2028317%2ftwo-sides-of-a-triangle-have-equal-length-if-the-angles-opposite-them-are-equal%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It's an immediate consequence of the ASA congruence theorem (or axiom?): A triangle with equal angles at $A$ and $B$ is congruent to itself under $(A,B,C)mapsto(B,A,C)$, hence $|AC|=|BC|$.
$endgroup$
add a comment |
$begingroup$
It's an immediate consequence of the ASA congruence theorem (or axiom?): A triangle with equal angles at $A$ and $B$ is congruent to itself under $(A,B,C)mapsto(B,A,C)$, hence $|AC|=|BC|$.
$endgroup$
add a comment |
$begingroup$
It's an immediate consequence of the ASA congruence theorem (or axiom?): A triangle with equal angles at $A$ and $B$ is congruent to itself under $(A,B,C)mapsto(B,A,C)$, hence $|AC|=|BC|$.
$endgroup$
It's an immediate consequence of the ASA congruence theorem (or axiom?): A triangle with equal angles at $A$ and $B$ is congruent to itself under $(A,B,C)mapsto(B,A,C)$, hence $|AC|=|BC|$.
answered Nov 24 '16 at 15:43


Christian BlatterChristian Blatter
175k8115327
175k8115327
add a comment |
add a comment |
$begingroup$
It is called "sides opposite equal angles".
$endgroup$
add a comment |
$begingroup$
It is called "sides opposite equal angles".
$endgroup$
add a comment |
$begingroup$
It is called "sides opposite equal angles".
$endgroup$
It is called "sides opposite equal angles".
answered Nov 24 '16 at 15:13


MickMick
11.9k21641
11.9k21641
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2028317%2ftwo-sides-of-a-triangle-have-equal-length-if-the-angles-opposite-them-are-equal%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
It defines an isosceles triangle
$endgroup$
– imranfat
Nov 24 '16 at 4:24
$begingroup$
@imranfat I see. Is there a name for this theorem?
$endgroup$
– The Pointer
Nov 24 '16 at 4:25
2
$begingroup$
That's the converse of Proposition 5 of Book 1 in Euclid's Elements. Lookup 'pons asinorum`.
$endgroup$
– dxiv
Nov 24 '16 at 4:25
1
$begingroup$
@dxiv Got it. Thank you.
$endgroup$
– The Pointer
Nov 24 '16 at 4:26
1
$begingroup$
It isn't really named per se. People didn't really name things back then. Euclid just compiled 90% of the knowledge of the geometry he knew from Egypt and other places around Greece. The only thing truly 100% credible to him was the idea of the postulates and his proofs using them. He may have made a few propositions of his own, but I imagine the first 7 or 8 were already known to people. Just pointing that out.
$endgroup$
– The Great Duck
Nov 24 '16 at 4:30