Mixing
What is the difference between [ and ) while specifying a set of numbers?
0
$begingroup$
I have a text on Algorithms which has these 2 lines in it -
random double value in [a,b)
random int value in [0..N)
What do the notations [ and ) mean?
What's the difference between the 2 lines?
linear-algebra arithmetic
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
$endgroup$
|
show 1 more comment
0
$begingroup$
I have a text on Algorithms which has these 2 lines in it -
random double value in [a,b)
random int value in [0..N)
What do the notations [ and ) mean?
What's the difference between the 2 lines?
linear-algebra arithmetic
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
$endgroup$
1
$begingroup$
See: here
$endgroup$
– StackTD
Jan 24 at 10:20
$begingroup$
$[a,b]$ includes both ends in the interval, $(a,b)$ includes neither, $[a,b)$ includes $a$ but not $b$, while $(a,b]$ includes $b$ but not $a$. Some people instead write $[a,b]$ and $]a,b[$ and $[a,b[$ and $]a,b]$ respectively
$endgroup$
– Henry
Jan 24 at 10:28
$begingroup$
The key difference between your two lines are the words double (double-precision floating-point type, so not necessarily an integer) and int (integer type).
$endgroup$
– Henry
Jan 24 at 10:30
$begingroup$
I meant, is there any significance of the '..' between the ends of the intervals? (in the 2nd line)
$endgroup$
– Karthik Bhat
Jan 24 at 10:44
$begingroup$
As you might guess,[0..N)probably means the same as ${0,1,dots,N-1}$.
$endgroup$
– Somos
Jan 24 at 11:16
|
show 1 more comment
0
0
0
$begingroup$
I have a text on Algorithms which has these 2 lines in it -
random double value in [a,b)
random int value in [0..N)
What do the notations [ and ) mean?
What's the difference between the 2 lines?
linear-algebra arithmetic
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
$endgroup$
I have a text on Algorithms which has these 2 lines in it -
random double value in [a,b)
random int value in [0..N)
What do the notations [ and ) mean?
What's the difference between the 2 lines?
linear-algebra arithmetic
linear-algebra arithmetic
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
edited Jan 24 at 12:29
Andrés E. Caicedo
65.7k8160250
65.7k8160250
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
asked Jan 24 at 10:18
Karthik BhatKarthik Bhat
133
133
1
$begingroup$
See: here
$endgroup$
– StackTD
Jan 24 at 10:20
$begingroup$
$[a,b]$ includes both ends in the interval, $(a,b)$ includes neither, $[a,b)$ includes $a$ but not $b$, while $(a,b]$ includes $b$ but not $a$. Some people instead write $[a,b]$ and $]a,b[$ and $[a,b[$ and $]a,b]$ respectively
$endgroup$
– Henry
Jan 24 at 10:28
$begingroup$
The key difference between your two lines are the words double (double-precision floating-point type, so not necessarily an integer) and int (integer type).
$endgroup$
– Henry
Jan 24 at 10:30
$begingroup$
I meant, is there any significance of the '..' between the ends of the intervals? (in the 2nd line)
$endgroup$
– Karthik Bhat
Jan 24 at 10:44
$begingroup$
As you might guess,[0..N)probably means the same as ${0,1,dots,N-1}$.
$endgroup$
– Somos
Jan 24 at 11:16
|
show 1 more comment
1
$begingroup$
See: here
$endgroup$
– StackTD
Jan 24 at 10:20
$begingroup$
$[a,b]$ includes both ends in the interval, $(a,b)$ includes neither, $[a,b)$ includes $a$ but not $b$, while $(a,b]$ includes $b$ but not $a$. Some people instead write $[a,b]$ and $]a,b[$ and $[a,b[$ and $]a,b]$ respectively
$endgroup$
– Henry
Jan 24 at 10:28
$begingroup$
The key difference between your two lines are the words double (double-precision floating-point type, so not necessarily an integer) and int (integer type).
$endgroup$
– Henry
Jan 24 at 10:30
$begingroup$
I meant, is there any significance of the '..' between the ends of the intervals? (in the 2nd line)
$endgroup$
– Karthik Bhat
Jan 24 at 10:44
$begingroup$
As you might guess,[0..N)probably means the same as ${0,1,dots,N-1}$.
$endgroup$
– Somos
Jan 24 at 11:16
1
1
$begingroup$
See: here
$endgroup$
– StackTD
Jan 24 at 10:20
$begingroup$
See: here
$endgroup$
– StackTD
Jan 24 at 10:20
$begingroup$
$[a,b]$ includes both ends in the interval, $(a,b)$ includes neither, $[a,b)$ includes $a$ but not $b$, while $(a,b]$ includes $b$ but not $a$. Some people instead write $[a,b]$ and $]a,b[$ and $[a,b[$ and $]a,b]$ respectively
$endgroup$
– Henry
Jan 24 at 10:28
$begingroup$
$[a,b]$ includes both ends in the interval, $(a,b)$ includes neither, $[a,b)$ includes $a$ but not $b$, while $(a,b]$ includes $b$ but not $a$. Some people instead write $[a,b]$ and $]a,b[$ and $[a,b[$ and $]a,b]$ respectively
$endgroup$
– Henry
Jan 24 at 10:28
$begingroup$
The key difference between your two lines are the words double (double-precision floating-point type, so not necessarily an integer) and int (integer type).
$endgroup$
– Henry
Jan 24 at 10:30
$begingroup$
The key difference between your two lines are the words double (double-precision floating-point type, so not necessarily an integer) and int (integer type).
$endgroup$
– Henry
Jan 24 at 10:30
$begingroup$
I meant, is there any significance of the '..' between the ends of the intervals? (in the 2nd line)
$endgroup$
– Karthik Bhat
Jan 24 at 10:44
$begingroup$
I meant, is there any significance of the '..' between the ends of the intervals? (in the 2nd line)
$endgroup$
– Karthik Bhat
Jan 24 at 10:44
$begingroup$
As you might guess,
[0..N) probably means the same as ${0,1,dots,N-1}$.$endgroup$
– Somos
Jan 24 at 11:16
$begingroup$
As you might guess,
[0..N) probably means the same as ${0,1,dots,N-1}$.$endgroup$
– Somos
Jan 24 at 11:16
|
show 1 more comment
1 Answer
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$begingroup$
$(a, b)$ means all $x$ such that $a<x<b$.
$(a,b]$ means all $x$ such that $a<xle b$.
$[a, b)$ ... such that $ale x <b$.
$[a, b]$ ... $ale x le b$
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
$endgroup$
add a comment |
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$begingroup$
$(a, b)$ means all $x$ such that $a<x<b$.
$(a,b]$ means all $x$ such that $a<xle b$.
$[a, b)$ ... such that $ale x <b$.
$[a, b]$ ... $ale x le b$
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
$endgroup$
add a comment |
2
$begingroup$
$(a, b)$ means all $x$ such that $a<x<b$.
$(a,b]$ means all $x$ such that $a<xle b$.
$[a, b)$ ... such that $ale x <b$.
$[a, b]$ ... $ale x le b$
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
$endgroup$
add a comment |
2
2
2
$begingroup$
$(a, b)$ means all $x$ such that $a<x<b$.
$(a,b]$ means all $x$ such that $a<xle b$.
$[a, b)$ ... such that $ale x <b$.
$[a, b]$ ... $ale x le b$
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
$endgroup$
$(a, b)$ means all $x$ such that $a<x<b$.
$(a,b]$ means all $x$ such that $a<xle b$.
$[a, b)$ ... such that $ale x <b$.
$[a, b]$ ... $ale x le b$
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
edited Jan 24 at 14:04
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
answered Jan 24 at 10:28
Bernard HurleyBernard Hurley
1787
1787
add a comment |
add a comment |
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1
$begingroup$
See: here
$endgroup$
– StackTD
Jan 24 at 10:20
$begingroup$
$[a,b]$ includes both ends in the interval, $(a,b)$ includes neither, $[a,b)$ includes $a$ but not $b$, while $(a,b]$ includes $b$ but not $a$. Some people instead write $[a,b]$ and $]a,b[$ and $[a,b[$ and $]a,b]$ respectively
$endgroup$
– Henry
Jan 24 at 10:28
$begingroup$
The key difference between your two lines are the words double (double-precision floating-point type, so not necessarily an integer) and int (integer type).
$endgroup$
– Henry
Jan 24 at 10:30
$begingroup$
I meant, is there any significance of the '..' between the ends of the intervals? (in the 2nd line)
$endgroup$
– Karthik Bhat
Jan 24 at 10:44
$begingroup$
As you might guess,
[0..N)probably means the same as ${0,1,dots,N-1}$.$endgroup$
– Somos
Jan 24 at 11:16