Why isn't it letting me convert a list into a string?

I am using BeautifulSoup to scrape the Wikipedia information box and am trying export it into a table

I want to convert my list into a BeatifulSoup in order to be able to use .find_all and .find , to look for the nested tags, but as i did not find anything online to convert, i decided to convert it into a string and then try to convert the string into beautiful soup

When I try to .join my string I get the error:

TypeError: sequence item 0: expected str instance, Tag found.

I have also tried

print (u'').join(unicode(row1) for fow1 in link)

print (u'').join(row1.stripped_strings)

but these give the error

AttributeError: 'NoneType' object has no attribute 'join'

my_table = soup.find('table',{'class':'infobox vcard'})



records =  



for my_tables in my_table:

    row1 = my_table.find_all('th',{'scope':'row'})

    print (row1)



    print()



    row2 = my_table.find_all('span')

    print (row2)



html = ''.join(row1)

It should convert the list into a string

edited Jan 1 at 12:21

HakunaMaData

730418

asked Jan 1 at 4:33

Remmerton

164

2

Print returns none

– dennmat
Jan 1 at 4:57

Provide the url you are scraping and your expected the output.

– salman wahed
Jan 1 at 5:05

1

The errors are very descriptive. Look at the beautiful soup docs. You have a list of Tags not strings. And in the other case you're trying to call join on the return of the print method.

– dennmat
Jan 1 at 5:32

In your code above "row2" is a list of BeautifulSoup Tag elements. You can get the displayed text for the elements with for elem in row2: print(elem.text) and the HTML source with for elem in row2: print(str(elem)) Maybe this helps.

– Hubert
Jan 1 at 7:30

add a comment |

I am using BeautifulSoup to scrape the Wikipedia information box and am trying export it into a table

When I try to .join my string I get the error:

TypeError: sequence item 0: expected str instance, Tag found.

I have also tried

print (u'').join(unicode(row1) for fow1 in link)

print (u'').join(row1.stripped_strings)

but these give the error

AttributeError: 'NoneType' object has no attribute 'join'

my_table = soup.find('table',{'class':'infobox vcard'})



records =  



for my_tables in my_table:

    row1 = my_table.find_all('th',{'scope':'row'})

    print (row1)



    print()



    row2 = my_table.find_all('span')

    print (row2)



html = ''.join(row1)

It should convert the list into a string

edited Jan 1 at 12:21

HakunaMaData

730418

asked Jan 1 at 4:33

Remmerton

164

2

Print returns none

– dennmat
Jan 1 at 4:57

Provide the url you are scraping and your expected the output.

– salman wahed
Jan 1 at 5:05

1

The errors are very descriptive. Look at the beautiful soup docs. You have a list of Tags not strings. And in the other case you're trying to call join on the return of the print method.

– dennmat
Jan 1 at 5:32

In your code above "row2" is a list of BeautifulSoup Tag elements. You can get the displayed text for the elements with for elem in row2: print(elem.text) and the HTML source with for elem in row2: print(str(elem)) Maybe this helps.

– Hubert
Jan 1 at 7:30

add a comment |

I am using BeautifulSoup to scrape the Wikipedia information box and am trying export it into a table

When I try to .join my string I get the error:

TypeError: sequence item 0: expected str instance, Tag found.

I have also tried

print (u'').join(unicode(row1) for fow1 in link)

print (u'').join(row1.stripped_strings)

but these give the error

AttributeError: 'NoneType' object has no attribute 'join'

my_table = soup.find('table',{'class':'infobox vcard'})



records =  



for my_tables in my_table:

    row1 = my_table.find_all('th',{'scope':'row'})

    print (row1)



    print()



    row2 = my_table.find_all('span')

    print (row2)



html = ''.join(row1)

It should convert the list into a string

edited Jan 1 at 12:21

HakunaMaData

730418

asked Jan 1 at 4:33

Remmerton

164

I am using BeautifulSoup to scrape the Wikipedia information box and am trying export it into a table

When I try to .join my string I get the error:

TypeError: sequence item 0: expected str instance, Tag found.

I have also tried

print (u'').join(unicode(row1) for fow1 in link)

print (u'').join(row1.stripped_strings)

but these give the error

AttributeError: 'NoneType' object has no attribute 'join'

my_table = soup.find('table',{'class':'infobox vcard'})



records =  



for my_tables in my_table:

    row1 = my_table.find_all('th',{'scope':'row'})

    print (row1)



    print()



    row2 = my_table.find_all('span')

    print (row2)



html = ''.join(row1)

It should convert the list into a string

python beautifulsoup wikipedia

edited Jan 1 at 12:21

HakunaMaData

730418

asked Jan 1 at 4:33

Remmerton

164

edited Jan 1 at 12:21

HakunaMaData

730418

asked Jan 1 at 4:33

Remmerton

164

edited Jan 1 at 12:21

HakunaMaData

730418

edited Jan 1 at 12:21

HakunaMaData

730418

edited Jan 1 at 12:21

HakunaMaData

730418

asked Jan 1 at 4:33

Remmerton

164

asked Jan 1 at 4:33

Remmerton

164

asked Jan 1 at 4:33

Remmerton

164

2

Print returns none

– dennmat
Jan 1 at 4:57

Provide the url you are scraping and your expected the output.

– salman wahed
Jan 1 at 5:05

1

The errors are very descriptive. Look at the beautiful soup docs. You have a list of Tags not strings. And in the other case you're trying to call join on the return of the print method.

– dennmat
Jan 1 at 5:32

In your code above "row2" is a list of BeautifulSoup Tag elements. You can get the displayed text for the elements with for elem in row2: print(elem.text) and the HTML source with for elem in row2: print(str(elem)) Maybe this helps.

– Hubert
Jan 1 at 7:30

add a comment |

2

Print returns none

– dennmat
Jan 1 at 4:57

Provide the url you are scraping and your expected the output.

– salman wahed
Jan 1 at 5:05

1

The errors are very descriptive. Look at the beautiful soup docs. You have a list of Tags not strings. And in the other case you're trying to call join on the return of the print method.

– dennmat
Jan 1 at 5:32

In your code above "row2" is a list of BeautifulSoup Tag elements. You can get the displayed text for the elements with for elem in row2: print(elem.text) and the HTML source with for elem in row2: print(str(elem)) Maybe this helps.

– Hubert
Jan 1 at 7:30

Print returns none

– dennmat
Jan 1 at 4:57

Provide the url you are scraping and your expected the output.

– salman wahed
Jan 1 at 5:05

The errors are very descriptive. Look at the beautiful soup docs. You have a list of Tags not strings. And in the other case you're trying to call join on the return of the print method.

– dennmat
Jan 1 at 5:32

In your code above "row2" is a list of BeautifulSoup Tag elements. You can get the displayed text for the elements with for elem in row2: print(elem.text) and the HTML source with for elem in row2: print(str(elem)) Maybe this helps.

– Hubert
Jan 1 at 7:30

add a comment |

1 Answer
1

active

oldest

votes

print is no longer a statement in Python 3. It's a function. This is also the case in Python 2 if you use from __future__ import print_function Try

print(''.join(str(row1) for fow1 in link))

answered Jan 1 at 6:13

gilch

4,1851716

Thanks. I was really stuck

– Remmerton
Jan 3 at 10:30

It says I don't have enough reputation to upvote, I need at least 15 reputation, or am I doing something really wrong.

– Remmerton
Jan 4 at 0:30

@Remmerton don't worry about the upvote before you get the rep for it. You should still be able to mark an answer as accepted since you asked the question though.

– gilch
Jan 4 at 2:55

Sorry didn't see the big tick before.

– Remmerton
Jan 5 at 20:38

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

print is no longer a statement in Python 3. It's a function. This is also the case in Python 2 if you use from __future__ import print_function Try

print(''.join(str(row1) for fow1 in link))

answered Jan 1 at 6:13

gilch

4,1851716

Thanks. I was really stuck

– Remmerton
Jan 3 at 10:30

It says I don't have enough reputation to upvote, I need at least 15 reputation, or am I doing something really wrong.

– Remmerton
Jan 4 at 0:30

@Remmerton don't worry about the upvote before you get the rep for it. You should still be able to mark an answer as accepted since you asked the question though.

– gilch
Jan 4 at 2:55

Sorry didn't see the big tick before.

– Remmerton
Jan 5 at 20:38

add a comment |

print is no longer a statement in Python 3. It's a function. This is also the case in Python 2 if you use from __future__ import print_function Try

print(''.join(str(row1) for fow1 in link))

answered Jan 1 at 6:13

gilch

4,1851716

Thanks. I was really stuck

– Remmerton
Jan 3 at 10:30

It says I don't have enough reputation to upvote, I need at least 15 reputation, or am I doing something really wrong.

– Remmerton
Jan 4 at 0:30

@Remmerton don't worry about the upvote before you get the rep for it. You should still be able to mark an answer as accepted since you asked the question though.

– gilch
Jan 4 at 2:55

Sorry didn't see the big tick before.

– Remmerton
Jan 5 at 20:38

add a comment |

print is no longer a statement in Python 3. It's a function. This is also the case in Python 2 if you use from __future__ import print_function Try

print(''.join(str(row1) for fow1 in link))

answered Jan 1 at 6:13

gilch

4,1851716

print is no longer a statement in Python 3. It's a function. This is also the case in Python 2 if you use from __future__ import print_function Try

print(''.join(str(row1) for fow1 in link))

answered Jan 1 at 6:13

gilch

4,1851716

answered Jan 1 at 6:13

gilch

4,1851716

answered Jan 1 at 6:13

gilch

4,1851716

answered Jan 1 at 6:13

gilch

4,1851716

Thanks. I was really stuck

– Remmerton
Jan 3 at 10:30

It says I don't have enough reputation to upvote, I need at least 15 reputation, or am I doing something really wrong.

– Remmerton
Jan 4 at 0:30

@Remmerton don't worry about the upvote before you get the rep for it. You should still be able to mark an answer as accepted since you asked the question though.

– gilch
Jan 4 at 2:55

Sorry didn't see the big tick before.

– Remmerton
Jan 5 at 20:38

add a comment |

Thanks. I was really stuck

– Remmerton
Jan 3 at 10:30

It says I don't have enough reputation to upvote, I need at least 15 reputation, or am I doing something really wrong.

– Remmerton
Jan 4 at 0:30

@Remmerton don't worry about the upvote before you get the rep for it. You should still be able to mark an answer as accepted since you asked the question though.

– gilch
Jan 4 at 2:55

Sorry didn't see the big tick before.

– Remmerton
Jan 5 at 20:38

Thanks. I was really stuck

– Remmerton
Jan 3 at 10:30

It says I don't have enough reputation to upvote, I need at least 15 reputation, or am I doing something really wrong.

– Remmerton
Jan 4 at 0:30

@Remmerton don't worry about the upvote before you get the rep for it. You should still be able to mark an answer as accepted since you asked the question though.

– gilch
Jan 4 at 2:55

Sorry didn't see the big tick before.

– Remmerton
Jan 5 at 20:38

add a comment |

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