Css grid layout with empty column





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







-1















I am new to css grid and I would like to know if it's possible to use it in the following scenario. I would like to create a layout containing 3 columns, and each column containing a button. In some cases, the button from the last column will not displayed (using angular ngif), but I don't want the layout to be changed (even if the last column does not contain anything, it should look the as if it was). How this be achieved?



I've tried creating 3 columns by using grid-template-columns: 1fr repeat(3, auto); but if the button in the last column is not displayed, all the other buttons are shifted a little to the right.










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  • 4





    what have you tried? post your complete code here

    – John Velasquez
    Jan 3 at 8:35


















-1















I am new to css grid and I would like to know if it's possible to use it in the following scenario. I would like to create a layout containing 3 columns, and each column containing a button. In some cases, the button from the last column will not displayed (using angular ngif), but I don't want the layout to be changed (even if the last column does not contain anything, it should look the as if it was). How this be achieved?



I've tried creating 3 columns by using grid-template-columns: 1fr repeat(3, auto); but if the button in the last column is not displayed, all the other buttons are shifted a little to the right.










share|improve this question




















  • 4





    what have you tried? post your complete code here

    – John Velasquez
    Jan 3 at 8:35














-1












-1








-1








I am new to css grid and I would like to know if it's possible to use it in the following scenario. I would like to create a layout containing 3 columns, and each column containing a button. In some cases, the button from the last column will not displayed (using angular ngif), but I don't want the layout to be changed (even if the last column does not contain anything, it should look the as if it was). How this be achieved?



I've tried creating 3 columns by using grid-template-columns: 1fr repeat(3, auto); but if the button in the last column is not displayed, all the other buttons are shifted a little to the right.










share|improve this question
















I am new to css grid and I would like to know if it's possible to use it in the following scenario. I would like to create a layout containing 3 columns, and each column containing a button. In some cases, the button from the last column will not displayed (using angular ngif), but I don't want the layout to be changed (even if the last column does not contain anything, it should look the as if it was). How this be achieved?



I've tried creating 3 columns by using grid-template-columns: 1fr repeat(3, auto); but if the button in the last column is not displayed, all the other buttons are shifted a little to the right.







css angular css3 css-grid






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edited Jan 3 at 14:12









Michael_B

158k50255363




158k50255363










asked Jan 3 at 8:30









RocshyRocshy

1,42693148




1,42693148








  • 4





    what have you tried? post your complete code here

    – John Velasquez
    Jan 3 at 8:35














  • 4





    what have you tried? post your complete code here

    – John Velasquez
    Jan 3 at 8:35








4




4





what have you tried? post your complete code here

– John Velasquez
Jan 3 at 8:35





what have you tried? post your complete code here

– John Velasquez
Jan 3 at 8:35












1 Answer
1






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oldest

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0














Because the grid template is applied to the direct children so if you have 3 columns you should have 3 direct children.
If you have a ng-if you will have only 2 children when the ng-if evaluates to false therefore I would recommend you to encapsulate this ng-if into another div so that you always have this 3 children even if the last one is empty.



for example:



<div class="my-grid">
<div>column 1</div>
<div>column 2</div>
<div>
<div ng-if="displayColumn3">column 3</div>
</div>
</div>


hope this makes sense and helps.






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    Because the grid template is applied to the direct children so if you have 3 columns you should have 3 direct children.
    If you have a ng-if you will have only 2 children when the ng-if evaluates to false therefore I would recommend you to encapsulate this ng-if into another div so that you always have this 3 children even if the last one is empty.



    for example:



    <div class="my-grid">
    <div>column 1</div>
    <div>column 2</div>
    <div>
    <div ng-if="displayColumn3">column 3</div>
    </div>
    </div>


    hope this makes sense and helps.






    share|improve this answer




























      0














      Because the grid template is applied to the direct children so if you have 3 columns you should have 3 direct children.
      If you have a ng-if you will have only 2 children when the ng-if evaluates to false therefore I would recommend you to encapsulate this ng-if into another div so that you always have this 3 children even if the last one is empty.



      for example:



      <div class="my-grid">
      <div>column 1</div>
      <div>column 2</div>
      <div>
      <div ng-if="displayColumn3">column 3</div>
      </div>
      </div>


      hope this makes sense and helps.






      share|improve this answer


























        0












        0








        0







        Because the grid template is applied to the direct children so if you have 3 columns you should have 3 direct children.
        If you have a ng-if you will have only 2 children when the ng-if evaluates to false therefore I would recommend you to encapsulate this ng-if into another div so that you always have this 3 children even if the last one is empty.



        for example:



        <div class="my-grid">
        <div>column 1</div>
        <div>column 2</div>
        <div>
        <div ng-if="displayColumn3">column 3</div>
        </div>
        </div>


        hope this makes sense and helps.






        share|improve this answer













        Because the grid template is applied to the direct children so if you have 3 columns you should have 3 direct children.
        If you have a ng-if you will have only 2 children when the ng-if evaluates to false therefore I would recommend you to encapsulate this ng-if into another div so that you always have this 3 children even if the last one is empty.



        for example:



        <div class="my-grid">
        <div>column 1</div>
        <div>column 2</div>
        <div>
        <div ng-if="displayColumn3">column 3</div>
        </div>
        </div>


        hope this makes sense and helps.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 3 at 9:52









        Didier CorronelDidier Corronel

        6018




        6018
































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