Mixing
Decoding dynamic JSON structure in swift 4
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
I have the following issue that I'm not sure how to handle.
My JSON response can look like this:
{
"data": {
"id": 7,
"token": "eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJleHAiOjE1NDY1MTU0NDMsImRhdGEiOiJ2bGFkVGVzdCIsImlhdCI6MTU0NjUwODI0M30.uwuPhlnchgBG4E8IvHvK4bB1Yj-TNDgmi7wUAiKmoVo"
},
"error": null
}
Or like this:
{
"data": [{
"id": 12
}, {
"id": 2
}, {
"id": 5
}, {
"id": 7
}],
"error": null
}
So in short the data can be either a single objet or an Array. What i have is this:
struct ApiData: Decodable {
var data: DataObject?
var error: String?
}
struct DataObject: Decodable {
var userId: Int?
enum CodingKeys: String, CodingKey {
case userId = "id"
}
}
This works fine for the first use case, but it will fail once data turns into
var data: [DataObject?]
How do I make that dynamic without duplicating code?
Edit: This is how i decode the object as well
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(_ apiData: ApiData?) -> ()) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
guard let _ = response, let data = data else {return}
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data)
completion(retreived)
} catch let decodeError as NSError {
print("Decoder error: (decodeError.localizedDescription)n")
return
}
}.resume()
}
swift decodable
edited Jan 3 at 13:06
SPatel
1,84121430
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
|
show 1 more comment
0
I have the following issue that I'm not sure how to handle.
My JSON response can look like this:
{
"data": {
"id": 7,
"token": "eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJleHAiOjE1NDY1MTU0NDMsImRhdGEiOiJ2bGFkVGVzdCIsImlhdCI6MTU0NjUwODI0M30.uwuPhlnchgBG4E8IvHvK4bB1Yj-TNDgmi7wUAiKmoVo"
},
"error": null
}
Or like this:
{
"data": [{
"id": 12
}, {
"id": 2
}, {
"id": 5
}, {
"id": 7
}],
"error": null
}
So in short the data can be either a single objet or an Array. What i have is this:
struct ApiData: Decodable {
var data: DataObject?
var error: String?
}
struct DataObject: Decodable {
var userId: Int?
enum CodingKeys: String, CodingKey {
case userId = "id"
}
}
This works fine for the first use case, but it will fail once data turns into
var data: [DataObject?]
How do I make that dynamic without duplicating code?
Edit: This is how i decode the object as well
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(_ apiData: ApiData?) -> ()) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
guard let _ = response, let data = data else {return}
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data)
completion(retreived)
} catch let decodeError as NSError {
print("Decoder error: (decodeError.localizedDescription)n")
return
}
}.resume()
}
swift decodable
edited Jan 3 at 13:06
SPatel
1,84121430
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
And what does the API send in case oferror != null?
– vadian
Jan 3 at 9:59
@vadian it sends a string, u can see that in the ApiData structure.
– CodeGeass
Jan 3 at 10:03
@RobertDresler I'm not sure i understand the question? With the help of the struct ApiData that conforms to decodable protocol
– CodeGeass
Jan 3 at 10:04
@RobertDresler i've edited the post to answer your question.
– CodeGeass
Jan 3 at 10:08
Use power of generic
– SPatel
Jan 3 at 10:11
|
show 1 more comment
0
0
0
I have the following issue that I'm not sure how to handle.
My JSON response can look like this:
{
"data": {
"id": 7,
"token": "eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJleHAiOjE1NDY1MTU0NDMsImRhdGEiOiJ2bGFkVGVzdCIsImlhdCI6MTU0NjUwODI0M30.uwuPhlnchgBG4E8IvHvK4bB1Yj-TNDgmi7wUAiKmoVo"
},
"error": null
}
Or like this:
{
"data": [{
"id": 12
}, {
"id": 2
}, {
"id": 5
}, {
"id": 7
}],
"error": null
}
So in short the data can be either a single objet or an Array. What i have is this:
struct ApiData: Decodable {
var data: DataObject?
var error: String?
}
struct DataObject: Decodable {
var userId: Int?
enum CodingKeys: String, CodingKey {
case userId = "id"
}
}
This works fine for the first use case, but it will fail once data turns into
var data: [DataObject?]
How do I make that dynamic without duplicating code?
Edit: This is how i decode the object as well
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(_ apiData: ApiData?) -> ()) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
guard let _ = response, let data = data else {return}
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data)
completion(retreived)
} catch let decodeError as NSError {
print("Decoder error: (decodeError.localizedDescription)n")
return
}
}.resume()
}
swift decodable
edited Jan 3 at 13:06
SPatel
1,84121430
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
I have the following issue that I'm not sure how to handle.
My JSON response can look like this:
{
"data": {
"id": 7,
"token": "eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJleHAiOjE1NDY1MTU0NDMsImRhdGEiOiJ2bGFkVGVzdCIsImlhdCI6MTU0NjUwODI0M30.uwuPhlnchgBG4E8IvHvK4bB1Yj-TNDgmi7wUAiKmoVo"
},
"error": null
}
Or like this:
{
"data": [{
"id": 12
}, {
"id": 2
}, {
"id": 5
}, {
"id": 7
}],
"error": null
}
So in short the data can be either a single objet or an Array. What i have is this:
struct ApiData: Decodable {
var data: DataObject?
var error: String?
}
struct DataObject: Decodable {
var userId: Int?
enum CodingKeys: String, CodingKey {
case userId = "id"
}
}
This works fine for the first use case, but it will fail once data turns into
var data: [DataObject?]
How do I make that dynamic without duplicating code?
Edit: This is how i decode the object as well
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(_ apiData: ApiData?) -> ()) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
guard let _ = response, let data = data else {return}
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data)
completion(retreived)
} catch let decodeError as NSError {
print("Decoder error: (decodeError.localizedDescription)n")
return
}
}.resume()
}
swift decodable
swift decodable
edited Jan 3 at 13:06
SPatel
1,84121430
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
edited Jan 3 at 13:06
SPatel
1,84121430
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
edited Jan 3 at 13:06
SPatel
1,84121430
edited Jan 3 at 13:06
SPatel
1,84121430
edited Jan 3 at 13:06
SPatel
1,84121430
1,84121430
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
asked Jan 3 at 9:54
CodeGeassCodeGeass
2141314
2141314
And what does the API send in case oferror != null?
– vadian
Jan 3 at 9:59
@vadian it sends a string, u can see that in the ApiData structure.
– CodeGeass
Jan 3 at 10:03
@RobertDresler I'm not sure i understand the question? With the help of the struct ApiData that conforms to decodable protocol
– CodeGeass
Jan 3 at 10:04
@RobertDresler i've edited the post to answer your question.
– CodeGeass
Jan 3 at 10:08
Use power of generic
– SPatel
Jan 3 at 10:11
|
show 1 more comment
And what does the API send in case oferror != null?
– vadian
Jan 3 at 9:59
@vadian it sends a string, u can see that in the ApiData structure.
– CodeGeass
Jan 3 at 10:03
@RobertDresler I'm not sure i understand the question? With the help of the struct ApiData that conforms to decodable protocol
– CodeGeass
Jan 3 at 10:04
@RobertDresler i've edited the post to answer your question.
– CodeGeass
Jan 3 at 10:08
Use power of generic
– SPatel
Jan 3 at 10:11
And what does the API send in case of
error != null?– vadian
Jan 3 at 9:59
And what does the API send in case of
error != null?– vadian
Jan 3 at 9:59
@vadian it sends a string, u can see that in the ApiData structure.
– CodeGeass
Jan 3 at 10:03
@vadian it sends a string, u can see that in the ApiData structure.
– CodeGeass
Jan 3 at 10:03
@RobertDresler I'm not sure i understand the question? With the help of the struct ApiData that conforms to decodable protocol
– CodeGeass
Jan 3 at 10:04
@RobertDresler I'm not sure i understand the question? With the help of the struct ApiData that conforms to decodable protocol
– CodeGeass
Jan 3 at 10:04
@RobertDresler i've edited the post to answer your question.
– CodeGeass
Jan 3 at 10:08
@RobertDresler i've edited the post to answer your question.
– CodeGeass
Jan 3 at 10:08
Use power of generic
– SPatel
Jan 3 at 10:11
Use power of generic
– SPatel
Jan 3 at 10:11
|
show 1 more comment
4 Answers
4
active
oldest
votes
3
If data can be a single object or an array write a custom initializer which decodes first an array, if a type mismatch error occurs decode a single object. data is declared as an array anyway.
As token appears only in a single object the property is declared as optional.
struct ApiData: Decodable {
let data : [DataObject]
let error : String?
private enum CodingKeys : String, CodingKey { case data, error }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([DataObject].self, forKey: .data)
} catch DecodingError.typeMismatch {
data = [try container.decode(DataObject.self, forKey: .data)]
}
error = try container.decodeIfPresent(String.self, forKey: .error)
}
}
struct DataObject: Decodable {
let userId : Int
let token : String?
private enum CodingKeys: String, CodingKey { case userId = "id", token }
}
Edit: Your code to receive the data can be improved. You should add a better error handling to return also all possible errors:
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(ApiData?, Error?) -> Void) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
if let error = error { completion(nil, error); return }
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data!)
completion(retreived, nil)
} catch {
print("Decoder error: ", error)
completion(nil, error)
}
}.resume()
}
answered Jan 3 at 10:10
vadianvadian
156k17166192
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
add a comment |
1
Using power of generic, it simple like below:
struct ApiData<T: Decodable>: Decodable {
var data: T?
var error: String?
}
struct DataObject: Decodable {
private var id: Int?
var userId:Int? {
return id
}
}
Use
if let obj = try? NetworkManager.shared.decoder.decode(ApiData<DataObject>.self, from: data) {
//Do somthing
} else if let array = try NetworkManager.shared.decoder.decode(ApiData<[DataObject]>.self, from: data) {
// Do somthing
}
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
add a comment |
0
If you have only two possible outcomes for your data, an option would be to try and parse data to one of the expected types, if that fails you know that the data is of other type and you can then handle it accordingly.
See this
answered Jan 3 at 10:04
EdvinasEdvinas
12
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
add a comment |
0
You can try
struct Root: Codable {
let data: DataUnion
let error: String?
}
enum DataUnion: Codable {
case dataClass(DataClass)
case datumArray([Datum])
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let x = try? container.decode([Datum].self) {
self = .datumArray(x)
return
}
if let x = try? container.decode(DataClass.self) {
self = .dataClass(x)
return
}
throw DecodingError.typeMismatch(DataUnion.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for DataUnion"))
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
switch self {
case .dataClass(let x):
try container.encode(x)
case .datumArray(let x):
try container.encode(x)
}
}
}
struct Datum: Codable {
let id: Int
}
struct DataClass: Codable {
let id: Int
let token: String
}
let res = try? JSONDecoder().decode(Root.self, from:data)
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54019877%2fdecoding-dynamic-json-structure-in-swift-4%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
If data can be a single object or an array write a custom initializer which decodes first an array, if a type mismatch error occurs decode a single object. data is declared as an array anyway.
As token appears only in a single object the property is declared as optional.
struct ApiData: Decodable {
let data : [DataObject]
let error : String?
private enum CodingKeys : String, CodingKey { case data, error }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([DataObject].self, forKey: .data)
} catch DecodingError.typeMismatch {
data = [try container.decode(DataObject.self, forKey: .data)]
}
error = try container.decodeIfPresent(String.self, forKey: .error)
}
}
struct DataObject: Decodable {
let userId : Int
let token : String?
private enum CodingKeys: String, CodingKey { case userId = "id", token }
}
Edit: Your code to receive the data can be improved. You should add a better error handling to return also all possible errors:
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(ApiData?, Error?) -> Void) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
if let error = error { completion(nil, error); return }
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data!)
completion(retreived, nil)
} catch {
print("Decoder error: ", error)
completion(nil, error)
}
}.resume()
}
answered Jan 3 at 10:10
vadianvadian
156k17166192
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
add a comment |
3
If data can be a single object or an array write a custom initializer which decodes first an array, if a type mismatch error occurs decode a single object. data is declared as an array anyway.
As token appears only in a single object the property is declared as optional.
struct ApiData: Decodable {
let data : [DataObject]
let error : String?
private enum CodingKeys : String, CodingKey { case data, error }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([DataObject].self, forKey: .data)
} catch DecodingError.typeMismatch {
data = [try container.decode(DataObject.self, forKey: .data)]
}
error = try container.decodeIfPresent(String.self, forKey: .error)
}
}
struct DataObject: Decodable {
let userId : Int
let token : String?
private enum CodingKeys: String, CodingKey { case userId = "id", token }
}
Edit: Your code to receive the data can be improved. You should add a better error handling to return also all possible errors:
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(ApiData?, Error?) -> Void) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
if let error = error { completion(nil, error); return }
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data!)
completion(retreived, nil)
} catch {
print("Decoder error: ", error)
completion(nil, error)
}
}.resume()
}
answered Jan 3 at 10:10
vadianvadian
156k17166192
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
add a comment |
3
3
3
If data can be a single object or an array write a custom initializer which decodes first an array, if a type mismatch error occurs decode a single object. data is declared as an array anyway.
As token appears only in a single object the property is declared as optional.
struct ApiData: Decodable {
let data : [DataObject]
let error : String?
private enum CodingKeys : String, CodingKey { case data, error }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([DataObject].self, forKey: .data)
} catch DecodingError.typeMismatch {
data = [try container.decode(DataObject.self, forKey: .data)]
}
error = try container.decodeIfPresent(String.self, forKey: .error)
}
}
struct DataObject: Decodable {
let userId : Int
let token : String?
private enum CodingKeys: String, CodingKey { case userId = "id", token }
}
Edit: Your code to receive the data can be improved. You should add a better error handling to return also all possible errors:
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(ApiData?, Error?) -> Void) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
if let error = error { completion(nil, error); return }
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data!)
completion(retreived, nil)
} catch {
print("Decoder error: ", error)
completion(nil, error)
}
}.resume()
}
answered Jan 3 at 10:10
vadianvadian
156k17166192
If data can be a single object or an array write a custom initializer which decodes first an array, if a type mismatch error occurs decode a single object. data is declared as an array anyway.
As token appears only in a single object the property is declared as optional.
struct ApiData: Decodable {
let data : [DataObject]
let error : String?
private enum CodingKeys : String, CodingKey { case data, error }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([DataObject].self, forKey: .data)
} catch DecodingError.typeMismatch {
data = [try container.decode(DataObject.self, forKey: .data)]
}
error = try container.decodeIfPresent(String.self, forKey: .error)
}
}
struct DataObject: Decodable {
let userId : Int
let token : String?
private enum CodingKeys: String, CodingKey { case userId = "id", token }
}
Edit: Your code to receive the data can be improved. You should add a better error handling to return also all possible errors:
func makeDataTaskWith(with urlRequest: URLRequest, completion: @escaping(ApiData?, Error?) -> Void) {
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
session.dataTask(with: urlRequest) {
(data, response, error) in
if let error = error { completion(nil, error); return }
if let responseCode = response as? HTTPURLResponse {
print("Response has status code: (responseCode.statusCode)")
}
do {
let retreived = try NetworkManager.shared.decoder.decode(ApiData.self, from: data!)
completion(retreived, nil)
} catch {
print("Decoder error: ", error)
completion(nil, error)
}
}.resume()
}
answered Jan 3 at 10:10
vadianvadian
156k17166192
edited Jan 3 at 10:23
answered Jan 3 at 10:10
vadianvadian
156k17166192
answered Jan 3 at 10:10
vadianvadian
156k17166192
answered Jan 3 at 10:10
vadianvadian
156k17166192
156k17166192
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
add a comment |
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
This is what i was looking for, didn't know of DecodingError.typeMismatch. Thank you!
– CodeGeass
Jan 3 at 10:12
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
You always nailed answer when it comes to Codable 🙌🏻
– iVarun
Jan 3 at 10:23
add a comment |
1
Using power of generic, it simple like below:
struct ApiData<T: Decodable>: Decodable {
var data: T?
var error: String?
}
struct DataObject: Decodable {
private var id: Int?
var userId:Int? {
return id
}
}
Use
if let obj = try? NetworkManager.shared.decoder.decode(ApiData<DataObject>.self, from: data) {
//Do somthing
} else if let array = try NetworkManager.shared.decoder.decode(ApiData<[DataObject]>.self, from: data) {
// Do somthing
}
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
add a comment |
1
Using power of generic, it simple like below:
struct ApiData<T: Decodable>: Decodable {
var data: T?
var error: String?
}
struct DataObject: Decodable {
private var id: Int?
var userId:Int? {
return id
}
}
Use
if let obj = try? NetworkManager.shared.decoder.decode(ApiData<DataObject>.self, from: data) {
//Do somthing
} else if let array = try NetworkManager.shared.decoder.decode(ApiData<[DataObject]>.self, from: data) {
// Do somthing
}
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
add a comment |
1
1
1
Using power of generic, it simple like below:
struct ApiData<T: Decodable>: Decodable {
var data: T?
var error: String?
}
struct DataObject: Decodable {
private var id: Int?
var userId:Int? {
return id
}
}
Use
if let obj = try? NetworkManager.shared.decoder.decode(ApiData<DataObject>.self, from: data) {
//Do somthing
} else if let array = try NetworkManager.shared.decoder.decode(ApiData<[DataObject]>.self, from: data) {
// Do somthing
}
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
Using power of generic, it simple like below:
struct ApiData<T: Decodable>: Decodable {
var data: T?
var error: String?
}
struct DataObject: Decodable {
private var id: Int?
var userId:Int? {
return id
}
}
Use
if let obj = try? NetworkManager.shared.decoder.decode(ApiData<DataObject>.self, from: data) {
//Do somthing
} else if let array = try NetworkManager.shared.decoder.decode(ApiData<[DataObject]>.self, from: data) {
// Do somthing
}
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
edited Jan 3 at 11:47
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
answered Jan 3 at 10:27
SPatelSPatel
1,84121430
1,84121430
add a comment |
add a comment |
0
If you have only two possible outcomes for your data, an option would be to try and parse data to one of the expected types, if that fails you know that the data is of other type and you can then handle it accordingly.
See this
answered Jan 3 at 10:04
EdvinasEdvinas
12
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
add a comment |
0
If you have only two possible outcomes for your data, an option would be to try and parse data to one of the expected types, if that fails you know that the data is of other type and you can then handle it accordingly.
See this
answered Jan 3 at 10:04
EdvinasEdvinas
12
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
add a comment |
0
0
0
If you have only two possible outcomes for your data, an option would be to try and parse data to one of the expected types, if that fails you know that the data is of other type and you can then handle it accordingly.
See this
answered Jan 3 at 10:04
EdvinasEdvinas
12
If you have only two possible outcomes for your data, an option would be to try and parse data to one of the expected types, if that fails you know that the data is of other type and you can then handle it accordingly.
See this
answered Jan 3 at 10:04
EdvinasEdvinas
12
edited Jan 3 at 10:05
answered Jan 3 at 10:04
EdvinasEdvinas
12
answered Jan 3 at 10:04
EdvinasEdvinas
12
answered Jan 3 at 10:04
EdvinasEdvinas
12
12
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
add a comment |
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
Yes but that would duplicate code, both types would have var userId: Int? and a bunch of other user info that i've not pasted in the example above.
– CodeGeass
Jan 3 at 10:05
add a comment |
0
You can try
struct Root: Codable {
let data: DataUnion
let error: String?
}
enum DataUnion: Codable {
case dataClass(DataClass)
case datumArray([Datum])
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let x = try? container.decode([Datum].self) {
self = .datumArray(x)
return
}
if let x = try? container.decode(DataClass.self) {
self = .dataClass(x)
return
}
throw DecodingError.typeMismatch(DataUnion.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for DataUnion"))
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
switch self {
case .dataClass(let x):
try container.encode(x)
case .datumArray(let x):
try container.encode(x)
}
}
}
struct Datum: Codable {
let id: Int
}
struct DataClass: Codable {
let id: Int
let token: String
}
let res = try? JSONDecoder().decode(Root.self, from:data)
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
add a comment |
0
You can try
struct Root: Codable {
let data: DataUnion
let error: String?
}
enum DataUnion: Codable {
case dataClass(DataClass)
case datumArray([Datum])
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let x = try? container.decode([Datum].self) {
self = .datumArray(x)
return
}
if let x = try? container.decode(DataClass.self) {
self = .dataClass(x)
return
}
throw DecodingError.typeMismatch(DataUnion.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for DataUnion"))
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
switch self {
case .dataClass(let x):
try container.encode(x)
case .datumArray(let x):
try container.encode(x)
}
}
}
struct Datum: Codable {
let id: Int
}
struct DataClass: Codable {
let id: Int
let token: String
}
let res = try? JSONDecoder().decode(Root.self, from:data)
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
add a comment |
0
0
0
You can try
struct Root: Codable {
let data: DataUnion
let error: String?
}
enum DataUnion: Codable {
case dataClass(DataClass)
case datumArray([Datum])
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let x = try? container.decode([Datum].self) {
self = .datumArray(x)
return
}
if let x = try? container.decode(DataClass.self) {
self = .dataClass(x)
return
}
throw DecodingError.typeMismatch(DataUnion.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for DataUnion"))
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
switch self {
case .dataClass(let x):
try container.encode(x)
case .datumArray(let x):
try container.encode(x)
}
}
}
struct Datum: Codable {
let id: Int
}
struct DataClass: Codable {
let id: Int
let token: String
}
let res = try? JSONDecoder().decode(Root.self, from:data)
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
You can try
struct Root: Codable {
let data: DataUnion
let error: String?
}
enum DataUnion: Codable {
case dataClass(DataClass)
case datumArray([Datum])
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let x = try? container.decode([Datum].self) {
self = .datumArray(x)
return
}
if let x = try? container.decode(DataClass.self) {
self = .dataClass(x)
return
}
throw DecodingError.typeMismatch(DataUnion.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for DataUnion"))
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
switch self {
case .dataClass(let x):
try container.encode(x)
case .datumArray(let x):
try container.encode(x)
}
}
}
struct Datum: Codable {
let id: Int
}
struct DataClass: Codable {
let id: Int
let token: String
}
let res = try? JSONDecoder().decode(Root.self, from:data)
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
answered Jan 3 at 10:05
Sh_KhanSh_Khan
47.4k51433
47.4k51433
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
add a comment |
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
Thanks, but that doesn't avoid duplication. Both structs Datum and DataClass have let id.
– CodeGeass
Jan 3 at 10:10
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
you can make them 1 but should make token optional if you want
– Sh_Khan
Jan 3 at 10:11
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54019877%2fdecoding-dynamic-json-structure-in-swift-4%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
And what does the API send in case of
error != null?– vadian
Jan 3 at 9:59
@vadian it sends a string, u can see that in the ApiData structure.
– CodeGeass
Jan 3 at 10:03
@RobertDresler I'm not sure i understand the question? With the help of the struct ApiData that conforms to decodable protocol
– CodeGeass
Jan 3 at 10:04
@RobertDresler i've edited the post to answer your question.
– CodeGeass
Jan 3 at 10:08
Use power of generic
– SPatel
Jan 3 at 10:11