Mixing
Name of binary operation property to be equal to constant on equal arguments
0
$begingroup$
How can someone call property for some binary operation $fcolon Xtimes X to X$ that
$$
exists ain X: forall x in X quad f(x,x) = a
$$
?
Examples are
$f(x, y) = x-y$ and $a = 0$.
$f(x, y) = (x, y) in R$, where $R$ some reflexive relation and $a = True$ and so on.
definition binary-operations
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
$endgroup$
add a comment |
0
$begingroup$
How can someone call property for some binary operation $fcolon Xtimes X to X$ that
$$
exists ain X: forall x in X quad f(x,x) = a
$$
?
Examples are
$f(x, y) = x-y$ and $a = 0$.
$f(x, y) = (x, y) in R$, where $R$ some reflexive relation and $a = True$ and so on.
definition binary-operations
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
$endgroup$
add a comment |
0
0
0
$begingroup$
How can someone call property for some binary operation $fcolon Xtimes X to X$ that
$$
exists ain X: forall x in X quad f(x,x) = a
$$
?
Examples are
$f(x, y) = x-y$ and $a = 0$.
$f(x, y) = (x, y) in R$, where $R$ some reflexive relation and $a = True$ and so on.
definition binary-operations
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
$endgroup$
How can someone call property for some binary operation $fcolon Xtimes X to X$ that
$$
exists ain X: forall x in X quad f(x,x) = a
$$
?
Examples are
$f(x, y) = x-y$ and $a = 0$.
$f(x, y) = (x, y) in R$, where $R$ some reflexive relation and $a = True$ and so on.
definition binary-operations
definition binary-operations
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
asked Feb 1 at 14:17
Azat IbrakovAzat Ibrakov
1176
1176
add a comment |
add a comment |
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