Deserialization of JSON reponse keeps quotation marks in Strings












-1














I am querying a Google API using reqwest:



let request_url = format!(
"https://maps.googleapis.com/maps/api/place/findplacefromtext/json?input=*
&inputtype=textquery
&fields=formatted_address,name,place_id,types
&locationbias=circle:50@{},{}
&key=my-secret-key",
lat, lng
);

let mut response = reqwest::get(&request_url).expect("pffff");

let gr: GoogleResponse = response.json::<GoogleResponse>().expect("geeez");


The GoogleResponse struct is defined as



#[derive(Debug, Serialize, Deserialize)]
pub struct DebugLog {
pub line: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct Candidate {
pub formatted_address: String,
pub name: String,
pub place_id: String,
pub types: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct GoogleResponse {
pub candidates: Vec<Candidate>,
pub debug_log: DebugLog,
pub status: String,
}


This all compiles and I can make the request, however the result that I am having in the String fields contain the original ". Is it supposed to be this way?



For instance, when printing one of the formatted addresses I get:



"result": ""Street blabh blahab blahb"",


When I really wanted just



"result": "Street blabh blahab blahb",


Am I doing something wrong or is this expected behavior?










share|improve this question




















  • 2




    In the future, please provide a proper MCVE, where you descripe your problem in a minimal way and let us see some code please.
    – hellow
    Nov 19 '18 at 16:26
















-1














I am querying a Google API using reqwest:



let request_url = format!(
"https://maps.googleapis.com/maps/api/place/findplacefromtext/json?input=*
&inputtype=textquery
&fields=formatted_address,name,place_id,types
&locationbias=circle:50@{},{}
&key=my-secret-key",
lat, lng
);

let mut response = reqwest::get(&request_url).expect("pffff");

let gr: GoogleResponse = response.json::<GoogleResponse>().expect("geeez");


The GoogleResponse struct is defined as



#[derive(Debug, Serialize, Deserialize)]
pub struct DebugLog {
pub line: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct Candidate {
pub formatted_address: String,
pub name: String,
pub place_id: String,
pub types: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct GoogleResponse {
pub candidates: Vec<Candidate>,
pub debug_log: DebugLog,
pub status: String,
}


This all compiles and I can make the request, however the result that I am having in the String fields contain the original ". Is it supposed to be this way?



For instance, when printing one of the formatted addresses I get:



"result": ""Street blabh blahab blahb"",


When I really wanted just



"result": "Street blabh blahab blahb",


Am I doing something wrong or is this expected behavior?










share|improve this question




















  • 2




    In the future, please provide a proper MCVE, where you descripe your problem in a minimal way and let us see some code please.
    – hellow
    Nov 19 '18 at 16:26














-1












-1








-1







I am querying a Google API using reqwest:



let request_url = format!(
"https://maps.googleapis.com/maps/api/place/findplacefromtext/json?input=*
&inputtype=textquery
&fields=formatted_address,name,place_id,types
&locationbias=circle:50@{},{}
&key=my-secret-key",
lat, lng
);

let mut response = reqwest::get(&request_url).expect("pffff");

let gr: GoogleResponse = response.json::<GoogleResponse>().expect("geeez");


The GoogleResponse struct is defined as



#[derive(Debug, Serialize, Deserialize)]
pub struct DebugLog {
pub line: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct Candidate {
pub formatted_address: String,
pub name: String,
pub place_id: String,
pub types: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct GoogleResponse {
pub candidates: Vec<Candidate>,
pub debug_log: DebugLog,
pub status: String,
}


This all compiles and I can make the request, however the result that I am having in the String fields contain the original ". Is it supposed to be this way?



For instance, when printing one of the formatted addresses I get:



"result": ""Street blabh blahab blahb"",


When I really wanted just



"result": "Street blabh blahab blahb",


Am I doing something wrong or is this expected behavior?










share|improve this question















I am querying a Google API using reqwest:



let request_url = format!(
"https://maps.googleapis.com/maps/api/place/findplacefromtext/json?input=*
&inputtype=textquery
&fields=formatted_address,name,place_id,types
&locationbias=circle:50@{},{}
&key=my-secret-key",
lat, lng
);

let mut response = reqwest::get(&request_url).expect("pffff");

let gr: GoogleResponse = response.json::<GoogleResponse>().expect("geeez");


The GoogleResponse struct is defined as



#[derive(Debug, Serialize, Deserialize)]
pub struct DebugLog {
pub line: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct Candidate {
pub formatted_address: String,
pub name: String,
pub place_id: String,
pub types: Vec<String>,
}

#[derive(Debug, Serialize, Deserialize)]
pub struct GoogleResponse {
pub candidates: Vec<Candidate>,
pub debug_log: DebugLog,
pub status: String,
}


This all compiles and I can make the request, however the result that I am having in the String fields contain the original ". Is it supposed to be this way?



For instance, when printing one of the formatted addresses I get:



"result": ""Street blabh blahab blahb"",


When I really wanted just



"result": "Street blabh blahab blahb",


Am I doing something wrong or is this expected behavior?







json serialization rust serde rust-rocket






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 4 '18 at 21:27









Shepmaster

148k12285419




148k12285419










asked Nov 19 '18 at 16:20









LudeeD

317




317








  • 2




    In the future, please provide a proper MCVE, where you descripe your problem in a minimal way and let us see some code please.
    – hellow
    Nov 19 '18 at 16:26














  • 2




    In the future, please provide a proper MCVE, where you descripe your problem in a minimal way and let us see some code please.
    – hellow
    Nov 19 '18 at 16:26








2




2




In the future, please provide a proper MCVE, where you descripe your problem in a minimal way and let us see some code please.
– hellow
Nov 19 '18 at 16:26




In the future, please provide a proper MCVE, where you descripe your problem in a minimal way and let us see some code please.
– hellow
Nov 19 '18 at 16:26












1 Answer
1






active

oldest

votes


















1














I'll try to provide a simple example here.



extern crate serde; // 1.0.80
extern crate serde_json; // 1.0.33

use serde_json::Value;

const JSON: &str = r#"{
"name": "John Doe",
"age": 43
}"#;

fn main() {
let v: Value = serde_json::from_str(JSON).unwrap();
println!("{} is {} years old", v["name"], v["age"]);
}


(playground)



will lead to




"John Doe" is 43 years old




The reason is, that v["name"] is not a String, but a Value instead (You can check that by adding the line let a: () = v["name"]; which will result in the error: expected (), found enum 'serde_json::Value').



If you want a &str/String, you have to convert it first by using Value::as_str.



If you change the println! line accordingly:



println!("{} is {} years old", v["name"].as_str().unwrap(), v["age"]);


it will print out:




John Doe is 43 years old







share|improve this answer























  • Thanks, that really helped
    – LudeeD
    Nov 19 '18 at 16:40










  • This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
    – Shepmaster
    Nov 19 '18 at 17:35











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1 Answer
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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














I'll try to provide a simple example here.



extern crate serde; // 1.0.80
extern crate serde_json; // 1.0.33

use serde_json::Value;

const JSON: &str = r#"{
"name": "John Doe",
"age": 43
}"#;

fn main() {
let v: Value = serde_json::from_str(JSON).unwrap();
println!("{} is {} years old", v["name"], v["age"]);
}


(playground)



will lead to




"John Doe" is 43 years old




The reason is, that v["name"] is not a String, but a Value instead (You can check that by adding the line let a: () = v["name"]; which will result in the error: expected (), found enum 'serde_json::Value').



If you want a &str/String, you have to convert it first by using Value::as_str.



If you change the println! line accordingly:



println!("{} is {} years old", v["name"].as_str().unwrap(), v["age"]);


it will print out:




John Doe is 43 years old







share|improve this answer























  • Thanks, that really helped
    – LudeeD
    Nov 19 '18 at 16:40










  • This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
    – Shepmaster
    Nov 19 '18 at 17:35
















1














I'll try to provide a simple example here.



extern crate serde; // 1.0.80
extern crate serde_json; // 1.0.33

use serde_json::Value;

const JSON: &str = r#"{
"name": "John Doe",
"age": 43
}"#;

fn main() {
let v: Value = serde_json::from_str(JSON).unwrap();
println!("{} is {} years old", v["name"], v["age"]);
}


(playground)



will lead to




"John Doe" is 43 years old




The reason is, that v["name"] is not a String, but a Value instead (You can check that by adding the line let a: () = v["name"]; which will result in the error: expected (), found enum 'serde_json::Value').



If you want a &str/String, you have to convert it first by using Value::as_str.



If you change the println! line accordingly:



println!("{} is {} years old", v["name"].as_str().unwrap(), v["age"]);


it will print out:




John Doe is 43 years old







share|improve this answer























  • Thanks, that really helped
    – LudeeD
    Nov 19 '18 at 16:40










  • This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
    – Shepmaster
    Nov 19 '18 at 17:35














1












1








1






I'll try to provide a simple example here.



extern crate serde; // 1.0.80
extern crate serde_json; // 1.0.33

use serde_json::Value;

const JSON: &str = r#"{
"name": "John Doe",
"age": 43
}"#;

fn main() {
let v: Value = serde_json::from_str(JSON).unwrap();
println!("{} is {} years old", v["name"], v["age"]);
}


(playground)



will lead to




"John Doe" is 43 years old




The reason is, that v["name"] is not a String, but a Value instead (You can check that by adding the line let a: () = v["name"]; which will result in the error: expected (), found enum 'serde_json::Value').



If you want a &str/String, you have to convert it first by using Value::as_str.



If you change the println! line accordingly:



println!("{} is {} years old", v["name"].as_str().unwrap(), v["age"]);


it will print out:




John Doe is 43 years old







share|improve this answer














I'll try to provide a simple example here.



extern crate serde; // 1.0.80
extern crate serde_json; // 1.0.33

use serde_json::Value;

const JSON: &str = r#"{
"name": "John Doe",
"age": 43
}"#;

fn main() {
let v: Value = serde_json::from_str(JSON).unwrap();
println!("{} is {} years old", v["name"], v["age"]);
}


(playground)



will lead to




"John Doe" is 43 years old




The reason is, that v["name"] is not a String, but a Value instead (You can check that by adding the line let a: () = v["name"]; which will result in the error: expected (), found enum 'serde_json::Value').



If you want a &str/String, you have to convert it first by using Value::as_str.



If you change the println! line accordingly:



println!("{} is {} years old", v["name"].as_str().unwrap(), v["age"]);


it will print out:




John Doe is 43 years old








share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 '18 at 16:37

























answered Nov 19 '18 at 16:31









hellow

4,79532042




4,79532042












  • Thanks, that really helped
    – LudeeD
    Nov 19 '18 at 16:40










  • This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
    – Shepmaster
    Nov 19 '18 at 17:35


















  • Thanks, that really helped
    – LudeeD
    Nov 19 '18 at 16:40










  • This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
    – Shepmaster
    Nov 19 '18 at 17:35
















Thanks, that really helped
– LudeeD
Nov 19 '18 at 16:40




Thanks, that really helped
– LudeeD
Nov 19 '18 at 16:40












This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
– Shepmaster
Nov 19 '18 at 17:35




This answer makes no sense to me in relation to the original question — the OP never uses the indexing syntax. They specifically use typed deserialization.
– Shepmaster
Nov 19 '18 at 17:35


















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