How to remove first segment or segments from PATH in shell script





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I wanted to remove a CUDA directory from PATH by a .sh script when deactivate a conda virtual environment like described in this link.
The env variables are showed by echo $PATH.



/usr/local/cuda-9.0/bin:/home/dude/anaconda/envs/my_v_env/bin:/usr/sbin:/usr/bin:


So I create a .sh file in /home/dude/anaconda/envs/my_v_env/etc/conda/deactivate.d/.



My followed .sh script changes nothing but it DOES in terminal(this script will be automatically executed when I do conda deactivate):



export PATH=$(echo ${PATH} | sed -r 's|/usr/local/cuda-9.0/bin||')


I want only after deactivating the venv:



/usr/sbin:/usr/bin:


/home/dude/anaconda/envs/my_v_env/bin is deleted automatically but I still have the segment of /usr/local/cuda-9.0/bin: in the PATH










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    1















    I wanted to remove a CUDA directory from PATH by a .sh script when deactivate a conda virtual environment like described in this link.
    The env variables are showed by echo $PATH.



    /usr/local/cuda-9.0/bin:/home/dude/anaconda/envs/my_v_env/bin:/usr/sbin:/usr/bin:


    So I create a .sh file in /home/dude/anaconda/envs/my_v_env/etc/conda/deactivate.d/.



    My followed .sh script changes nothing but it DOES in terminal(this script will be automatically executed when I do conda deactivate):



    export PATH=$(echo ${PATH} | sed -r 's|/usr/local/cuda-9.0/bin||')


    I want only after deactivating the venv:



    /usr/sbin:/usr/bin:


    /home/dude/anaconda/envs/my_v_env/bin is deleted automatically but I still have the segment of /usr/local/cuda-9.0/bin: in the PATH










    share|improve this question



























      1












      1








      1








      I wanted to remove a CUDA directory from PATH by a .sh script when deactivate a conda virtual environment like described in this link.
      The env variables are showed by echo $PATH.



      /usr/local/cuda-9.0/bin:/home/dude/anaconda/envs/my_v_env/bin:/usr/sbin:/usr/bin:


      So I create a .sh file in /home/dude/anaconda/envs/my_v_env/etc/conda/deactivate.d/.



      My followed .sh script changes nothing but it DOES in terminal(this script will be automatically executed when I do conda deactivate):



      export PATH=$(echo ${PATH} | sed -r 's|/usr/local/cuda-9.0/bin||')


      I want only after deactivating the venv:



      /usr/sbin:/usr/bin:


      /home/dude/anaconda/envs/my_v_env/bin is deleted automatically but I still have the segment of /usr/local/cuda-9.0/bin: in the PATH










      share|improve this question
















      I wanted to remove a CUDA directory from PATH by a .sh script when deactivate a conda virtual environment like described in this link.
      The env variables are showed by echo $PATH.



      /usr/local/cuda-9.0/bin:/home/dude/anaconda/envs/my_v_env/bin:/usr/sbin:/usr/bin:


      So I create a .sh file in /home/dude/anaconda/envs/my_v_env/etc/conda/deactivate.d/.



      My followed .sh script changes nothing but it DOES in terminal(this script will be automatically executed when I do conda deactivate):



      export PATH=$(echo ${PATH} | sed -r 's|/usr/local/cuda-9.0/bin||')


      I want only after deactivating the venv:



      /usr/sbin:/usr/bin:


      /home/dude/anaconda/envs/my_v_env/bin is deleted automatically but I still have the segment of /usr/local/cuda-9.0/bin: in the PATH







      bash conda






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      edited Apr 10 at 6:39







      Zézouille

















      asked Jan 3 at 13:56









      ZézouilleZézouille

      4310




      4310
























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          So this removes the first two entries on the path using stream manipulation:



          num_entries_to_remove=2
          export PATH=`echo $PATH | sed 's/:/n/g' | tail -n+$(expr $num_entries_to_remove + 1) | tr 'n' ':'`





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            So this removes the first two entries on the path using stream manipulation:



            num_entries_to_remove=2
            export PATH=`echo $PATH | sed 's/:/n/g' | tail -n+$(expr $num_entries_to_remove + 1) | tr 'n' ':'`





            share|improve this answer






























              0














              So this removes the first two entries on the path using stream manipulation:



              num_entries_to_remove=2
              export PATH=`echo $PATH | sed 's/:/n/g' | tail -n+$(expr $num_entries_to_remove + 1) | tr 'n' ':'`





              share|improve this answer




























                0












                0








                0







                So this removes the first two entries on the path using stream manipulation:



                num_entries_to_remove=2
                export PATH=`echo $PATH | sed 's/:/n/g' | tail -n+$(expr $num_entries_to_remove + 1) | tr 'n' ':'`





                share|improve this answer















                So this removes the first two entries on the path using stream manipulation:



                num_entries_to_remove=2
                export PATH=`echo $PATH | sed 's/:/n/g' | tail -n+$(expr $num_entries_to_remove + 1) | tr 'n' ':'`






                share|improve this answer














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                edited Jan 7 at 16:09

























                answered Jan 6 at 2:46









                Aidan LovelaceAidan Lovelace

                29729




                29729
































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