Round datetime to the last 10 minutes JavaScript

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For my application is need the current datetime. But I need to round that to the nearest 10 min. I accomplished this with Math.round. The problem is that I need it to round to the LAST 10 min. Not up to the next. Because I won't have that data yet.

For example:

16:33 = 16:30 || 16:38 = 16:30 || 16:41 = 16:40

How can I do this?

const coeff = 1000 * 60 * 10;

const date = new Date();  //or use any other date

let roundDate = new Date(Math.round(date.getTime() / coeff) * coeff);

edited Jan 3 at 13:58

asked Jan 3 at 13:56

Trisha

356

I think you answered your own question, your code is working: stackoverflow.com/questions/10789384/…

– Armel
Jan 3 at 14:03

add a comment |

For example:

16:33 = 16:30 || 16:38 = 16:30 || 16:41 = 16:40

How can I do this?

const coeff = 1000 * 60 * 10;

const date = new Date();  //or use any other date

let roundDate = new Date(Math.round(date.getTime() / coeff) * coeff);

edited Jan 3 at 13:58

asked Jan 3 at 13:56

Trisha

356

I think you answered your own question, your code is working: stackoverflow.com/questions/10789384/…

– Armel
Jan 3 at 14:03

add a comment |

For example:

16:33 = 16:30 || 16:38 = 16:30 || 16:41 = 16:40

How can I do this?

const coeff = 1000 * 60 * 10;

const date = new Date();  //or use any other date

let roundDate = new Date(Math.round(date.getTime() / coeff) * coeff);

edited Jan 3 at 13:58

asked Jan 3 at 13:56

Trisha

356

For example:

16:33 = 16:30 || 16:38 = 16:30 || 16:41 = 16:40

How can I do this?

const coeff = 1000 * 60 * 10;

const date = new Date();  //or use any other date

let roundDate = new Date(Math.round(date.getTime() / coeff) * coeff);

javascript date time rounding

edited Jan 3 at 13:58

asked Jan 3 at 13:56

Trisha

356

edited Jan 3 at 13:58

asked Jan 3 at 13:56

Trisha

356

edited Jan 3 at 13:58

asked Jan 3 at 13:56

Trisha

356

asked Jan 3 at 13:56

Trisha

356

asked Jan 3 at 13:56

Trisha

356

I think you answered your own question, your code is working: stackoverflow.com/questions/10789384/…

– Armel
Jan 3 at 14:03

add a comment |

I think you answered your own question, your code is working: stackoverflow.com/questions/10789384/…

– Armel
Jan 3 at 14:03

I think you answered your own question, your code is working: stackoverflow.com/questions/10789384/…

– Armel
Jan 3 at 14:03

add a comment |

2 Answers
2

active

oldest

votes

Use Math.floor but divide the value by 10, then multiply by 10.

Example:

var x = 11;

console.log(Math.floor(x / 10) * 10);

Date Example:

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

answered Jan 3 at 14:02

basic

2,29211226

Thanks! This is what I needed :) I will mark it as the answer

– Trisha
Jan 3 at 14:05

No worrries @Trisha

– basic
Jan 3 at 14:05

add a comment |

You can use Math.floor():

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

answered Jan 3 at 14:05

Peter B

13.7k52046

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

Use Math.floor but divide the value by 10, then multiply by 10.

Example:

var x = 11;

console.log(Math.floor(x / 10) * 10);

Date Example:

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

answered Jan 3 at 14:02

basic

2,29211226

Thanks! This is what I needed :) I will mark it as the answer

– Trisha
Jan 3 at 14:05

No worrries @Trisha

– basic
Jan 3 at 14:05

add a comment |

Use Math.floor but divide the value by 10, then multiply by 10.

Example:

var x = 11;

console.log(Math.floor(x / 10) * 10);

Date Example:

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

answered Jan 3 at 14:02

basic

2,29211226

Thanks! This is what I needed :) I will mark it as the answer

– Trisha
Jan 3 at 14:05

No worrries @Trisha

– basic
Jan 3 at 14:05

add a comment |

Use Math.floor but divide the value by 10, then multiply by 10.

Example:

var x = 11;

console.log(Math.floor(x / 10) * 10);

Date Example:

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

answered Jan 3 at 14:02

basic

2,29211226

Use Math.floor but divide the value by 10, then multiply by 10.

Example:

var x = 11;

console.log(Math.floor(x / 10) * 10);

Date Example:

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

var x = 11;

console.log(Math.floor(x / 10) * 10);

var x = 11;

console.log(Math.floor(x / 10) * 10);

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

let date = new Date();

console.log(date);



let min = date.getMinutes();

date.setMinutes(Math.floor(min / 10) * 10);

console.log(date);

answered Jan 3 at 14:02

basic

2,29211226

answered Jan 3 at 14:02

basic

2,29211226

answered Jan 3 at 14:02

basic

2,29211226

answered Jan 3 at 14:02

basic

2,29211226

Thanks! This is what I needed :) I will mark it as the answer

– Trisha
Jan 3 at 14:05

No worrries @Trisha

– basic
Jan 3 at 14:05

add a comment |

Thanks! This is what I needed :) I will mark it as the answer

– Trisha
Jan 3 at 14:05

No worrries @Trisha

– basic
Jan 3 at 14:05

Thanks! This is what I needed :) I will mark it as the answer

– Trisha
Jan 3 at 14:05

No worrries @Trisha

– basic
Jan 3 at 14:05

add a comment |

You can use Math.floor():

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

answered Jan 3 at 14:05

Peter B

13.7k52046

add a comment |

You can use Math.floor():

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

answered Jan 3 at 14:05

Peter B

13.7k52046

add a comment |

You can use Math.floor():

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

answered Jan 3 at 14:05

Peter B

13.7k52046

You can use Math.floor():

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

const coeff = 1000 * 60 * 10;

const date = new Date("2019-01-03T13:18:05.641Z");



let floorDate = new Date(Math.floor(date.getTime() / coeff) * coeff);



console.log(date);

console.log(floorDate);

answered Jan 3 at 14:05

Peter B

13.7k52046

answered Jan 3 at 14:05

Peter B

13.7k52046

answered Jan 3 at 14:05

Peter B

13.7k52046

answered Jan 3 at 14:05

Peter B

13.7k52046

add a comment |

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