Mixing
Show CUBE PostgreSQL results with all possible dimensions
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1
I use the following query to get cube results for pivot table:
SELECT
client,
shop,
SUM (sales)
FROM
sales
GROUP BY
CUBE (client, shop)
ORDER BY
client,
shop;
And get an output:
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Please note that Client B sales only to Shop A.
But I need an output (added a last line) where output shows all possible intersections in dimensions (client, shop). How to change my query?
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Client B Shop B null
postgresql cube
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
add a comment |
1
I use the following query to get cube results for pivot table:
SELECT
client,
shop,
SUM (sales)
FROM
sales
GROUP BY
CUBE (client, shop)
ORDER BY
client,
shop;
And get an output:
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Please note that Client B sales only to Shop A.
But I need an output (added a last line) where output shows all possible intersections in dimensions (client, shop). How to change my query?
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Client B Shop B null
postgresql cube
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
add a comment |
1
1
1
I use the following query to get cube results for pivot table:
SELECT
client,
shop,
SUM (sales)
FROM
sales
GROUP BY
CUBE (client, shop)
ORDER BY
client,
shop;
And get an output:
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Please note that Client B sales only to Shop A.
But I need an output (added a last line) where output shows all possible intersections in dimensions (client, shop). How to change my query?
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Client B Shop B null
postgresql cube
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
I use the following query to get cube results for pivot table:
SELECT
client,
shop,
SUM (sales)
FROM
sales
GROUP BY
CUBE (client, shop)
ORDER BY
client,
shop;
And get an output:
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Please note that Client B sales only to Shop A.
But I need an output (added a last line) where output shows all possible intersections in dimensions (client, shop). How to change my query?
client shop sales
null null 1000
null Shop A 400
null Shop B 600
Client A null 800
Client A Shop A 200
Client A Shop B 600
Client B null 200
Client B Shop A 200
Client B Shop B null
postgresql cube
postgresql cube
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
edited Jan 3 at 13:17
Андрей Писарев
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
asked Jan 3 at 12:47
Андрей ПисаревАндрей Писарев
176
176
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
You need to query the cartesian product of client and shop left-joined with the table:
select
client,
shop,
sum(sales)
from (
select distinct client
from sales
) c
cross join (
select distinct shop
from sales
) s
left join
sales t using (client, shop)
group by
cube(client, shop)
order by
client, shop;
client | shop | sum
----------+--------+------
Client A | Shop A | 200
Client A | Shop B | 600
Client A | | 800
Client B | Shop A | 200
Client B | Shop B |
Client B | | 200
| Shop A | 400
| Shop B | 600
| | 1000
(9 rows)
answered Jan 3 at 13:31
klinklin
61k65991
And if your clients and shops are stored in other tables, you can use those rather than theSELECT DISTINCTandCROSS JOINs.
– Zack
Jan 3 at 14:31
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You need to query the cartesian product of client and shop left-joined with the table:
select
client,
shop,
sum(sales)
from (
select distinct client
from sales
) c
cross join (
select distinct shop
from sales
) s
left join
sales t using (client, shop)
group by
cube(client, shop)
order by
client, shop;
client | shop | sum
----------+--------+------
Client A | Shop A | 200
Client A | Shop B | 600
Client A | | 800
Client B | Shop A | 200
Client B | Shop B |
Client B | | 200
| Shop A | 400
| Shop B | 600
| | 1000
(9 rows)
answered Jan 3 at 13:31
klinklin
61k65991
And if your clients and shops are stored in other tables, you can use those rather than theSELECT DISTINCTandCROSS JOINs.
– Zack
Jan 3 at 14:31
add a comment |
2
You need to query the cartesian product of client and shop left-joined with the table:
select
client,
shop,
sum(sales)
from (
select distinct client
from sales
) c
cross join (
select distinct shop
from sales
) s
left join
sales t using (client, shop)
group by
cube(client, shop)
order by
client, shop;
client | shop | sum
----------+--------+------
Client A | Shop A | 200
Client A | Shop B | 600
Client A | | 800
Client B | Shop A | 200
Client B | Shop B |
Client B | | 200
| Shop A | 400
| Shop B | 600
| | 1000
(9 rows)
answered Jan 3 at 13:31
klinklin
61k65991
And if your clients and shops are stored in other tables, you can use those rather than theSELECT DISTINCTandCROSS JOINs.
– Zack
Jan 3 at 14:31
add a comment |
2
2
2
You need to query the cartesian product of client and shop left-joined with the table:
select
client,
shop,
sum(sales)
from (
select distinct client
from sales
) c
cross join (
select distinct shop
from sales
) s
left join
sales t using (client, shop)
group by
cube(client, shop)
order by
client, shop;
client | shop | sum
----------+--------+------
Client A | Shop A | 200
Client A | Shop B | 600
Client A | | 800
Client B | Shop A | 200
Client B | Shop B |
Client B | | 200
| Shop A | 400
| Shop B | 600
| | 1000
(9 rows)
answered Jan 3 at 13:31
klinklin
61k65991
You need to query the cartesian product of client and shop left-joined with the table:
select
client,
shop,
sum(sales)
from (
select distinct client
from sales
) c
cross join (
select distinct shop
from sales
) s
left join
sales t using (client, shop)
group by
cube(client, shop)
order by
client, shop;
client | shop | sum
----------+--------+------
Client A | Shop A | 200
Client A | Shop B | 600
Client A | | 800
Client B | Shop A | 200
Client B | Shop B |
Client B | | 200
| Shop A | 400
| Shop B | 600
| | 1000
(9 rows)
answered Jan 3 at 13:31
klinklin
61k65991
answered Jan 3 at 13:31
klinklin
61k65991
answered Jan 3 at 13:31
klinklin
61k65991
answered Jan 3 at 13:31
klinklin
61k65991
61k65991
And if your clients and shops are stored in other tables, you can use those rather than theSELECT DISTINCTandCROSS JOINs.
– Zack
Jan 3 at 14:31
add a comment |
And if your clients and shops are stored in other tables, you can use those rather than theSELECT DISTINCTandCROSS JOINs.
– Zack
Jan 3 at 14:31
And if your clients and shops are stored in other tables, you can use those rather than the
SELECT DISTINCT and CROSS JOINs.– Zack
Jan 3 at 14:31
And if your clients and shops are stored in other tables, you can use those rather than the
SELECT DISTINCT and CROSS JOINs.– Zack
Jan 3 at 14:31
add a comment |
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