$| sin x| > frac{sqrt{2-sqrt{2}}}{2}$ iff $1/8< { frac{x}{pi}} < 7/8$ where ${x}$ is the fractional...












0












$begingroup$


This is a problem that arose while reading the book "Putnam and Beyond":




Why is $| sin x| > frac{sqrt{2-sqrt{2}}}{2}$ iff $frac18 < { frac{x}{pi}} < frac78$ where ${x}$ is the fractional part of $x?$




This was used in proving the divergence of $sum frac{ |sin n|}{n}$, although the divergence is not in question here.










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$endgroup$












  • $begingroup$
    Just to clarify, you mean ${x}=x-lfloor xrfloor$, not ${x}=xleft(x-lfloor xrfloorright)$, right?
    $endgroup$
    – Carl Schildkraut
    Feb 2 at 6:31






  • 1




    $begingroup$
    $frac{sqrt{2-sqrt{2}}}2=sin frac{pi}8$
    $endgroup$
    – random
    Feb 4 at 1:14
















0












$begingroup$


This is a problem that arose while reading the book "Putnam and Beyond":




Why is $| sin x| > frac{sqrt{2-sqrt{2}}}{2}$ iff $frac18 < { frac{x}{pi}} < frac78$ where ${x}$ is the fractional part of $x?$




This was used in proving the divergence of $sum frac{ |sin n|}{n}$, although the divergence is not in question here.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just to clarify, you mean ${x}=x-lfloor xrfloor$, not ${x}=xleft(x-lfloor xrfloorright)$, right?
    $endgroup$
    – Carl Schildkraut
    Feb 2 at 6:31






  • 1




    $begingroup$
    $frac{sqrt{2-sqrt{2}}}2=sin frac{pi}8$
    $endgroup$
    – random
    Feb 4 at 1:14














0












0








0





$begingroup$


This is a problem that arose while reading the book "Putnam and Beyond":




Why is $| sin x| > frac{sqrt{2-sqrt{2}}}{2}$ iff $frac18 < { frac{x}{pi}} < frac78$ where ${x}$ is the fractional part of $x?$




This was used in proving the divergence of $sum frac{ |sin n|}{n}$, although the divergence is not in question here.










share|cite|improve this question











$endgroup$




This is a problem that arose while reading the book "Putnam and Beyond":




Why is $| sin x| > frac{sqrt{2-sqrt{2}}}{2}$ iff $frac18 < { frac{x}{pi}} < frac78$ where ${x}$ is the fractional part of $x?$




This was used in proving the divergence of $sum frac{ |sin n|}{n}$, although the divergence is not in question here.







trigonometry inequality problem-solving fractional-part






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 2 at 13:50









Michael Lugo

18.4k33576




18.4k33576










asked Jan 27 at 1:45









Cute BrownieCute Brownie

1,085417




1,085417












  • $begingroup$
    Just to clarify, you mean ${x}=x-lfloor xrfloor$, not ${x}=xleft(x-lfloor xrfloorright)$, right?
    $endgroup$
    – Carl Schildkraut
    Feb 2 at 6:31






  • 1




    $begingroup$
    $frac{sqrt{2-sqrt{2}}}2=sin frac{pi}8$
    $endgroup$
    – random
    Feb 4 at 1:14


















  • $begingroup$
    Just to clarify, you mean ${x}=x-lfloor xrfloor$, not ${x}=xleft(x-lfloor xrfloorright)$, right?
    $endgroup$
    – Carl Schildkraut
    Feb 2 at 6:31






  • 1




    $begingroup$
    $frac{sqrt{2-sqrt{2}}}2=sin frac{pi}8$
    $endgroup$
    – random
    Feb 4 at 1:14
















$begingroup$
Just to clarify, you mean ${x}=x-lfloor xrfloor$, not ${x}=xleft(x-lfloor xrfloorright)$, right?
$endgroup$
– Carl Schildkraut
Feb 2 at 6:31




$begingroup$
Just to clarify, you mean ${x}=x-lfloor xrfloor$, not ${x}=xleft(x-lfloor xrfloorright)$, right?
$endgroup$
– Carl Schildkraut
Feb 2 at 6:31




1




1




$begingroup$
$frac{sqrt{2-sqrt{2}}}2=sin frac{pi}8$
$endgroup$
– random
Feb 4 at 1:14




$begingroup$
$frac{sqrt{2-sqrt{2}}}2=sin frac{pi}8$
$endgroup$
– random
Feb 4 at 1:14










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